Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 2, Problem 95P
To determine
To find: The minimum constant speed to catch the train.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
sketch a position vs time graph and a velocity vs time graph and an acceleration vs time graph.
At time t = 0 you are walking in the positive x direction with a constant speed of 1 m/s. You maintain that speed for 6 s. Then, you decrease your speed uniformly to 0 over a 2 s interval. You rest for 2 s, then turn around and increase your speed uniformly to 2 m/s in 2 s. You continue at that speed until you return to the starting place.
Hi, I am doing problem number 2 from the end of the chapter questions in my textbook. The problem reads as such:
"An 18-year-old runner can complete a 10.0-km course with an average speed of 4.39 m/s. A 50-year-old runner can cover the same distance with an average speed of 4.27 m/s. How much later (in seconds) should the younger runner start in order to finish the course at the same time as the older runner?"
I am looking at the solution for the problem and I did everything right except the last step. The solution says to subtract the time found for the 18 year old to run 10km from the time found for the 50 year old to run 10km. However, I divided the anwers I found. Why are we subtracting the answers from one another and not dividing them? Thank you!
Sarah is driving on a freeway in a forest at 13.0m/s when suddenly a deer runs in front of her and stands still out of fright. The deer is 20.0m in front of Sarah when she steps on the brakes with a deceleration of magnitude 4.59 m/s2A) Find the stopping distance of Sarah. Does she hit the deer? Give support to your explanation.B) How long (how much time) does it take Sarah to travel half of the stopping distance in part (a)?
Chapter 2 Solutions
Physics for Scientists and Engineers
Ch. 2 - Prob. 1PCh. 2 - Prob. 2PCh. 2 - Prob. 3PCh. 2 - Prob. 4PCh. 2 - Prob. 5PCh. 2 - Prob. 6PCh. 2 - Prob. 7PCh. 2 - Prob. 8PCh. 2 - Prob. 9PCh. 2 - Prob. 10P
Ch. 2 - Prob. 11PCh. 2 - Prob. 12PCh. 2 - Prob. 13PCh. 2 - Prob. 14PCh. 2 - Prob. 15PCh. 2 - Prob. 16PCh. 2 - Prob. 17PCh. 2 - Prob. 18PCh. 2 - Prob. 19PCh. 2 - Prob. 20PCh. 2 - Prob. 21PCh. 2 - Prob. 22PCh. 2 - Prob. 23PCh. 2 - Prob. 24PCh. 2 - Prob. 25PCh. 2 - Prob. 26PCh. 2 - Prob. 27PCh. 2 - Prob. 28PCh. 2 - Prob. 29PCh. 2 - Prob. 30PCh. 2 - Prob. 31PCh. 2 - Prob. 32PCh. 2 - Prob. 33PCh. 2 - Prob. 34PCh. 2 - Prob. 35PCh. 2 - Prob. 36PCh. 2 - Prob. 37PCh. 2 - Prob. 38PCh. 2 - Prob. 39PCh. 2 - Prob. 40PCh. 2 - Prob. 41PCh. 2 - Prob. 42PCh. 2 - Prob. 43PCh. 2 - Prob. 44PCh. 2 - Prob. 45PCh. 2 - Prob. 46PCh. 2 - Prob. 47PCh. 2 - Prob. 48PCh. 2 - Prob. 49PCh. 2 - Prob. 50PCh. 2 - Prob. 51PCh. 2 - Prob. 52PCh. 2 - Prob. 53PCh. 2 - Prob. 54PCh. 2 - Prob. 55PCh. 2 - Prob. 56PCh. 2 - Prob. 57PCh. 2 - Prob. 58PCh. 2 - Prob. 59PCh. 2 - Prob. 60PCh. 2 - Prob. 61PCh. 2 - Prob. 62PCh. 2 - Prob. 63PCh. 2 - Prob. 64PCh. 2 - Prob. 65PCh. 2 - Prob. 66PCh. 2 - Prob. 67PCh. 2 - Prob. 68PCh. 2 - Prob. 69PCh. 2 - Prob. 70PCh. 2 - Prob. 71PCh. 2 - Prob. 72PCh. 2 - Prob. 73PCh. 2 - Prob. 74PCh. 2 - Prob. 75PCh. 2 - Prob. 76PCh. 2 - Prob. 77PCh. 2 - Prob. 78PCh. 2 - Prob. 79PCh. 2 - Prob. 80PCh. 2 - Prob. 81PCh. 2 - Prob. 82PCh. 2 - Prob. 83PCh. 2 - Prob. 84PCh. 2 - Prob. 85PCh. 2 - Prob. 86PCh. 2 - Prob. 87PCh. 2 - Prob. 88PCh. 2 - Prob. 89PCh. 2 - Prob. 90PCh. 2 - Prob. 91PCh. 2 - Prob. 92PCh. 2 - Prob. 93PCh. 2 - Prob. 94PCh. 2 - Prob. 95PCh. 2 - Prob. 96PCh. 2 - Prob. 97PCh. 2 - Prob. 98PCh. 2 - Prob. 99PCh. 2 - Prob. 100PCh. 2 - Prob. 101PCh. 2 - Prob. 102PCh. 2 - Prob. 103PCh. 2 - Prob. 104PCh. 2 - Prob. 105PCh. 2 - Prob. 106PCh. 2 - Prob. 107PCh. 2 - Prob. 108PCh. 2 - Prob. 109PCh. 2 - Prob. 110PCh. 2 - Prob. 111PCh. 2 - Prob. 112PCh. 2 - Prob. 113PCh. 2 - Prob. 114PCh. 2 - Prob. 115PCh. 2 - Prob. 116PCh. 2 - Prob. 117PCh. 2 - Prob. 118PCh. 2 - Prob. 119PCh. 2 - Prob. 120PCh. 2 - Prob. 121PCh. 2 - Prob. 122P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Marie-Philip Poulin begins from rest at one end of a 65 m long ice rink. She skates in a straight horizontal line and reaches the other end after 6.14s. She begins by accelerating with constant acceleration for 2.09 s before reaching top speed. She then continues at her top speed until she reaches the end of the rink. What is her speed when she reaches the end of the ice rink?arrow_forwardSketch a position vs time graph, a velocity vs time graph, and an acceleration vs time graph for the situation described below. At time t = 0 you are walking in the positive x direction with a constant speed of 1 m/s. You maintain that speed for 6 s. Then, you decrease your speed uniformly to 0 over a 2 s interval. You rest for 2 s, then turn around and increase your speed uniformly to 2 m/s in 4 s. You continue at that speed until you return to the starting place.arrow_forwardA car is moving along a straight line defined to be the positive x direction. It's velocity is measured and found to be a function of time given by v_x(t)=at^2 where a is a known constant. The car was at the point x=A at the time t=2s. Find the cars position as a function of timr. How fast would the car be going just before it hits a wall located at x=L?arrow_forward
- An astronaut has left an orbiting space shuttle to test a new personal maneuvering unit. As she moves along a straight line, her partner on board the shuttle measures her velocity every 2.0s starting at 2. time t=1.0s as follows: t 1.0s 0.8m/s 1.2m/s 1.8m/s 3.0s 5.0s Find the average acceleration for each time interval: a) 1s to 3s and b) 3s to 5sarrow_forwardA subway train has to travel a distance of 1800 m until it stops at the next station. The train starts from rest and accelerates at a rate of 1.60 m/s2 for 15.0 s. It then runs at a constant speed for some time and finally slows down at a rate of 4.0m/s2 until it stops at the next station. How long did it take to reach the next station?arrow_forwardA race driver has made a pit stop to refuel. After refueling, he starts from rest and leaves the pit area with an acceleration whose magnitude is 5.8 m/s2 ; after 3.6 s, he enters the main speedway. At the same instant, another car on the speedway and traveling at a constant velocity of 67.4 m/s overtakes and passes the entering car. The entering car maintains its acceleration. How much time is required for the entering car to catch up with the other car?arrow_forward
- A car traveling at a constant speed of 34.5 m/s passes a trooper hidden behind a billboard. One second after the speeding car passes the billboard, the trooper sets off in chase with a constant acceleration of 2.50 m/s2. How long does it take the trooper to overtake the speeding car? Solve this problem by a graphical method. On the same graph, plot position versus time for the car and the trooper. From the intersection of the two curves, read the time at which the trooper overtakes the car. sarrow_forwardSally is driving along a straight highway in her 1965 Mustang. At t=0, when she is moving at 10m/s in the positive x direction, she passes a signpost at x = 50m. Her acceleration as a function of time is a = 2.0 m/s^2 - 0.10t (m/s^2) a) Deduce the expression for its velocity and position as a function of time. b) At what time is the velocity maximum? c) What is the speed? d) Where is the car when it reaches that speed?arrow_forwardA pedestrian is running at his maximum speed of 6.0 m/s to catch a bus stopped at a traffic light. When he is 15 m from the bus, the light changes and the bus accelerates uniformly at 1.00 m/s2. Does he make it to the bus? If so, how far does he have to run in order to catch it? If not, how close does he get? Use sketches on velocity vs time and acceleration vs time graphs to make your case.arrow_forward
- An electric vehicle starts from rest and accelerates at a rate of 3.0 m/s2 in a straight line until it reaches a speed of 21 m/s. The vehicle then slows at a constant rate of 1.0 m/s2 until it stops. How far does the vehicle travel from start to stop?arrow_forwardA lion is napping in the shade as a zebra saunters by at steady 48.2 km/h. Feeling the desire for dinner the lion accelerates at 4.43m/s2 for 5.50 seconds. How far does the lion travel during this 5.50 second period of acceleration? How far does the zebra travel during the same time interval? Graph the acceleration vs. time of the lion and the zebra for the entire scenario. Label the axis and any major points.arrow_forwardA student drives a moped along a straight road as described by the velocity–time graph in Figure P2.58. Sketch this graph in the middle of a sheet of graph paper. (a) Directly above your graph, sketch a graph of the position versus time, aligning the time coordinates of the two graphs. (b) Sketch a graph of the acceleration versus time directly below the velocity–time graph, again aligning the time coordinates. On each graph, show the numerical values of x and ax for all points of inflection. (c) What is the acceleration at t = 6.00 s? (d) Find the position (relative to the starting point) at t = 6.00 s. (e) What is the moped’s final position at t = 9.00 s?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Position/Velocity/Acceleration Part 1: Definitions; Author: Professor Dave explains;https://www.youtube.com/watch?v=4dCrkp8qgLU;License: Standard YouTube License, CC-BY