Electric machinery fundamentals
5th Edition
ISBN: 9780073529547
Author: Chapman, Stephen J.
Publisher: MCGRAW-HILL HIGHER EDUCATION
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Chapter 1, Problem 1.4P
A motor is supplying
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Chapter 1 Solutions
Electric machinery fundamentals
Ch. 1 - What is torque? What role does torque play in the...Ch. 1 - What is Amperes law?Ch. 1 - What is magnetizing intensity? What is magnetic...Ch. 1 - How does the magnetic circuit concept aid in the...Ch. 1 - What is reluctance?Ch. 1 - What is a ferromagnetic material? Why is the...Ch. 1 - How does the relative permeability of a...Ch. 1 - Prob. 1.8QCh. 1 - What are eddy current losses? What can be done to...Ch. 1 - Why are all cores exposed to ac flux variations...
Ch. 1 - What is Faraday law?Ch. 1 - What conditions are necessary for a magnetic field...Ch. 1 - What conditions are necessary for a magnetic field...Ch. 1 - Prob. 1.14QCh. 1 - The linear machine in Figure 1-19 is running at...Ch. 1 - Just how does a decrease in flux produce an...Ch. 1 - Will current be leading or lagging voltage in an...Ch. 1 - What are real, reactive, and apparent power? What...Ch. 1 - What is power factor?Ch. 1 - Prob. 1.1PCh. 1 - A flywheel with a moment of inertia of 4kgm2 is...Ch. 1 - A force of 10 N is applied to a cylinder of radius...Ch. 1 - A motor is supplying 50Nm of torque to its load....Ch. 1 - A ferromagnetic core is shown in Figure P1-2. The...Ch. 1 - A ferromagnetic core with a relative permeability...Ch. 1 - A two-legged core is shown in Figure P1-4. The...Ch. 1 - A core with three legs is shown in Figure P1-5....Ch. 1 - A two-legged core is shown in Figure P1-4. The...Ch. 1 - A wire is shown in Figure P1-7 that is moving in...Ch. 1 - Repeat Problem 1-10 for the wire in Figure P1-8.Ch. 1 - Prob. 1.12PCh. 1 - A core with three legs is shown in Figure P1-10....Ch. 1 - A two-legged magnetic core with an air gap is...Ch. 1 - A transformer core with an effective mean path...Ch. 1 - The core shown in Figure P1-2 has the flux shown...Ch. 1 - Prob. 1.17PCh. 1 - Prob. 1.18PCh. 1 - Prob. 1.19PCh. 1 - Demonstrate that Equation (1-59) can be derived...Ch. 1 - Prob. 1.21PCh. 1 - Prob. 1.22PCh. 1 - For the linear machine of Problem 1-22: When this...
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- A DC motor armature draws 150 A while generating a magnetic flux of 0.02 Wb. The armature constant is K = 1 V min/Wb. What is most nearly the motor's developed torque? 28.65 n-m 50.3 n-m O 4,73 n-m O 11.70 n-marrow_forwardQUESTION 6 A DC motor armature draws 150 A while generating a magnetic flux of 0.02 Wb. The armature constant is K = 1 V min/Wb. What is most nearly the motor's developed torque? 28.65 n-m 50.3 n-m 4,73 n-m O 11.70 n-marrow_forwardA series motor develops 164 lb-ft torque when the current is 94A. If the load increases the current 50% with the flux increase of 20%, what is the torque at the second value of current?arrow_forward
- A 255 V, DC lathe machine, (not a 2 pole machine) has armature resistance and series resistance are 0.150 and 1702 respectively. The motor has 25mWb flux per pole. The ratio of pole to parallel paths is unity. The product of this ratio and number of turns in armature section is 1000. When it runs light, it has a speed of 1200 rpm. If it runs at maximum load, it takes a current of 70A. (1) Which machine is this one, shunt or series ? Is machine lap wound or wave wound? (3) Calculate the no load back EMF. (4) Calculate the no load armature current. (5) Calculate the no load shunt current. (6) Calculate the current drawn by the machine. Calculate the variable losses on load. (8) Calculate the armature power when it runs light. (9) Calculate the stray losses when it runs light. (10) Calculate the full load armature current. (11) (12) (13) Calculate the full load back EMF. Calculate the Variable losses on maximum possible load. Calculate the armature power on maximum load. (14) Calculate…arrow_forwardA 220V dc machine supplies 20A at 200 V as a generator. The armature resistance is 0.2. If the machine is now operated as a motor as a same terminal voltage and current but with flux increased by 10%, the ratio of motor speed to generator speed isarrow_forwardA 220 V DC Machine supplies 20 A at 200 V as a generator. The armature resistance is 0.2 ohm. If the machine is now operated as a motor at the same terminal voltage and current but with the flux increased by 10 percent, the ratio of motor speed to generator speed will bearrow_forward
- 1. Knowing that a motor has a power P of 300 W, calculate the torque T that the motor must produce in order to rotate at a speed n of 1146 r/min. T= 1.79 N·m O T= 2.50 N•m O T= 5.33 N•m O T= 4.14 N-marrow_forwardA 220 V series motor runs at 800 r.p.m., when taking a current of 15 A. The motor has R, = 0.3 Q and R = 0.2 0.Find the resistance to be connected in series with the armature if it has to take the same current at the same voltage at 600 r.m.p.Assume flux is proportional to the current.arrow_forwardTHIS QUESTION IS FROM BOOK ELECTRIC MACHINE 1 FROM TOPIC DC MOTOR A 255 V, DC lathe machine, (not a 2 pole machine) has armature resistance and series resistance are0.15Ω and 170Ω respectively. The motor has 25mWb flux per pole. The ratio of pole to parallel pathsis unity. The product of this ratio and number of turns in armature section is 1000. When it runs light, ithas a speed of 1200 rpm. If it runs at maximum load, it takes a current of 70A. (4) Calculate the no load armature current. and no load shunt current.(6) Calculate the current drawn by the machine.(7) Calculate the variable losses on load and armature power when it runs light.arrow_forward
- A 550-V series motor takes 112A and operates at 820 r/min when the load is 75hp. if the effective armature-circuit resistance is 0.15 ohms calculate the horsepower output of the motor when the current drops to 84A, assuming that the flux is reduced by 15%arrow_forwardTHIS QUESTION IS FROM BOOK ELECTRIC MACHINE 1 FROM TOPIC DC MOTOR A 255 V, DC lathe machine, (not a 2 pole machine) has armature resistance and series resistance are0.15Ω and 170Ω respectively. The motor has 25mWb flux per pole. The ratio of pole to parallel pathsis unity. The product of this ratio and number of turns in armature section is 1000. When it runs light, ithas a speed of 1200 rpm. If it runs at maximum load, it takes a current of 70A. (1) Which machine is this one, shunt or series ?(2) Is machine lap wound or wave wound?(3) Calculate the no load back EMF.(4) Calculate the no load armature current.(5) Calculate the no load shunt current.(6) Calculate the current drawn by the machine.(7) Calculate the variable losses on load.(8) Calculate the armature power when it runs light.(9) Calculate the stray losses when it runs light.(10) Calculate the full load armature current.(11) Calculate the full load back EMF.(12) Calculate the Variable losses on maximum possible load.(13)…arrow_forward128. The hysteresis loss of a dc machine is 300 W when the flux per pole is 30 mWb and the machine is driven at 1000 rpm. How much Is the loss If the field is adjusted to produce 50 mWb per pole whlle the speed Is reduced to 900 rpm? A. 420 W B. 510 W C. 450 W D. 500 Warrow_forward
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