Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
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Chapter 5, Problem 49P
(a)
To determine
The vehicle’s maximum acceleration.
(b)
To determine
To Calculate: The shortest possible time in which the car can achieve a speed of
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calculate the highest speed a car can reach over a 196.85 foot distance starting from a standstill. The weight of the automobile is not uniformly distributed ( 60% at the front, 40% at the back), and the static friction between the car and the road is 0.8. Consider (a) four-wheel drive , (b) front wheel drive (c) rear-wheel drive.
(a) If the coefficient of kinetic friction between tires and dry pavement is 0.80, what is the shortest distance in which you can stop a car by locking the brakes when the car is traveling at 28.7 m/s (about 65 mi/h)? (b) On wet pavement the coefficient of kinetic friction may be only 0.25. How fast should you drive on wet pavement to be able to stop in the same distance as in part (a)? (Note: Locking the brakes is not the safest way to stop.)
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FN on the car from the track if the car's speed is v- 9.49 m/s? (b) What is F if v- 16.7 m/s?
(a) Number i
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Chapter 5 Solutions
Physics for Scientists and Engineers
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- A frictionless plane is 10.0 m long and inclined at 35.0°.A sled starts at the bottom with an initial speed of 5.00 m/sup the incline. When the sled reaches the point at which itmomentarily stops, a second sled is released from the top ofthe incline with an initial speed vi. Both sleds reach the bottomof the incline at the same moment. (a) Determine the distance that the first sled traveled up the incline. (b) Determinethe initial speed of the second sled.arrow_forwardIf a car takes a banked curve at less than the ideal speed, friction is needed to keep it from sliding toward the inside of the curve (a real problem on icy mountain roads). (a) Calculate the ideal speed in (m/s) to take a 105 m radius curve banked at 15°. m/s (b) What is the minimum coefficient of friction needed for a frightened driver to take the same curve at 15.0 km/h?arrow_forwardIf a car takes a banked curve at less than a given speed, friction is needed to keep it from sliding toward the inside of the curve (a real problem on icy mountain roads). Part (a) Calculate the minimum speed, in meters per second, required to take a 88 m radius curve banked at 11° so that you don't slide inwards, assuming there is no friction. Part (b) What is the minimum coefficient of friction needed for a frightened driver to take the same curve at 18 km/h?arrow_forward
- A roller-coaster car has a mass of 1120 kg when fully loaded with passengers. As the car passes over the top of a circular hill of radius 21 m, its speed is not changing. (a) At the top of the hill, what is the normal force (using the negative sign for the downward direction) FN on the car from the track if the car's speed is v = 7.6 m/s? (b) What is EN if v = 19 m/s? Use g=9.81 m/s².arrow_forwardThe motorcyclist drives into a bend with a radius of 100 m at a speed of 72 km/h. By how many degrees does he have to lean in? At what maximum speed can he drive if the bend is icy and the coefficient of friction is 0.10? (The solutions are 22° and 36 km/h)arrow_forwardA skier is on a 25 degree slope and his mass is 80kg. If his constant velocity and the coefficient of kinetic friction between the ski and the snow is 9 m/s and 0.80, respectively, compute his velocity when he has skid 20m from his initial position and a drag force experienced by the skier equivalent to a magnitude of 0.6V^2.arrow_forward
- A bicyclist starting from rest applies a force of F = 396 N to ride his bicycle across flat ground for a distance of d = 295 m before encountering a hill making an angle of theta = 29 degrees with respect to the horizontalThe bicycle and rider have a mass of m = 105 kg combined. In this problem, you can ignore air resistance and other losses due to friction What is the bicycle speed, v in m/s just before the hill ? If the cyclist start coasting at the bottom of the hill what distance , di in meters does the bike travel up in the inclinearrow_forwardA skier is on a 25° slope and his mass is 80kg. If his constant velocity and the coefficient of kinetic friction between the ski and the snow is 9 m/s and 0.80, respectively, compute his velocity when he has skid 20m from his initial position and a drag force experienced by the skier equivalent to a magnitude of 0.6V^2.arrow_forwardA track is built so that going around a curve (R = 65.0 m), the banking of the track will allow the automobile to safely travel the curve when there is no friction at a speed of 22.0 m/s. (a) What is the angle of the banking for the curve? (b) What coefficient of friction is required for the vehicle to travel the same curve with a speed of 34.0 m/s?arrow_forward
- Problem 5: A car negotiates an unbanked 85.2 m radius curve at 19.9 m/s. Calculate the minimum coeficient of friction needed to negotiate the curve. Hg = || sin() cotan() atan() cosh() cos() asin() acotan() tanh() O Degrees tan() ♫ acos() E sinh() cotanh() Radians 7 ^^^ 4 1 1 + 0 VO BACKSPACE * ∞02 - 8 9 5 63 DEL HOME END CLEARarrow_forwardA basketball player jumps straight up for a ball. To do this, he lowers his body 0.270 m and then accelerates through this distance by forcefully straightening his legs. This player leaves the floor with a vertical velocity sufficient to carry him 0.940 m above the floor.arrow_forwardEngineering a highway curve. If a car goes through a curve too fast, the car tends to slide out of the curve. For a banked curve with friction, a frictional force acts on a fast car to oppose the tendency to slide out of the curve; the force is directed down the bank (in the direction water would drain). Consider a circular curve of radius R = 180 m and bank angle 8, where the coefficient of static friction between tires and pavement is µs. A car (without negative lift) is driven around the curve as shown in Figure (a). Find an expression for the car speed Vmax that puts the car on the verge of sliding out, in terms of R, 0, and us. Evaluate Vmax for a bank angle of = 10° and for (a) μ = 0.51 (dry pavement) and (b) µs = 0.050 (wet or icy pavement). (Now you can see why accidents occur in highway curves when icy conditions are not obvious to drivers, who tend to drive at normal speeds.) (a) Number i 36.5 (a) Units R m/s^2 EN FN 8 FNr Cararrow_forward
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