(a)
The acceleration of center of mass of two block cylinder string system.
(a)
Explanation of Solution
Given:
The mass of cylinder is
Formula used:
Write expression for total force on the system.
Substitute
Substitute
Calculation:
Draw free body diagram of blocks of Atwood’s machine.
Write expression for net force in block of mass
Substitute
Write expression for net force in block of mass
Substitute
Rearrange above expression for
Substitute
Substitute
Substitute
Conclusion:
Thus, the acceleration of COM is
(b)
The force exerted by the support.
(b)
Explanation of Solution
Given:
The mass of cylinder is
Formula used:
Write expression for total force on the system.
Substitute
Substitute
Write expression for force exerted by the support.
Calculation:
Draw free body diagram of blocks of Atwood’s machine.
Write expression for net force in block of mass
Substitute
Write expression for net force in block of mass
Substitute
Rearrange above expression for
Substitute
Substitute
Substitute
Substitute
Substitute
Conclusion:
Thus, force exerted by the support is
(c)
Tension
(c)
Explanation of Solution
Given:
Formula used:
Write expression for total force on the system.
Substitute
Substitute
Write expression for force exerted by the support.
Draw free body diagram of blocks of Atwood’s machine.
Write expression for net force in block of mass
Substitute
Write expression for net force in block of mass
Substitute
Rearrange above expression for
Substitute
Substitute
Substitute
Calculation:
Substitute
Substitute
Substitute
Substitute
Conclusion:
Thus, the tension in the string is
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Chapter 5 Solutions
Physics for Scientists and Engineers
- Problem The coefficient of friction between blocks is us = 0.4, at what angle will the block start sliding if it is initially at rest? Solution Let us obtain the net force in the axis perpendicular to the inclined plane. By virtue of the first law of motion (equilibrium), the net force is 2 F perpendicular =n- Fgperpendicular Thus, the normal force is n= m cos On the axis parallel to the inclined, the net force is Z FI - Fg||-fs,max= Substituting the forces, we get the following: mg smg By simplifying, we get the following: tan(theta) = mus Thus, the angle that the object will slide is: (rounded of to the ones)arrow_forwardFour people are attempting to move a stage platform across the floor. If they exert the horizontal forces shown, determine (a) the equivalent force-couple system at O and (b) the points on the x- and y-axes through which the line of action of the single resultant force R passes. 72 lb 69 lb 61" 75 lb- 74" 34 lb Answers: (a) The force-couple system at O: R= 1) Ib k Ib-in. (b) The line of action of the single resultant R On the x-axis x = Jin. On the y-axis y =arrow_forward•G h A UBC genng Given: The horizontal force F=450 is applied at a height y 0.6 m from the bottom of the cart The cart's total mass of m 350 kg with a center of mass at G. The ground. d_A = 0.91 m and d_B = 0.78 m. Find: of gravity G is located at a height h = 1.5 m from the al Acceleration of the cart b/ Normal forces at A and B. Assume the wheels have negligible mass and no rolling resistance CamScannerarrow_forward
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- University Physics Volume 1PhysicsISBN:9781938168277Author:William Moebs, Samuel J. Ling, Jeff SannyPublisher:OpenStax - Rice University