Explanation Given: One third of total height is covered by rock in last second of its fall. Formula used: Take the downward direction as positive and height of cliff is h . Write the expression of displacement covered in last nth sec in terms of acceleration due to gravity, initial speed and time. s n = v 0 + g 2 ( 2 t − 1 ) . ........(1) Here, s n is displacement, v 0 is initial velocity, t is time taken and is g acceleration due to gravity Write the expression for time taken by rock to fall to ground in terms of height and acceleration due to gravity. t = 2 h g ........(2) Calculation: Calculate for displacement during first two third of fall. Substitute h 3 for s n , 0 for v 0 , 2 h g for t and 9.8 m/s 2 for g in equation (1) h 3 = 0 + 9.8 2 ( 2 ( 2 h 9

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ISBN: 9781429281843

Author: Tipler

Publisher: MAC HIGHER

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Chapter 2, Problem 82P

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Total height of the cliff

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Chapter 2, Problem 81P

Chapter 2, Problem 83P

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