Suppose the alphabet consists of
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Elements Of Modern Algebra
- Suppose that in a long ciphertext message the letter occurred most frequently, followed in frequency by. Using the fact that in the -letter alphabet, described in Example, "blank" occurs most frequently, followed in frequency by, read the portion of the message enciphered using an affine mapping on. Write out the affine mapping and its inverse. Example 2 Translation Cipher Associate the letters of the "alphabet" with the integers. Let and define the mapping by where is the key, the number of positions from the plaintext to the ciphertext. If our alphabet consists of through, in natural order, followed by a blank, then we have "letters" that we associate with the integers as follows:arrow_forwardSuppose the RSA system that is used for sending secret messages has private key (15, 3) and the cipher text "4" is received. What was the plain text sent? 12 0 8 6 4arrow_forwardEncrypt the message APPLES AND ORANGES using a shift cipher with key k = 13.arrow_forward
- Suppose the Caesar cipher is used to encrypt the message "QUICK." Which of the following cipher text corresponds to this plain text? O TXLFN TLXFN TXLNF None of the Abovearrow_forwardDecrypt the message "XMJQYJWNSUQFHJ" which was encrypted with a Caesar cipher with a shift of 5 (A to F). Give your response in all caps with no spaces.arrow_forward1. Use A¹ to decode the cryptogram 1 = [33] 85 120 6 8 10 15 84 117 42 56 90 125 60 80 30 45 19 26arrow_forward
- Encrypt the message AT TEN HEAD NORTH TO TRENCHES using a tabular transposition cipher with rows of length 4 characters. If necessary, pad the message with A's.arrow_forward5. Find the plaintext message if the ciphertext produced by exponential encryption (§8.3) with key (e, p) (7,3001) is: = 2059 2010 1027 1524 1511 1717 1378 1713 0668 0937 1734arrow_forwardSuppose the RSA cryptosystem is used with public key (35, 7). What is the corresponding cipher text when the plain text "2" is sent? O 23 15 12 O 8arrow_forward
- Suppose (n, d) = (55, 3) is the private key of an RSA cryptosystem. If the received ciphertext is C = 49 what is the corresponding plaintext? O 3 4 10 14arrow_forwardThe following parameters are chosen to generate the public and private keys for the RSA cryptosystem. p = 13q = 11e = 37d = 13 If the ciphertext is c = 8, then what is the plaintext m?arrow_forwardEncrypt the message KILLTHEBEAST using shift cipher with K=18.arrow_forward
- Elements Of Modern AlgebraAlgebraISBN:9781285463230Author:Gilbert, Linda, JimmiePublisher:Cengage Learning,