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Review. Three forces acting on an object are given by
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Chapter 5 Solutions
Physics for Scientists and Engineers
- While an elevator of mass 898 kg moves downward, the tension in the supporting cable is a constant 7730 N. Between t=0 and 1= 4.00 s, the elevator's displacement is 5.00 m downward. What is the elevator's speed at f= 4.00 s? m/sarrow_forwardYou are pushing a wooden crate against a rubber floor. The two surfaces have a static coefficient of friction of 0.45 and a kinetic coefficient of friction of 0.38. The floor is horizontal, and the crate has a mass of 25.0 kg, and is initially at rest. You are pushing with a horizontal force of 155 N. What is the magnitude of the force of friction in this case? Give your answer in units of N, to three significant figures.arrow_forwardOnly two forces act on an object (mass=3.61 kg), as in the drawing. Find (a) the magnitude and (b) the direction (relative to the x axis) of the acceleration of the object. (a) Number (b) Number i 145.0° 1 40.0 N 60.0 N +X Units Unitsarrow_forward
- Let V1 = -6.4 i^ + 8.1 j^ and V2 = -4.5 j^ + 4.4 i^. Determine the magnitude of abs.(V1+V2)arrow_forwardA cart of mass 8.00 kg was moved by applying two constant forces. Force 1 is 28.0 N at 42.0°, and Force 2 is 13.0 N at 110°. Initially, the cart has a velocity of (3.50 i +2.20 j) m/s. a. Express the two forces in in unit-vector notation. Ans. F = (20.81 i + 18.74 j)N, F, = (-4.45 i + 12.22 j)N b. Find the total force exerted on the cart. Ans. EF = (16.36 i + 30.96 j)N or 35.02 N Find the angle at which the total force is applied. Ans. 62.15° NEERINarrow_forwardA cart of mass 8.00 kg was moved by applying two constant forces. Force 1 is 28.0 N at 42.0°, and Force 2 is 13.0 N at 110°. Initially, the cart has a velocity of (3.50 i +2.20 j) m/s. a. Express the two forces in in unit-vector notation. Ans. F = (20.81 i+ 18.74 j)N, F, =(-4.45 i+ 12.22 j)N b. Find the total force exerted on the cart. Ans. EF = (16.36 i + 30.96 j)N or 35.02 N c. Find the angle at which the total force is applied. Ans. 62.15º d. What is the acceleration of the cart? Ans. å = (2.05 i + 3.87 j)" or 4.38 EERINarrow_forward
- A cart of mass 8.00 kg was moved by applying two constant forces. Force 1 is 28.0 N at 42.0°, and Force 2 is 13.0 N at 110°. Initially, the cart has a velocity of (3.50 i +2.20 j) m/s. a. Express the two forces in in unit-vector notation. Ans. F = (20.81 i + 18.74 j)N, F, = (-4.45 i + 12.22 j)N b. Find the total force exerted on the cart. Ans. EF = (16.36 i+ 30.96 j)N or 35.02 N c. Find the angle at which the total force is applied. Ans. 62.15°arrow_forwardYou place a crate of mass 39.4 kg on a frictionless 3.67- meter-long incline. You release the crate from rest, and it begins to slide down, eventually reaching the bottom 1.27 s after you released it. What is the angle of the incline? 1 27.6 degrees 2 38.6 degrees 3 57.9 degrees 4 33.1 degreesarrow_forwardA crate of mass m = 2.00 kg is released from rest at the top of an inclined plane as seen in the figure. The crate starts out at height = 0.100 m above the top of the table, the table height is H = 2.00 m, and 0 = 41.0⁰. H ↑ h i (a) What is the acceleration (in m/s2) of the crate while it slides down the incline? m/s² m (b) What is the speed (in m/s) of the crate when it leaves the incline? m/s (c) At what horizontal distance (in m) from the end of the table will the crate hit the ground? m O No (d) How long (in s) from when the crate is released does it hit the ground? S (e) Does the crate's mass affect any of your above answers? Yesarrow_forward
- You are pushing a rubber crate against a concrete floor. The two surfaces have a static coefficient of friction of 0.61 and a kinetic coefficient of friction of 0.49. The floor is horizontal, and the crate has a mass of 25.0 kg, and is initially at rest. You are pushing with a horizontal force of 100 N. What is the magnitude of the force of friction in this case? Give your answer in units of N, to three significant figures.arrow_forwardIn the figure, a body with a mass of 2 kg moves under the influence of two constant forces F1 = 5N and F2 = 4N in the xy plane. At time t = 0, the object is at point 0 and its speed is V = 2i + j (m / s). What is the acceleration of the particle and its position after 2 seconds in terms of the unit vector?arrow_forwardA box of mass m = 2.00 kg is released from rest at the top of an inclined plane as seen in the figure. The box starts out at height h 0.200 m above the top of the table, the table height is H = 2.00 m, and 8 = 45.0⁰. = H m (a) What is the acceleration (in m/s²) of the box while it slides down the incline? m/s² (b) What is the speed (in m/s) of the box when it leaves the incline? m/s (c) At what horizontal distance (in m) from the end of the table will the box hit the ground? m (d) How long (in s) from when the box is released does it hit the ground? S (e) Does the box's mass affect any of your above answers? Yes Noarrow_forward
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