Biology 2e
2nd Edition
ISBN: 9781947172517
Author: Matthew Douglas, Jung Choi, Mary Ann Clark
Publisher: OpenStax
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Textbook Question
Chapter 13, Problem 6RQ
Which recombination frequency corresponds to independent assortment and the absence of linkage?
- 0
- 0.25
- 0.50
- 0.75
Expert Solution & Answer
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What would justify the following ratio appearing after phenotyping the outcome of a crossing
trial: 8.9: 2.9: 3.2:1?
Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer.
a
b
C
d
Obviously this represents independent assortment based on crossing dihybrid
heterozygotes.
Obviously this represents gene linkage based on test crossing a dihybrid
heterozygote.
Obviously this represents the results of a trihybrid test cross.
Obviously this represents independent assortment based on crossing monohybrid
heterozygotes.
The recombination frequencies (RF) of genes A, B, C, and D are as follows:
Relationship
B-D
C-D
A-D
B-C
A-B
What is the order of the genes?
OBDAC
OCBAD
O CADB
O ADCB
RF
0.27
0.23
0.21
0.04
0.48
A 3-point test cross produces the following numbers of offspring:
The yellow cells are the recombinant
+ + a
348
offspring that result from a single cross-over
between A & G. What is the distance
g x +
363
between those two genes?
+ X +
88
O 18.8 mu
g + a
96
O 89.5 mu
g +
61
O cannot be determined from the information
given
+ X a
40
89.9 mu
g x a
1
O 18.4 mu
+ + +
3.
Chapter 13 Solutions
Biology 2e
Ch. 13 - Figure 13.3 In a test cross for two...Ch. 13 - Figure 13.4 Which of the following statements is...Ch. 13 - Figure 13.6 Which of the following statements...Ch. 13 - X-linked recessive traits in humans (or in...Ch. 13 - The first suggestion that chromosomes may...Ch. 13 - Which recombination frequency corresponds to...Ch. 13 - Which recombination frequency corresponds to...Ch. 13 - Which of the following codes describes position 12...Ch. 13 - In agriculture, polyploid crops (like coffee,...Ch. 13 - Assume a pericentric inversion occurred in one of...
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- Which recombination frequency corresponds to perfect linkage and violates the law of independent assortment? 0 0.25 0.50 0.75arrow_forwardBelow are the results from a 3 gene testcross between an XxYyZz plant and an xxyyzz plant: Testcross outcome: XYZ 365 xyz 367 xYz 110 XyZ 105 XYZ 3 Xyz 4 XYZ 25 xyZ 21 1. Determine the order of these genes on the chromosome. Indicate them on the diagram below. 2. Calculate the map distances between the genes (give you answer as map units). Indicate these distances on the diagram above. 3. Determine the coefficient of coincidence. 4. Determine the interference among these genes.arrow_forwardIf two genes are completely linked, the value of r = : 1.00 0.75 0.25 0.50arrow_forward
- In a diploid plant species, an F1 with the genotype Mm Rr Ss is test crossed to a pure breeding recessive plant with the genotype mm rr ss. The offspring genotypes are as follows: Genotype Number Mm Rr Ss 687 Mm Rr ss 5 Mm rr Ss 68 Mm rr ss 196 mm Rr Ss 185 mm Rr ss 72 mm rr Ss 8 mm rr ss 679 Total 1900 1. Calculate the recombination frequency between each pair of genesarrow_forwardIn a cross between mice the genotypes AB/ab x ab/ab, what is the recombination frequency if the progeny numbers are 72 AB/ab, 68 ab/ab, 17 Ab/ab, and 21 aB/ab? The alleles are shown for each chromosome, separated by a slash (/)arrow_forwardA cross is made between a heterozygote, +++/abc, and a recessive homozygote, abc/abc. Analysis of the progeny gave the following results: + + + 450 + + C 10 a + c 70 + b c 210 + b + 65 a + + 200 a bc 460 ab + 15 What is the map distance between the a and c genes? O 25.12 map units O 27.71 map units O 29.39 map units O 32.53 map units O None of the above Next» • Previous PgUp End F10 PrtScn Home 23 F2 DII F3 F4 F5 FB F9 F1 @ %23 %24 1. 3. 4. 8. To W R. Y U S D G H. C M Barrow_forward
- 5 & :56M ******* 24 DIHYBRID CROSSES DRV 0 Stv T alı A @ zladenA 9160p2-id2 bns obidalbaneoviene da II\ MOD YR 21 $59A ... Create a dihybrid cross and determine the expected phenotypic percentages of the offspring of two corn plants both of which are heterozygous for colour and texture (RrTt X RrTt). Don't forget to include clear let statements, and follow the all six steps taught on solving genetics problems. insig moni nellog: bna. zoomarrow_forward3.5 25 An individual of genotype AA Bb Cc DD Ee is test- crossed. Assuming that the loci undergo indepen- mETg dent assortment, what fraction of the progeny are expected to have the genotype Aa Bb Cc Dd Ee? oldizz0g S 16 J60 016 160arrow_forwardIn a diploid plant species, an F1 with the genotype Mm Rr Ss is test crossed to a pure breeding recessive plant with the genotype mm rr ss. The offspring genotypes are as follows: Genotype Number Mm Rr Ss 687 Mm Rr ss 5 Mm rr Ss 68 Mm rr ss 196 mm Rr Ss 185 mm Rr ss 72 mm rr Ss 8 mm rr ss 679 Total 1900 1. Why is the recombination frequency for the outside pair of genes not equal to the sum of the recombination between the adjacent gene pairs?arrow_forward
- In letter B: If the map distance equals the number of recombinant/total of offspring, wouldn't it be 24/806 x 100? Wouldn't we add both recombinants? Can you explain letter C? I don't grasp that concept well. And since I'm using my question already, would you be able to answer D. Thank you!arrow_forwardThe gel image above shows 7 alleles, let's call them 1-7 in order of size, with 1 being the largest and 7 being the smallest. What is the approximate size in Kbp of allele 4? Please type your answer as a number, please do not add units. ANSWER: The approximate size of allele 4 in the gel image below is Blank 1 Kbp Photograph of UV illuminated 1 % agarose TBE gel run for 40 minutes at 120 V, showing the result of PCR from a variable number tandem repeat region in 11 different individuals (A-K) 2000 1650 1000 850 600 500 Key: Lane 1: Lanes 2-12: A B C D E F G H I J K DNA ladder, see image for fragment sizes in base pairs (bp) PCR Products from the same variable number tandem repeat (VNTR) autosomal region of DNA from 11 different individuals (A-K)arrow_forwardTick all the essential steps to demonstrate a genetic linkage between a disease and a molecular marker in humans. identify the alleles of the genetic marker only for diseased individuals in the pedigree enumerate parental type individuals sequence the wild-type and mutant alleles to find the mutation no correct answer calculate a Lod score calculate the recombination frequency between the mutation and the molecular marker identify the alleles of the genetic marker for each individual in the pedigree pedigree analysis cloning the defective gene enumerate recombinant individualsarrow_forward
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