Explanation Given information: r ( t ) is the hourly rate that an animal burns calories and R ( t ) is the total number of calories burned since time t = 0. Assume r ( t ) > 0 and r ' ( t ) < 0 for 0 ≤ t ≤ 12 . Concept used: If f ' < 0 on an interval, then f is decreasing and the graph of f is concave down on that interval. If f ' > 0 on an interval, then f is increasing and the graph of f is concave up on that interval. Calculation: r ( t ) > 0 and r ' ( t ) < 0 for 0 ≤ t ≤ 12 . ⇒ r ( t ) is decreasing and concave down on the interval 0 ≤ t ≤ 12

6th Edition

ISBN: 9781119399353

Author: DA

Publisher: JOHN WILEY+SONS,INC.-CONSIGNMENT

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Chapter 5.5, Problem 26P

To determine

To list:

The expressions (I)-(III) in order from smallest to largest.

R(10)

R(12)

R(10)+r(10)⋅2

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Chapter 5.5, Problem 25P

Chapter 5.5, Problem 27P

Chapter 5 Solutions

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Ch. 5.1 - Prob. 1P Ch. 5.1 - Prob. 2P Ch. 5.1 - Prob. 3P Ch. 5.1 - Prob. 4P Ch. 5.1 - Prob. 5P Ch. 5.1 - Prob. 6P Ch. 5.1 - Prob. 7P Ch. 5.1 - Prob. 8P Ch. 5.1 - Prob. 9P Ch. 5.1 - Prob. 10P

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The expressions (I)-(III) in order from smallest to largest. R ( 10 ) R ( 12 ) R ( 10 ) + r ( 10 ) ⋅ 2

Solution Summary: The author lists the expressions (I)-(III) in order from smallest to largest. r(t) is the hourly rate that an animal burns calories.

Concept explainers

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To list:

The expressions (I)-(III) in order from smallest to largest.

R(10)

R(12)

R(10)+r(10)⋅2

Want to see the full answer?

Chapter 5 Solutions

The expressions (I)-(III) in order from smallest to largest. R ( 10 ) R ( 12 ) R ( 10 ) + r ( 10 ) ⋅ 2

Solution Summary: The author lists the expressions (I)-(III) in order from smallest to largest. r(t) is the hourly rate that an animal burns calories.

Concept explainers

Videos

To list: The expressions (I)-(III) in order from smallest to largest. R(10) R(12) R(10)+r(10)⋅2

Want to see the full answer?

Chapter 5 Solutions

To list:

The expressions (I)-(III) in order from smallest to largest.

R(10)

R(12)

R(10)+r(10)⋅2