To Prove: Prove that partial derivative of ln ( det A ) gives A − 1 . f ( a , b , c , d ) = ln ( a d − b c ) leads to [ ∂ f ∂ a ∂ f ∂ c ∂ f ∂ b ∂ f ∂ d ] = A − 1

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Answer 1

Question

Chapter 5.1, Problem 30PS

To determine

To Prove:

Prove that partial derivative of ln(detA) gives A−1.

f(a,b,c,d)=ln(ad−bc) leads to [ ∂f ∂a ∂f ∂c ∂f ∂b ∂f ∂d]=A−1

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Answer 2

Question

Chapter 5.1, Problem 30PS

To determine

To Prove:

Prove that partial derivative of ln(detA) gives A−1.

f(a,b,c,d)=ln(ad−bc) leads to [ ∂f ∂a ∂f ∂c ∂f ∂b ∂f ∂d]=A−1

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Answer 3

Question

Chapter 5.1, Problem 30PS

To determine

To Prove:

Prove that partial derivative of ln(detA) gives A−1.

f(a,b,c,d)=ln(ad−bc) leads to [ ∂f ∂a ∂f ∂c ∂f ∂b ∂f ∂d]=A−1

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Answer 4

Question

Chapter 5.1, Problem 30PS

To determine

To Prove:

Prove that partial derivative of ln(detA) gives A−1.

f(a,b,c,d)=ln(ad−bc) leads to [ ∂f ∂a ∂f ∂c ∂f ∂b ∂f ∂d]=A−1

Expert Solution & Answer

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Answer 5

Chapter 5.1, Problem 30PS

To determine

To Prove:

Prove that partial derivative of ln(detA) gives A−1.

f(a,b,c,d)=ln(ad−bc) leads to [ ∂f ∂a ∂f ∂c ∂f ∂b ∂f ∂d]=A−1

Answer 6

Chapter 5.1, Problem 30PS

To determine

To Prove:

Prove that partial derivative of ln(detA) gives A−1.

f(a,b,c,d)=ln(ad−bc) leads to [ ∂f ∂a ∂f ∂c ∂f ∂b ∂f ∂d]=A−1

Answer 7

Chapter 5.1, Problem 30PS

To determine

To Prove:

Prove that partial derivative of ln(detA) gives A−1.

f(a,b,c,d)=ln(ad−bc) leads to [ ∂f ∂a ∂f ∂c ∂f ∂b ∂f ∂d]=A−1

Answer 8

Expert Solution & Answer

Answer 9

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Answer 10

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Answer 11

Ch. 5.1 - Prob. 1PS Ch. 5.1 - Prob. 2PS Ch. 5.1 - Prob. 3PS Ch. 5.1 - Prob. 4PS Ch. 5.1 - Prob. 5PS Ch. 5.1 - Prob. 6PS Ch. 5.1 - Prob. 7PS Ch. 5.1 - Prob. 8PS Ch. 5.1 - Prob. 9PS Ch. 5.1 - Prob. 10PS

To Prove: Prove that partial derivative of ln ( det A ) gives A − 1 . f ( a , b , c , d ) = ln ( a d − b c ) leads to [ ∂ f ∂ a ∂ f ∂ c ∂ f ∂ b ∂ f ∂ d ] = A − 1

To Prove: Prove that partial derivative of ln(detA) gives A−1. f(a,b,c,d)=ln(ad−bc) leads to [ ∂f ∂a ∂f ∂c ∂f ∂b ∂f ∂d]=A−1

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Chapter 5 Solutions

To Prove:

Prove that partial derivative of ln(detA) gives A−1.

f(a,b,c,d)=ln(ad−bc) leads to [ ∂f ∂a ∂f ∂c ∂f ∂b ∂f ∂d]=A−1