Introduction To Health Physics
Introduction To Health Physics
5th Edition
ISBN: 9780071835275
Author: Johnson, Thomas E. (thomas Edward), Cember, Herman.
Publisher: Mcgraw-hill Education,
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Chapter 3, Problem 3.22P
To determine

To calculate:The molecular weight of chlorine.

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QUESTION 19 In 1911, when Rutherford observed alpha particles being scattered at back angles from a gold foil, he reached the conclusion that alpha particles are helium nuclei. alpha particles are very tightly bound. the plum-pudding model of the atom must be wrong . gold has a much higher atomic number than previously thought.
Use the below values for this problem. Please note that the mass for H is for the entire atom (proton & electron). Neutron: m,= 1.67493x1027 kg= 1.008665 u = 939.57 MeVIC H: my = 1.67353x10 27 kg = 1.007825 u = 938.78 MeVic 1u= 1.6605x10-27 kg = 931.5 MeVic? Consider the following decay: 211 At 207 Bi + a. 211 At has a mass of 210.9874963 u, 207 Bi has a mass of 206.981593 u, and a has a mass of 4.002603 u. 85 83 85 83 Determine the disintegration energy (Q-value) in MeV. Determine the binding energy (in MeV) for 211 At. 85 EB =
The two nuclei in the nitric oxide (NO) molecule are 0.1154 nm apart. The mass of the most common nitrogen atom is 2.326 * 10-26 kg, and the mass of the most common oxygen atom is 2.656 * 10-26 kg. Find the reduced mass of the NO molecule.
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