Concept explainers
(a)
Interpretation:
Moles of oxygen must be found out when 0.625 moles of KOH is produced from the reaction of KO2 and H2O.
Concept Introduction:
Four mole KO2 reacts with two moles of H2O to produce three moles of O2 and four moles of KOH.
(a)
Answer to Problem 10A
0.469 mole of O2 will be produced.
Explanation of Solution
From the balanced equation it is clear that when 4 moles of KOH is produced then 3 moles of O2 is produced.
So, when 1 mole of KOH is produced then
Thus, when 0.625 mole of KOH is produced then
b)
Interpretation:
Moles of selenium must be found out when 0.625 moles of H2O is produced from the reaction of SeO2 and H2Se.
Concept Introduction:
One mole SeO2 reacts with two moles of H2Se to produce three moles of Se and two moles of H2O.
b)
Answer to Problem 10A
0.938 mole of Se will be produced.
Explanation of Solution
From the balanced equation it is clear that when 2 mole of H2O is produced then 3 moles of Se is produced.
So, when 1 mole of H2O is produced then
Thus, when 0.625 mole of H2O is produced then
c)
Interpretation:
Moles of acetaldehyde must be found out when 0.625 moles of H2O is produced from the reaction of CH3CH2OH and O2.
Concept Introduction:
One mole CH3CH2OH reacts with 0.5 mole of O2 to produce one moles of CH3CHO and one mole of H2O.
c)
Answer to Problem 10A
0.625 mole of CH3CHO will be produced.
Explanation of Solution
From the balanced equation it is clear that when 1 mole of H2O is produced then 1 mole of CH3CHO is produced.
So, when 0.625 mole of H2O is produced then 0.625 moles of CH3CHO is produced.
d)
Interpretation:
Moles of iron must be found out when 0.625 moles of Al2O3 is produced from the reaction of Fe2O3 and Al.
Concept Introduction:
One mole Fe2O3 reacts with 2 moles of Al to produce one moles of Al2O3 and two moles of Fe.
d)
Answer to Problem 10A
1.25 mole of Fe will be produced.
Explanation of Solution
From the balanced equation it is clear that when 1 mole of Al2O3 is produced then 2 moles of Fe is produced.
So, when 0.625 mole of Al2O3 is produced then
Chapter 9 Solutions
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