10. The recessive allele that causes Ellis-van Creveld syndrome when homozygous has a frequency of about 0.07 in the Amish population of Pennsylvania, although its frequency is only about 0.001 in the general population. How many persons out of one thousand in the Amish population would be expected to have the disease? a. How many out of one million in the general population would be expected to have the disease?

10. The recessive allele that causes Ellis-van Creveld syndrome when homozygous has a frequency of about 0.07 in the Amish population of Pennsylvania, although its frequency is only about 0.001 in the general population. How many persons out of one thousand in the Amish population would be expected to have the disease? a. How many out of one million in the general population would be expected to have the disease?

Biology: The Unity and Diversity of Life (MindTap Course List)

14th Edition

ISBN:9781305073951

Author:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Publisher:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Chapter13: Observing Patterns In Inherited Traits

Section: Chapter Questions

Problem 11GP: A single allele gives rise to the Hbs form of hemoglobin. Individuals who are homozygous for the...

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Tay-Sachs is a recessive lethal disease in which thereis neurological deterioration early in life. This diseaseis rare in the population overall but is found at relatively high frequency in Ashkenazi Jews from EasternEurope. A woman whose maternal uncle had the disease is trying to determine the probability that sheand her husband could have an affected child. Her father does not come from a high-risk population. Herhusband’s sister died of the disease at an early age.a. Draw the pedigree of the individuals described.Include the genotypes where possible.b. Determine the probability that the couple’s firstchild will be affected.
d Dd 501. s0% 5. Another type of blood disorder is hemophilia, which is an X linked disorder caused by a recessive allele. Like VWD, this disorder interferes with the protein that is involved with blood clotting. Known as "bleeder's disease" because any minor injury can become life threatening. This disorder is considered more severe than VWD. In both cases there are versions of the disorder that can be less and more severe depending on which protein or clotting factor is affected. Normal XHY Normal X"Xh Carrier XhY Hemophilia Bourthelesm X"Xh Hemophilia If a woman is a carrier, what percentage of her SONS will have the disorder? How many (%) of their sons will have hemophilia? How many (%) of their sons will be normal? How many (%) of their daughters will be normal? 6. A man who has hemophilia marries a normal woman (not a carrier)... How many (%) of their sons will have hemophilia? How many (%) of their daughters will be carriers 7. A woman who is a carrier marries a man with…
5.) A man and a woman living in a tropical area where malaria is prevalent and health care is not accessible have seven children during their lifetime. The genotypes of their children are: ss, Ss, SS, ss, Ss, Ss, and SS. What must the genotypes of both parents be? Your answer should include a Punnett square to illustrate your work, and list all the genotypes and phenotypes.
BB AB AB A. None B.3 с.1 D.2 ВВ OE. The father AB In the pedigree presented above, an autosomal dominant disease which causes significant visual loss and eventual blindness, is segregating in the family. The disease gene causing this sight loss looks as if it may be linked to a marker locus. The alleles of this marker locus that are present in this family are allele A and allele B. Are there any recombinant individuals in this pedigree? AB ВВ AB ВВ AB ВВ AB AB ВВ
1.) “Cystic fibrosis is an autosomal recessive disease that affects the entire body. It also results in the early death of an individual. One in every 2500 children is born with this disorder.” The frequency of the homozygous dominant genotype in the above population is ___________. 2.) “The allele for brown eyes in human beings is dominant over that for blue eyes. Out of 50 individuals in a human population, 8 have blue eyes and 42 have brown eyes.” The value of p for the above population is _____. 3.) The allele for brown eyes in human beings is dominant over that for blue eyes. Out of 50 individuals in a human population, 8 have blue eyes and 42 have brown eyes. The frequency of the recessive allele in the above population is______. 4.) The allele for black coat colour is dominant to the allele for white coat colour in mice. In a population of 500 mice, the frequency of the homozygous recessive genotype (q2) is 0.25. The frequency of the dominant allele in the above…
Tay-Sachs disease in humans is caused by a recessive allele. The disease is characterized by mental deficiency and blindness, with death occurring by 4 years of age. Among Ashkenazi Jews of central European ancestry, about 1 in 3600 children is born with the disease. Assume Hardy-Weinberg equilibrium and calculate the frequency of the Tay- Sachs allele in this population. Round your answer to the nearest 0.001. Type your answer...
Cystic fibrosis (CF) is an autosomal recessive disorderthat occurs relatively frequently among people ofEuropean descent. In an Amish community in Ohio,medical researchers reported the occurrence of cysticfibrosis (CF) as being 1/569 live births. Using theHardy–Weinberg rule, estimate the frequency of carriers of the disease allele in this Amish population.
2. The following questions refer to the pedigree chart in the figure for a family, some of whose members exhibit the dominant trait, W. Affected individuals are indicated by a dark square or circle. 2 I ww Ww 2 34 5 6 III IV 1 23 A. What is the genotype of individual II-4? B. What is the genotype of individual II-5? C. If individual II-2 and his partner have a second child, what is the probability that their second child will be a normal, unaffected male? Show your work: 3. Phenylketonuria is an inherited disease caused by a recessive autosomal allele. If a woman and her husband are both carriers, what is the probability that their first child will be a phenotypically normal female? First, draw the pedigree for this family. Then, calculate the probability (show your work): 3 4. A man who is heterozygous for PTC tasting marries a woman who is homozygous recessive. They have two children. Their oldest daughter is a taster, and their youngest boy is a non-taster. What is the probability…
Part I. A. Examine the gene pool of this population (Column A) and then choose the answer for the following questions from the box in Column B. show computation (3pts each) 10% 30% 40% 50% 60% 70% 1. What is the frequency of the AA genotype in this population? 2. What is the frequency of Aa genotype in this population? 3. What is the frequency of the aa genoty pe in this population? 4. What is the frequency of the A allele in this population? 5. What is the frequency of the a allele in this population?
Background information for problem #5 In humans there is a gene that controls formation of hemoglobin (the protein in red blood cells {RBC's} that is responsible for carrying oxygen to the tissues of the body). The normal allele of this gene codes for normal hemoglobin. However, there is another allele for this gene that contains a mutation in the DNA and the resulting hemoglobin protein is defective. An RBC with this defective hemoglobin will, under stress, crystallize within the cell and cause a characteristic sickle shape. While the letters S and s are often used to represent these alleles, in reality neither is dominant to the other (codominant). Someone who is SS makes all normal hemoglobin, someone who is ss makes all abnormal hemoglobin (someone who has sickle-cell anemia), and someone who is Ss essentially has two sets of instructions (and so makes some of each kind of hemoglobin; often referred to as sickle-cell trait). Because the RBC's of a person who is ss contain all…
A single allele gives rise to the Hbs form of hemoglobin. Individuals who are homozygous for the allele (HbS/HbS) develop sickle-cell anemia (Section 9.6). Heterozygous individuals (HbA/HbS) have few symptoms. A couple who are both heterozygous for the HbS allele plan to have children. For each of the pregnancies, state the probability that they will have a child who is: a. homozygous for the HbS allele b. homozygous for the normal allele (HbA) c. heterozygous: HbA/HbS
10 11012 130 14 150 30 170 19C U 2.EVC syndrome O 3. All of the above QUESTION 5 What is the difference between a phenotype and a genotype? O 1.A phenotype is the set of genes an organism carries, a genotype is the organism's observable characteristics O 2. A phenotype is the organism's observable characteristics, a genotype is the set of genes an organism carries QUESTION 6 On a Punnett Square, which combination shows heterozygous alleles? O 1. BB O 2. bb O 3. Bb Click Save and Submit to save and submit. Click Save All Answers to save all answers. 44°F Mostly c の f1 fi0 fe t9 144 f7 1- fs 10 米 & 6. 8. 3. 4 近 %24