Please answer fast 11. The questions below refer to the image on the right: PonarationGenats make elen)Pure os WhoA. Draw a circle around a pair of homozygousdominant alleles (note – there are multipleexamples, you only need to circle one)Gamets ADAPeratonB. Draw a square around a pair of homozygousrecessive alleles (note - there are multipleexamples, you only need to draw a squarearound one)A PpAlleleegregeteGamteFagenerationC. Draw a triangle around a pair of heterozygousalleles (note - there are multiple examples,you only need to draw a triangle around one)Sperm frem F planReulefrom FplantD. What character is being examined in this cross?ReteE. What 2 traits are being examined in this cross?F. What is the phenotypic ratio of the Fi generation (dominant: recessive)?G. Is this a monohybrid or a dihybrid cross?

Alleles are the alternative forms of a gene that are located on the same locus of a homologous…

11. The questions below refer to the image on the right: P A. Draw a circle around a pair of homozygous dominant alleles (note - there are multiple examples, you only need to circle one) B. Draw a square around a pair of homozygous recessive alleles (note - there are multiple examples, you only need to draw a square around one) Fagrtion C. Draw a triangle around a pair of heterozygous alleles (note - there are multiple examples, you only need to draw a triangle around one) Spermo flan D. What character is being examined in this cross? te E. What 2 traits are being examined in this cross? F. What is the phenotypic ratio of the Fa generation (dominant: recessivey? G. Is this a monohybrid or a dihybrid cross?

11. The questions below refer to the image on the right: P A. Draw a circle around a pair of homozygous dominant alleles (note - there are multiple examples, you only need to circle one) B. Draw a square around a pair of homozygous recessive alleles (note - there are multiple examples, you only need to draw a square around one) Fagrtion C. Draw a triangle around a pair of heterozygous alleles (note - there are multiple examples, you only need to draw a triangle around one) Spermo flan D. What character is being examined in this cross? te E. What 2 traits are being examined in this cross? F. What is the phenotypic ratio of the Fa generation (dominant: recessivey? G. Is this a monohybrid or a dihybrid cross?

Biology: The Dynamic Science (MindTap Course List)

4th Edition

ISBN:9781305389892

Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Chapter12: Mendel, Genes, And Inheritance

Section: Chapter Questions

Problem 7TYK: In cats, the genotype AA produces tabby fur color; Aa is also a tabby, and aa is black. Another gene...

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A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What is the chance that this couple will have a child with two copies of the dominant mutant gene? What is the chance that the child will have normal height?
A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. Should the parents be concerned about the heterozygous condition as well as the homozygous mutant condition?
A heterozygous individual has a _______ for a trait being studied. a. pair of identical alleles b. pair of nonidentical alleles c. haploid condition, in genetic terms
In cats, the genotype AA produces tabby fur color; Aa is also a tabby, and aa is black. Another gene at a different locus is epistatic to the gene for fur color. When present in its dominant W form (WW or Ww), this gene blocks the formation of fur color and all the offspring are white; ww individuals develop normal fur color. What fur colors, and in what proportions, would you expect from the cross AaWw Aa Ww?
(X^X^) and one male (X"). 12. The following are the gene order on the chromosomes of an individual who is heterozygous for this translocation. translocations (a.unbalanced breciprocal C. Robertsonian MN OP QR N067 89 34 5P QR 3 4 5 6 7 8 9 a. 0 LMNOP QR LMN067 89 345P QR 3456789 hmm Draw the synapsis (Prophase/Metaphase I) configuration dark spots b. What type of translocation is depicted by these chromosomes and what are the consequences of this chromosome rearrangement to the individual? this type of translocation is unbalanced and the major consequence here is that the chromosome number is not reciprocated leading to all sorts of problems with non-disjunction.
FAlpQLSfiOhfAvlhxzCSiUll_6rt-nU5b0WI73UmWOxkOw8OCwk01ng/formResponse B 1 2 Bb x Bb b 4 The fur in both parents in this cross is * 1 B B Bb x Bb b 3 4 brown black O homozygous dominant homozygous recessive 3. 近
9. Make a pedigree for each of the following situations. For each individual, write the individual's genotype (when possible) next to the individual's symbol (e.g. O xty, I Gg): a. Two parents do not have cystic fibrosis and they have a daughter with cystic fibrosis and a son who does not have cystic fibrosis. The daughter grows up and she mates with a male who does not have cystic fibrosis. Their only child is a boy and he has cystic fibrosis. b. A man with hemophilia mates with a female without hemophilia. They have one son and one daughter. The daughter has hemophilia and the son does not have hemophilia. The son grows up, and he marries and mates with a female. Their only child is a boy, and he has hemophilia.
I need some help with this fill-in-the-blank problem. The answer choices are bolded and bracketed. Please see the attached photo to complete. 1. In the D2S441 locus, Sophie's allele [10, 12] is maternal and her allele 10 is paternal from [Sam or Bill only, Sam or Harry only, Bill or Harry only, Sam Bill or Harry (either 3)]. 2. Sophie's allele 13 for D19S433 is [maternal, paternal] and her allele 14 could have come from [Sam and Bill only, Sam and Harry only, Bill and Harry only, Sam Bill or Harry (either 3)]. 3. In the FGA locus, Sophie's allele [21, 22] is maternal and her other allele could have come only from [Sam, Bill, Harry]. 4. Based on all STRs in the 3 panels we studied, it is clear that [Sam, Bill, Harry] is Sophie's father. He has one allele of Sophie's alleles for all STR loci 5. Would these results stand in court as proof paternity: [Yes or No] 6. This type of DNA profiling can also be used to determine maternity. Is there any doubt that Donna is Sophie's biological…
1- In garden peas, yellow (Y) seed color is dominant to green (y). Because yellow and green are two different forms of the same gene (seed color), they are alleles. Use a Punnett square to show a cross between two heterozygous pea plants. What are the phenotype(s) of the offspring? What are the genotype(s) of the offspring? 2- In garden peas, yellow (Y) seed color is dominant to green (y). Because yellow and green are two different forms of the same gene (seed color), they are alleles. Use a Punnett square to show a cross between two heterozygous pea plants. What are the phenotype(s) of the offspring? What are the genotype(s) of the offspring? Use the information below to answer questions 3-6 There may be a number of possible alleles for a given gene within a population. In a multiple allele system the dominance relationships between the various alleles must be considered. One of the more familiar examples of a multiple allelic system is that of the human ABO blood group. The gene…
Purple flowers are dominant to white flowers. Identify the phenotypefor the following genotype Ff, FF, ff and determine if the genotype is heterozygous or homozygous. * For each row, you should select two columns. Purple flowers White flowers Heterozygous Homozygous Ff FF ff Brown eyes are dominant to blue eyes. Identify the phenotype for the following genotype BB, Bb, bb and determine if the genotype is heterozygous or homozygous. * 口ロ口

Genetic Crosses that Involve 2 Traits In rabbits, black hair is dominant to brown hair. Also in rabbits, long straight ears are dominant to floppy ears. These letters represent the genotypes and phenotypes of the rabbits: BB = black hair EE = long ears Ee = long ears ee = floppy ears %3D %3D Bb = black hair bb = brown 1. A male rabbit with the genotype BBee is crossed with a female rabbit with the genotype bbEe The square Is set up below. Fill it out and determine the phenotypes and proportions in the offspring. How many out of 16 have black hair Ве Ве Ве Ве and long ears? bE How many out of 16 have black hair and floppy ears? be How many out of 16 have brown hair and long ears? bE How many out of 16 have brown hair be and floppy ears?
8. Answer the following questions for the two following pedigrees In Pedigree A, is the red highlighted trait dominant or recessive? Why? а. b. What is the genotype of individual C? In Pedigree B, is the red highlighted trait dominant or recessive? Why? а. d. What is the genotype of individual D? Pedigree A Pedigree B mele male : foncle I femole teffected D offected