(a)
Interpretation:
Interpret name of CuCl.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The name of Binary ion contains the name of cation first then proceeded the name of anion. The name of cation in Binary ion remain same to that of metal while for anion its name ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state name is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
(b)
Interpretation:
Interpret name of Fe2 O3.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The name of Binary ion contains the name of cation first then proceeded the name of anion. The name of cation in Binary ion remain same to that of metal while for anion its name ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state name is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
(c)
Interpretation:
Interpret name of Hg2 Cl2.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The name of Binary ion contains the name of cation first then proceeded the name of anion. The name of cation in Binary ion remain same to that of metal while for anion its name ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state name is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
(d)
Interpretation:
Interpret name of MnCl2.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The name of Binary ion contains the name of cation first then proceeded the name of anion. The name of cation in Binary ion remain same to that of metal while for anion its name ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state name is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
(e)
Interpretation:
Interpret name of TiO2.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The name of Binary ion contains the name of cation first then proceeded the name of anion. The name of cation in Binary ion remain same to that of metal while for anion its name ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state name is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
(f)
Interpretation:
Interpret name of PbO.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The name of Binary ion contains the name of cation first then proceeded the name of anion. The name of cation in Binary ion remain same to that of metal while for anion its name ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state name is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
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Chapter 5 Solutions
Introductory Chemistry: A Foundation
- For the following processes that show the formation of ions, use the periodic table to indicate the number of electrons and protons present in both theionand theneutral atomfrom which the ion is made. a.CaCa2++2e b.P+3eP3 c.Br+eBr d.FeEe3++3e e.AlAl3++3e f.N+3eN3arrow_forwardName the compounds in parts ad and write the formulas for the compounds in parts eh. a. NaBr b. Rb2O c. CaS d. AlI3 e. strontium fluoride f. aluminum selenide g. potassium nitride h. magnesium phosphidearrow_forwardName the compounds in parts a-d and write the formulas for the compounds in parts eh. a. Hg2O b. FeBr3 c. CoS d. TiCl4 e. tin(II) nitride f. cobalt(III) iodide g. mercury(II) oxide h. chromium(VI) sulfidearrow_forward
- The formula of barium molybdate is BaMoO4. Which of the following is the formula of sodium molybdate? (a) Na4MoO (b) NaMoO (c) Na2MoO3 (d) Na2MoO4 (e) Na4MoO4arrow_forwardWrite the formula for each of the following compounds: a. chromium(VI) oxide b. disulfur dichloride c. nickel(II) fluoride d. potassium hydrogen phosphate e. aluminum nitride f. ammonia g. manganese(IV) sulfide h. sodium dichromate i. ammonium sulfite j. carbon tetraiodidearrow_forward
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