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Complete hydrolysis of an unknown basic decapeptide gives Gly, Ala, Leu, IIe, Phe, Tyr, Glu, Arg, Lys, and Ser. Terminal residue analysis shows that the N terminus is Ala and the C terminus is lle. Incubation of the decapeptide with chymotrypsin gives two tripeptides, A and B, and a tetrapeptide, C. Amino acid analysis shows that peptide A contains Gly, Glu, Tyr, and NH3; peptide B contains Ala, Phe, and Lys, and peptide C contains Leu, lle, Ser, and Arg. Terminal residue analysis gives the following results.
N terminus | C terminus | |
A | Gln | Tyr |
B | Ala | Phe |
C | Arg | Ile |
Incubation of the decapeptide with trypsin gives a dipeptide D, a pentapeptide E, and a tripeptide F. Terminal residue analysis of F shows that the N terminus is Ser and the C terminus is Iie. Propose a structure for the decapeptide and for fragments A through F.
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Organic Chemistry (9th Edition)
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