Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 7.3, Problem 21LC
Interpretation Introduction

Interpretation: The reason for alloys to be more useful than pure metals need to be explained.

Concept Introduction: Alloy is formed by combining metals with metals or non-metals. Thus, it is a metal formed by the combination of two and more metals or a metal and a non-metal. Some examples of alloys are bronze, stainless steel, brass, etc.

Expert Solution & Answer
Check Mark

Explanation of Solution

Alloy can be defined as a mixture of two or more elements. They have metallic properties and at least one of the elements is metal. In daily life, it is difficult to find iron, copper, silver, gold, and other metals in pure form. They are always used as alloys. Some of the alloys are brass, bronze, steel, etc. Thus, the alloy is formed to enhance the properties of metals. It also helps in making the metal more ductile. It is done by combining the best properties of different metals. For example, iron can be easily corroded when exposed to the atmosphere but steel which is an alloy of iron and copper cannot corrode easily thus, it is used to make utensils.

Conclusion

Therefore, alloys are more useful than pure metals because they have greater strength and resistance to corrosion as compared to metals in pure form.

Chapter 7 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 7.2 - Prob. 11SPCh. 7.2 - Prob. 12LCCh. 7.2 - Prob. 13LCCh. 7.2 - Prob. 14LCCh. 7.2 - Prob. 15LCCh. 7.2 - Prob. 16LCCh. 7.2 - Prob. 17LCCh. 7.2 - Prob. 18LCCh. 7.2 - Prob. 19LCCh. 7.3 - Prob. 20LCCh. 7.3 - Prob. 21LCCh. 7.3 - Prob. 22LCCh. 7.3 - Prob. 23LCCh. 7.3 - Prob. 24LCCh. 7.3 - Prob. 25LCCh. 7.3 - Prob. 26LCCh. 7 - Prob. 27ACh. 7 - Prob. 28ACh. 7 - Prob. 29ACh. 7 - Prob. 30ACh. 7 - Prob. 31ACh. 7 - Prob. 32ACh. 7 - Prob. 33ACh. 7 - Prob. 34ACh. 7 - Prob. 35ACh. 7 - Prob. 36ACh. 7 - Prob. 37ACh. 7 - Prob. 38ACh. 7 - Prob. 39ACh. 7 - Prob. 40ACh. 7 - Prob. 41ACh. 7 - Prob. 42ACh. 7 - Prob. 43ACh. 7 - Prob. 44ACh. 7 - Prob. 45ACh. 7 - Prob. 46ACh. 7 - Prob. 47ACh. 7 - Prob. 48ACh. 7 - Prob. 49ACh. 7 - Prob. 50ACh. 7 - Prob. 51ACh. 7 - Prob. 52ACh. 7 - Prob. 53ACh. 7 - Prob. 54ACh. 7 - Prob. 55ACh. 7 - Prob. 56ACh. 7 - Prob. 57ACh. 7 - Prob. 58ACh. 7 - Prob. 59ACh. 7 - Prob. 60ACh. 7 - Prob. 61ACh. 7 - Prob. 62ACh. 7 - Prob. 63ACh. 7 - Prob. 64ACh. 7 - Prob. 65ACh. 7 - Prob. 66ACh. 7 - Prob. 67ACh. 7 - Prob. 68ACh. 7 - Prob. 69ACh. 7 - Prob. 70ACh. 7 - Prob. 71ACh. 7 - Prob. 72ACh. 7 - Prob. 73ACh. 7 - Prob. 74ACh. 7 - Prob. 75ACh. 7 - Prob. 76ACh. 7 - Prob. 77ACh. 7 - Prob. 78ACh. 7 - Prob. 79ACh. 7 - Prob. 80ACh. 7 - Prob. 81ACh. 7 - Prob. 82ACh. 7 - Prob. 83ACh. 7 - Prob. 84ACh. 7 - Prob. 85ACh. 7 - Prob. 86ACh. 7 - Prob. 87ACh. 7 - Prob. 88ACh. 7 - Prob. 89ACh. 7 - Prob. 90ACh. 7 - Prob. 91ACh. 7 - Prob. 92ACh. 7 - Prob. 93ACh. 7 - Prob. 94ACh. 7 - Prob. 95ACh. 7 - Prob. 96ACh. 7 - Prob. 97ACh. 7 - Prob. 98ACh. 7 - Prob. 99ACh. 7 - Prob. 100ACh. 7 - Prob. 101ACh. 7 - Prob. 102ACh. 7 - Prob. 103ACh. 7 - Prob. 104ACh. 7 - Prob. 105ACh. 7 - Prob. 106ACh. 7 - Prob. 107ACh. 7 - Prob. 108ACh. 7 - Prob. 109ACh. 7 - Prob. 110ACh. 7 - Prob. 111ACh. 7 - Prob. 112ACh. 7 - Prob. 113ACh. 7 - Prob. 114ACh. 7 - Prob. 1STPCh. 7 - Prob. 2STPCh. 7 - Prob. 3STPCh. 7 - Prob. 4STPCh. 7 - Prob. 5STPCh. 7 - Prob. 6STPCh. 7 - Prob. 7STPCh. 7 - Prob. 8STPCh. 7 - Prob. 9STPCh. 7 - Prob. 10STPCh. 7 - Prob. 11STPCh. 7 - Prob. 12STP
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