Identical beams of light are incident on three different pairs of (ideal) polarizers. The double arrow drawn on each polarizer represents its direction of polarization. Suppose that the incident light in each case were unpolarized . Rank the three cases (A−C) according to the intensity of the light transmitted past the second polarizer, from largest to smallest. If for any case no light is transmitted past the second polarizer, state that explicitly. Explain your reasoning .

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Answer 1

Textbook Question

Chapter 25.7, Problem 1aTH

Identical beams of light are incident on three different pairs of (ideal) polarizers. The double arrow drawn on each polarizer represents its direction of polarization.

Chapter 25.7, Problem 1aTH, Identical beams of light are incident on three different pairs of (ideal) polarizers. The double , example 1

Suppose that the incident light in each case were unpolarized.

Rank the three cases (A−C) according to the intensity of the light transmitted past the second polarizer, from largest to smallest. If for any case no light is transmitted past the second polarizer, state that explicitly. Explain your reasoning.

Expert Solution & Answer

To determine

The ranking of intensity of light after passing through the second polarizer in each case.

Answer to Problem 1aTH

B<A=C

Explanation of Solution

Introduction:

The intensity of light passing through a polarizer depends directly on square of cosine of the angle. Smaller the angle between the two polarizer, greater will be the intensity of light passing through the second polarizer.

The angle between the two polariser is smallest in case A. hence the intensity of light is greatest in case A.

For case A and case C, the value of square of cosine of the angle between two polariser is same. Hence the intensity of light is same in case A and case C.

The angle between the two polariser is greatest in case B. hence the intensity of light is smallest in case B.

Conclusion:

Hence the intensity of light after passing through second polarizer is same in case A and case C and is greater than the intensity of light in case B.

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We have a plane electromagnetic wave traveling in the +z direction. As you may recall, plane waves have electric and magnetic fields that vary like either sine or cosine, with an argument of (kz−ωt). Our goal here will be to write down the equations describing the electric and magnetic fields in this particular wave, and then use those equations to calculate a few quantities.Let's suppose that at z=0 and t=0, the magnetic field has its maximum value B0 and points in the −y direction. Use that information to decide whether your B -field should vary like sine or like cosine, and write a symbolic vector expression for B . Then write a symbolic vector expression for the E -field that would be in this wave. The definition of the Poynting vector will let you figure the direction of the E -field. A) The frequency of this wave is f=3.060e+06 Hz. What is the scalar value of the magnetic field at t=1.29e−07 s? You can still assume that z=0, and that B0 = .0056 T . For m answer I got .0059 T…

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Answer 2

Textbook Question

Chapter 25.7, Problem 1aTH

Identical beams of light are incident on three different pairs of (ideal) polarizers. The double arrow drawn on each polarizer represents its direction of polarization.

Chapter 25.7, Problem 1aTH, Identical beams of light are incident on three different pairs of (ideal) polarizers. The double , example 1

Suppose that the incident light in each case were unpolarized.

Rank the three cases (A−C) according to the intensity of the light transmitted past the second polarizer, from largest to smallest. If for any case no light is transmitted past the second polarizer, state that explicitly. Explain your reasoning.

Expert Solution & Answer

To determine

The ranking of intensity of light after passing through the second polarizer in each case.

Answer to Problem 1aTH

B<A=C

Explanation of Solution

Introduction:

The intensity of light passing through a polarizer depends directly on square of cosine of the angle. Smaller the angle between the two polarizer, greater will be the intensity of light passing through the second polarizer.

The angle between the two polariser is smallest in case A. hence the intensity of light is greatest in case A.

For case A and case C, the value of square of cosine of the angle between two polariser is same. Hence the intensity of light is same in case A and case C.

The angle between the two polariser is greatest in case B. hence the intensity of light is smallest in case B.

Conclusion:

Hence the intensity of light after passing through second polarizer is same in case A and case C and is greater than the intensity of light in case B.

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Answer 3

Textbook Question

Chapter 25.7, Problem 1aTH

Identical beams of light are incident on three different pairs of (ideal) polarizers. The double arrow drawn on each polarizer represents its direction of polarization.

Chapter 25.7, Problem 1aTH, Identical beams of light are incident on three different pairs of (ideal) polarizers. The double , example 1

Suppose that the incident light in each case were unpolarized.

Rank the three cases (A−C) according to the intensity of the light transmitted past the second polarizer, from largest to smallest. If for any case no light is transmitted past the second polarizer, state that explicitly. Explain your reasoning.

Expert Solution & Answer

To determine

The ranking of intensity of light after passing through the second polarizer in each case.

Answer to Problem 1aTH

B<A=C

Explanation of Solution

Introduction:

The intensity of light passing through a polarizer depends directly on square of cosine of the angle. Smaller the angle between the two polarizer, greater will be the intensity of light passing through the second polarizer.

The angle between the two polariser is smallest in case A. hence the intensity of light is greatest in case A.

For case A and case C, the value of square of cosine of the angle between two polariser is same. Hence the intensity of light is same in case A and case C.

The angle between the two polariser is greatest in case B. hence the intensity of light is smallest in case B.

Conclusion:

Hence the intensity of light after passing through second polarizer is same in case A and case C and is greater than the intensity of light in case B.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Textbook Question

Chapter 25.7, Problem 1aTH

Identical beams of light are incident on three different pairs of (ideal) polarizers. The double arrow drawn on each polarizer represents its direction of polarization.

Chapter 25.7, Problem 1aTH, Identical beams of light are incident on three different pairs of (ideal) polarizers. The double , example 1

Suppose that the incident light in each case were unpolarized.

Rank the three cases (A−C) according to the intensity of the light transmitted past the second polarizer, from largest to smallest. If for any case no light is transmitted past the second polarizer, state that explicitly. Explain your reasoning.

Expert Solution & Answer

To determine

The ranking of intensity of light after passing through the second polarizer in each case.

Answer to Problem 1aTH

B<A=C

Explanation of Solution

Introduction:

The intensity of light passing through a polarizer depends directly on square of cosine of the angle. Smaller the angle between the two polarizer, greater will be the intensity of light passing through the second polarizer.

The angle between the two polariser is smallest in case A. hence the intensity of light is greatest in case A.

For case A and case C, the value of square of cosine of the angle between two polariser is same. Hence the intensity of light is same in case A and case C.

The angle between the two polariser is greatest in case B. hence the intensity of light is smallest in case B.

Conclusion:

Hence the intensity of light after passing through second polarizer is same in case A and case C and is greater than the intensity of light in case B.

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Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution & Answer

To determine

The ranking of intensity of light after passing through the second polarizer in each case.

Answer to Problem 1aTH

B<A=C

Explanation of Solution

Introduction:

The intensity of light passing through a polarizer depends directly on square of cosine of the angle. Smaller the angle between the two polarizer, greater will be the intensity of light passing through the second polarizer.

The angle between the two polariser is smallest in case A. hence the intensity of light is greatest in case A.

For case A and case C, the value of square of cosine of the angle between two polariser is same. Hence the intensity of light is same in case A and case C.

The angle between the two polariser is greatest in case B. hence the intensity of light is smallest in case B.

Conclusion:

Hence the intensity of light after passing through second polarizer is same in case A and case C and is greater than the intensity of light in case B.

Answer 8

Expert Solution & Answer

To determine

The ranking of intensity of light after passing through the second polarizer in each case.

Answer to Problem 1aTH

B<A=C

Explanation of Solution

Introduction:

The intensity of light passing through a polarizer depends directly on square of cosine of the angle. Smaller the angle between the two polarizer, greater will be the intensity of light passing through the second polarizer.

The angle between the two polariser is smallest in case A. hence the intensity of light is greatest in case A.

For case A and case C, the value of square of cosine of the angle between two polariser is same. Hence the intensity of light is same in case A and case C.

The angle between the two polariser is greatest in case B. hence the intensity of light is smallest in case B.

Conclusion:

Hence the intensity of light after passing through second polarizer is same in case A and case C and is greater than the intensity of light in case B.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

To determine

The ranking of intensity of light after passing through the second polarizer in each case.

Answer 12

Answer to Problem 1aTH

B<A=C

Answer 13

Explanation of Solution

Introduction:

The intensity of light passing through a polarizer depends directly on square of cosine of the angle. Smaller the angle between the two polarizer, greater will be the intensity of light passing through the second polarizer.

The angle between the two polariser is smallest in case A. hence the intensity of light is greatest in case A.

For case A and case C, the value of square of cosine of the angle between two polariser is same. Hence the intensity of light is same in case A and case C.

The angle between the two polariser is greatest in case B. hence the intensity of light is smallest in case B.

Conclusion:

Hence the intensity of light after passing through second polarizer is same in case A and case C and is greater than the intensity of light in case B.

Answer 14

Ch. 25.1 - The top view diagram at right illustrates two...Ch. 25.1 - The top view diagram at right illustrates two...Ch. 25.1 - Label each nodal line and line of maximum...Ch. 25.1 - Prob. 2bTH Ch. 25.1 - How do the angles a and ß compare? Explain.Ch. 25.1 - Prob. 3bTH Ch. 25.1 - Prob. 3cTH Ch. 25.1 - The enlarged diagram at right illustrates the...Ch. 25.1 - For what values of D (in terms of ) will there be:...Ch. 25.1 - Use your answers from parts d and e to write...

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