Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN: 9781337094740
Author: Segui, William T.
Publisher: Cengage Learning
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Chapter 9, Problem 9.7.3P
To determine
The flexural strength of the composite section.
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2. Determine if the composite beam pictured below is adequate for this application
(this includes bending, shear, deflection and shear stud limit states). The dead
load for this beam is 10 psf plus the weight of the deck, which is made from
normal weight concrete.
I
5"
5" Normal weight slab
fc=4000 psi
W24x94
Span length = 30'
Service Live Load = 100 psf
3/4" Diameter Shear Connectors
8' o.c. typical
Fu=60 ksi (shear connectors)
1. A two span beam subjected to shear and flexure only is reinforced as follows:
SECTION: TOP BARS
@ MIDSPAN: 2-⌀20mm
@ FACE OF SUPPORTS: 5-⌀20mm
SECTION: BOTTOM BARS
@ MIDSPAN: 3-⌀20 mm
@ FACE IF SUPPORTS: 2-⌀20 mm
Given:
Stirrup diameter, ds = 10 mm
Concrete f'c = 21 MPa
Steel rebar fy = 415 MPa
Stirrup fy = 275 MPa
Beam size b x h = 270 mm x 450 mm
Assume all bars laid out in single layer.
Calculate the following:
a. Design Moment strength of section at midspan for positive bending = ______ kN·m (nearest whole number)
A simply supported beam is reinforced with 5-p25 mm at the bottom and 2-020 mm at the top of the
beam. Concrete covering to centroid of reinforcement is 70 mm at the top and 64 mm at the bottom of
the beam. The beam has a gross depth of 450 mm and gross width of 300 mm. fc'= 28 MPa, fy = 415 MPa.
Assume bars laid out in single layer.
Calculate the following if the limiting tensile steel strain is 0.004 for a ductile failure:
Depth of the neutral axis from the extreme concrete compression fiber to the nearest whole number =
mm
Design strength of the beam section to the nearest whole number =
kN -m
Maximum service uniform live load over the entire span in addition to a DL = 20 kN/m (including the
weight of the beam) if it has a span of 6 m =
kN/m (to the nearest whole
number)
Chapter 9 Solutions
Steel Design (Activate Learning with these NEW titles from Engineering!)
Ch. 9 - Prob. 9.1.1PCh. 9 - Prob. 9.1.2PCh. 9 - Prob. 9.1.3PCh. 9 - Prob. 9.1.4PCh. 9 - Prob. 9.1.5PCh. 9 - Prob. 9.1.6PCh. 9 - A W1422 acts compositely with a 4-inch-thick floor...Ch. 9 - Prob. 9.2.2PCh. 9 - Prob. 9.3.1PCh. 9 - Prob. 9.3.2P
Ch. 9 - Prob. 9.4.1PCh. 9 - Prob. 9.4.2PCh. 9 - Prob. 9.4.3PCh. 9 - Prob. 9.4.4PCh. 9 - Prob. 9.4.5PCh. 9 - Prob. 9.5.1PCh. 9 - Prob. 9.5.2PCh. 9 - Prob. 9.5.3PCh. 9 - Note For Problems 9.6-1 through 9.6-5, use the...Ch. 9 - Note For Problems 9.6-1 through 9.6-5, use the...Ch. 9 - Note For Problems 9.6-1 through 9.6-5, use the...Ch. 9 - Note For Problems 9.6-1 through 9.6-5, use the...Ch. 9 - Note For Problems 9.6-1 through 9.6-5, use the...Ch. 9 - Prob. 9.7.1PCh. 9 - Prob. 9.7.2PCh. 9 - Prob. 9.7.3PCh. 9 - Prob. 9.7.4PCh. 9 - Prob. 9.8.1PCh. 9 - Prob. 9.8.2PCh. 9 - A beam must be designed to the following...Ch. 9 - Prob. 9.8.4PCh. 9 - Prob. 9.8.5PCh. 9 - Prob. 9.8.6PCh. 9 - Prob. 9.8.7PCh. 9 - Prob. 9.8.8PCh. 9 - Use the composite beam tables and select a W-shape...Ch. 9 - Prob. 9.8.10PCh. 9 - Prob. 9.10.1PCh. 9 - Prob. 9.10.2P
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