Biochemistry
6th Edition
ISBN: 9781305577206
Author: Reginald H. Garrett, Charles M. Grisham
Publisher: Cengage Learning
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Chapter 18, Problem 8P
Interpretation Introduction
To state:
Whether we can detect
Introduction:
Glycolysis is a series of
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If a reaction has a ΔG°′ value of at least −30.5 kJ · mol−1, suffi -cient to drive the synthesis of ATP (ΔG°′ = 30.5 kJ · mol−1), can it still drive the synthesis of ATP in vivo when its ΔG is only −10 kJ · mol−1? Explain.
Make an electron-flow-mechanism for this synthetic scheme. This involves predicting major and by-products using electronic and structural effects. The arrow push mechanism must be shown.(from the reaction of α-ketoacids and oxaprolines to proteins that contain native serine residues ) with label
What is the catalytic efficiency of Catalase ?
Table. The values of KM and kcat for some Enzymes and Substrates
Enzyme
Carbonic anhydrase
Substrate
CO2
HCO3
KM (M)
1.2 x 10-2
2.6 x 10-2
Kcat (s-1)
1.0 x 106
4.0 x 105
Catalase
H2O2
2.5 x 10-2
1.0 x 107
Urease
Urea
2.5 x 10-2
4.0 x 105
O A. 4 x 108 M-s-1
O B. 4 x 108 M-1.s-1
OC25x 10-9 M-s1
D. 2.5 x 102 M-1.s-1
OE 1.0 x 107 s1
Chapter 18 Solutions
Biochemistry
Ch. 18 - Characterizing Glycolysis List the reactions of...Ch. 18 - Radiotracer Labeling of Pyruvate from Glucose...Ch. 18 - Effects of Changing Metabolite Concentrations on...Ch. 18 - Prob. 4PCh. 18 - Prob. 5PCh. 18 - The Reactions and Meehanisms of the Leloir Pathway...Ch. 18 - The Effect of lodoacetic Acid on the...Ch. 18 - Prob. 8PCh. 18 - Comparing Glycolysis Entry Points for Sucrose...Ch. 18 - Prob. 10P
Ch. 18 - Prob. 11PCh. 18 - Prob. 12PCh. 18 - Prob. 13PCh. 18 - Energetic of Fructose-1 ,6-bis P Hydrolysis...Ch. 18 - Prob. 15PCh. 18 - Energetics of the Hexokinase Reaction The...Ch. 18 - Prob. 17PCh. 18 - Distinguishing the Mechanisms of Class I and Class...Ch. 18 - Prob. 19PCh. 18 - Understanding the Mechanism of Hemolytic Anemia...Ch. 18 - Prob. 21PCh. 18 - Based on your residing of this chapter, what would...Ch. 18 - Examine the ActiveModel for alcohol dehydrogenase...Ch. 18 - Based on your knowledge of the structure of NAD+...Ch. 18 - Using the ActiveModel for phosphofructokinase...
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- TABLE 3-LACTATE PRODUCTION IN FORTIFIED HEMOLYSATES OF HUMAN ERYTHROCYTES* Substrate Glucose Glucose Lactate production† No. of experiments pH 6 7.1 2.03 ± 0.91 6 7.8 4.76 ± 1.09 7-1 10-73 +1-88 5 7.8 12.34 ±2.92 5 7.0 7-15±0.73 5 7-7 (b)( ) In mature erythrocytes (red blood cells) the end product of glycolysis is lactate because of the absence of mitochondria. On the right is a table comparing the rate of lac- tate production in hemolysates (lysed cells) of human RBCs as a function of pH with dif- ferent substrates introduced into the glyco- lytic pathway. The hemolysate was fortified with 30 μmoles substrate, 7.5 μmoles MgCl2, 10 μmoles disodium phosphate, 1.5 μmoles NAD and 5 μmoles ATP in a volume of 5 mL. The rate of lactate production is given as μmoles of lactate/g Hb/hr at 37° C, buffered to either pH 7.1 or 7.8, as indicated. According to the results in the table which glycolytic enzyme is rate-limiting? Explain. Glucose-6-phosphate Glucose-6-phosphate Fructose-1,6-diphosphate…arrow_forward6-25 substrate-band enzyme concentrations. The the turnover number is equal to umax- b) V=Umax •57(Km+S) anstont For an enzyme that displays Michaelis-Menten kinetics, what is the reaction velocity, V (as a percentage of Vmax), observed at the following values? a) [S] = KM C) d) e) [S] = 0.5KM [S] = = 0.1KM [S] = 2KM [S] = 10KM w reactores -maximumrate of reaction boteles conc. Would you expect the structure of a competitive inhibitor of a given enzyme to be similar to that of its substrate?arrow_forwardENZYME KINETICS ANALYSIS of 6 Xanthine oxidase (XO) is the enzyme that catalyzes the synthesis of uric acid, which in excess causes gouty arthritis. The inhibition of this enzyme is therefore critical in its treatment. A student researcher is investigating the inhibitory effects of kaempferol (Kmp) and chlorogenic acid (Cha) on XO which uses xanthine (Xan) as substrate. Table 1 below shows the enzyme kinetic data. Construct the Lineweaver-Burk plot complete with the linear regression analvsis. Fill in the needed information on Table 2 and paste a copy of your Lineweaver-Burk plot. submit the picture of your output in PNG or JPG format. Table 1. Enzyme Kinetic Data Velocity, mM/s [S], mM Хan Kmp Cha 0.492 0.0678 0.0351 0.0615 0.211 0.0531 0.0261 0.0451 0.087 0.0298 0.0157 0.0211 0.048 0.0195 0.0091 0.0142 0.029 0.0127 0.0067 0.0081 Table 2. Enzyme Kinetic Parameters Xanthine Kaempferol Chlorogenic acid Parameters Vmax Км Type of Inhibition Mode of Binding NA NA Lineweaver-Burk Plotarrow_forward
- Glucosidase I catalyzes hydrolysis of specific glucosidase I is a synthetic trisaccharide, glucose-al-2- glucose-al-3-glucose-a-O(CH₂) #COOCH3. Kinetic measurements oligosaccharides containing glucose. obtained using this trisaccharide as substrate in the deoxynorjirimycin at concentrations of 50 μM (), 100 μM absence (x-x) and presence of the inhibitor 1- A) were used to prepare the (-), and 200 μM (4 Lineweaver-Burk plot below: b) Page 3 12) 7. a) V/V (nmol/hr)-1 1.S 1.0- 0.5 1/Trisaccharide (mM)-! Estimate the values for Vmax and KM for the trisaccharide substrate in the absence of the inhibitor. 0.0 -1.0 0.0 One substrate for 1.0 2.0 Determine whether inhibition by 1-deoxynorjirimycin is competitive, non-competitive or neither.arrow_forwardIn carbonic anhydrase II, mutation of the proton-shuttle residue His 64 to Ala was expected to result in a decrease in the maximal catalytic rate. However, in buffers such as imidazole with relatively small molecular components, no rate reduction was observed. In buffers with larger molecular components, significant rate reductions were observed. Propose an explanation.arrow_forwardSubstrate KM (M) N-Acetylvaline ethyl ether 8.8 X 10 -2 N-Acetyltyrosine ethyl ether 6.6 X 10-4 Which substrate has the higher apparent affinity for the enzyme? Explain. Which substrate is likely to give a higher value for Vmax?arrow_forward
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