General, Organic, and Biological Chemistry
General, Organic, and Biological Chemistry
7th Edition
ISBN: 9781285853918
Author: H. Stephen Stoker
Publisher: Cengage Learning
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Chapter 24, Problem 24.19EP

(a)

Interpretation Introduction

Interpretation: To identify the name of the missing substance in the following word equation.

Glucose+ATPHexokinase?_+ADP

Concept introduction: Glycolysis is the metabolic pathway that breaks down a glucose molecule and converts it into two pyruvate molecules along with the production of two ATP molecules and NADH reduced coenzymes.

The block diagram to represent an overview of glycolysis is as follows:

General, Organic, and Biological Chemistry, Chapter 24, Problem 24.19EP , additional homework tip  1

From the above diagram, it is concluded that in the overall process of glycolysis, two stages are present.

a) Steps 1 to 3 represents a six-carbon stage (C6 stage).

b) Steps 4 to 10 represent a three-carbon stage (C3 stage).

The transfer of a phosphoryl group (PO32) is catalyzed by the kinase enzymes. In the glycolysis process, the phosphate group comes from ATP, ADP or some higher energetic phosphate molecules.

(a)

Expert Solution
Check Mark

Answer to Problem 24.19EP

The complete word equation is as follows:

Glucose+ATPHexokinaseGlucose 6phosphate_+ADP

Explanation of Solution

The first step in the glycolysis process is the phosphorylation of glucose using ATP. Glucose is converted to glucose 6phosphate. The phosphoryl group (PO32) is transferred from ATP to glucose, thus ATP is converted to ADP. Hexokinase enzyme catalyzes this reaction. The word equation for the phosphorylation reaction is as follows:

Glucose+ATPHexokinaseGlucose 6phosphate+ADP

Conclusion

In step 1, glucose is converted to glucose 6phosphate. The phosphoryl group (PO32) is transferred from ATP to glucose. ATP is converted to ADP. Therefore, the missing substance is glucose 6phosphate.

(b)

Interpretation Introduction

Interpretation: To identify the name of the missing substance in the following word equation.

?_EnolasePhosphoenolpyruvate+water

Concept introduction: Glycolysis is the metabolic pathway that breaks down a glucose molecule and converts it into two pyruvate molecules along with the production of two ATP molecules and NADH reduced coenzymes.

The block diagram to represent an overview of glycolysis is as follows:

General, Organic, and Biological Chemistry, Chapter 24, Problem 24.19EP , additional homework tip  2

From the above diagram, it is concluded that in the overall process of glycolysis, two stages are present.

a) Steps 1 to 3 represents a six-carbon stage (C6 stage).

b) Steps 4 to 10 represent a three-carbon stage (C3 stage).

(b)

Expert Solution
Check Mark

Answer to Problem 24.19EP

The complete word equation is as follows:

2Phosphoglycerate_EnolasePhosphoenolpyruvate+water

Explanation of Solution

In step 9,2Phosphoglycerate is dehydrated in the presence of enolase enzymes to give phosphoenolpyruvate. The word equation for the reaction is as follows:

2PhosphoglycerateEnolasePhosphoenolpyruvate+water

Conclusion

In step 9,2Phosphoglycerate is dehydrated in the presence of enolase enzymes to give phosphoenolpyruvate along with water. Therefore, the missing substance is 2Phosphoglycerate.

(c)

Interpretation Introduction

Interpretation: To identify the name of the missing substance in the following word equation.

3Phosphoglycerate?_2Phosphoglycerate

Concept introduction: Glycolysis is the metabolic pathway that breaks down a glucose molecule and converts it into two pyruvate molecules along with the production of two ATP molecules and NADH reduced coenzymes.

The block diagram to represent an overview of glycolysis is as follows:

General, Organic, and Biological Chemistry, Chapter 24, Problem 24.19EP , additional homework tip  3

From the above diagram, it is concluded that in the overall process of glycolysis, two stages are present.

a) Steps 1 to 3 represents a six-carbon stage (C6 stage).

b) Steps 4 to 10 represent a three-carbon stage (C3 stage).

A mutase enzyme catalyzes the isomerization reaction by shifting a functional group from one position to another position within a molecule.

(c)

Expert Solution
Check Mark

Answer to Problem 24.19EP

The complete word equation is as follows:

3PhosphoglyceratePhosphoglyceromutase_2Phosphoglycerate

Explanation of Solution

In step 8, 3Phosphoglycerate is converted to 2Phosphoglycerate. Phosphoglyceromutase enzymes are involved in this reaction. The word equation for the isomerization reaction is as follows:

3PhosphoglyceratePhosphoglyceromutase2Phosphoglycerate

Conclusion

In step 8, 3Phosphoglycerate is isomerized to 2Phosphoglycerate using phosphoglyceromutase enzymes. Therefore, the missing substance is phosphoglyceromutase.

(d)

Interpretation Introduction

Interpretation: To identify the name of the substance in the following word equation.

1,3Biphosphoglycerate+?_Phosphoglycerokinase3phosphoglycerate+ATP

Concept introduction: Glycolysis is the metabolic pathway that breaks down a glucose molecule and converts it into two pyruvate molecules along with the production of two ATP molecules and NADH reduced coenzymes.

The block diagram to represent an overview of glycolysis is as follows:

General, Organic, and Biological Chemistry, Chapter 24, Problem 24.19EP , additional homework tip  4

From the above diagram, it is concluded that in the overall process of glycolysis, two stages are present.

a) Steps 1 to 3 represents a six-carbon stage (C6 stage).

b) Steps 4 to 10 represent a three-carbon stage (C3 stage).

The transfer of a phosphoryl group (PO32) is catalyzed by the kinase enzymes. In the glycolysis process, the phosphate group comes from ATP, ADP or some higher energetic phosphate molecules.

(d)

Expert Solution
Check Mark

Answer to Problem 24.19EP

The complete word equation is as follows:

1,3Biphosphoglycerate+ADP_Phosphoglycerokinase3phosphoglycerate+ATP

Explanation of Solution

The seventh step in the glycolysis process is the phosphorylation of 1,3Biphosphoglycerate using ADP, thus, ADP is converted to ATP. In step 7,1,3biphosphoglycerate is converted to 3phosphoglycerate by phosphoglycerokinase. The word equation for the phosphorylation reaction is as follows:

1,3Biphosphoglycerate+ADPPhosphoglycerokinase3phosphoglycerate+ATP

Conclusion

In step 7, 1,3biphosphoglycerate is phosphorylated by phosphoglycerokinase using ADP to give 3phosphoglycerate along with ATP. Therefore, the missing substance is ADP.

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Chapter 24 Solutions

General, Organic, and Biological Chemistry

Ch. 24.2 - Prob. 6QQCh. 24.2 - Prob. 7QQCh. 24.3 - Prob. 1QQCh. 24.3 - Prob. 2QQCh. 24.3 - Prob. 3QQCh. 24.3 - Prob. 4QQCh. 24.3 - Accumulation of which of the following substances...Ch. 24.4 - Prob. 1QQCh. 24.4 - The net yield of ATP for the complete oxidation of...Ch. 24.4 - Prob. 3QQCh. 24.5 - Prob. 1QQCh. 24.5 - Prob. 2QQCh. 24.5 - Prob. 3QQCh. 24.6 - Prob. 1QQCh. 24.6 - Prob. 2QQCh. 24.6 - Prob. 3QQCh. 24.6 - Which of the following statements about ATP...Ch. 24.6 - Prob. 5QQCh. 24.7 - Prob. 1QQCh. 24.7 - Prob. 2QQCh. 24.8 - Prob. 1QQCh. 24.8 - Prob. 2QQCh. 24.8 - Prob. 3QQCh. 24.9 - Which of the following hormones promotes the...Ch. 24.9 - Which of the following pairs of hormones increases...Ch. 24.10 - Prob. 1QQCh. 24.10 - Prob. 2QQCh. 24.10 - Prob. 3QQCh. 24 - Where does carbohydrate digestion begin in the...Ch. 24 - Very little digestion of carbohydrates occurs in...Ch. 24 - Prob. 24.3EPCh. 24 - Prob. 24.4EPCh. 24 - Prob. 24.5EPCh. 24 - Prob. 24.6EPCh. 24 - Prob. 24.7EPCh. 24 - Prob. 24.8EPCh. 24 - Prob. 24.9EPCh. 24 - Prob. 24.10EPCh. 24 - Prob. 24.11EPCh. 24 - Prob. 24.12EPCh. 24 - Prob. 24.13EPCh. 24 - Prob. 24.14EPCh. 24 - Prob. 24.15EPCh. 24 - Prob. 24.16EPCh. 24 - Prob. 24.17EPCh. 24 - Prob. 24.18EPCh. 24 - Prob. 24.19EPCh. 24 - Prob. 24.20EPCh. 24 - Prob. 24.21EPCh. 24 - Prob. 24.22EPCh. 24 - Prob. 24.23EPCh. 24 - Prob. 24.24EPCh. 24 - Prob. 24.25EPCh. 24 - Prob. 24.26EPCh. 24 - Prob. 24.27EPCh. 24 - Prob. 24.28EPCh. 24 - Prob. 24.29EPCh. 24 - Prob. 24.30EPCh. 24 - Prob. 24.31EPCh. 24 - Prob. 24.32EPCh. 24 - Prob. 24.33EPCh. 24 - Prob. 24.34EPCh. 24 - Prob. 24.35EPCh. 24 - Prob. 24.36EPCh. 24 - Prob. 24.37EPCh. 24 - Prob. 24.38EPCh. 24 - Prob. 24.39EPCh. 24 - Prob. 24.40EPCh. 24 - Prob. 24.41EPCh. 24 - Prob. 24.42EPCh. 24 - Prob. 24.43EPCh. 24 - Prob. 24.44EPCh. 24 - Prob. 24.45EPCh. 24 - Prob. 24.46EPCh. 24 - Prob. 24.47EPCh. 24 - Prob. 24.48EPCh. 24 - Prob. 24.49EPCh. 24 - Prob. 24.50EPCh. 24 - Prob. 24.51EPCh. 24 - Prob. 24.52EPCh. 24 - Prob. 24.53EPCh. 24 - Prob. 24.54EPCh. 24 - Prob. 24.55EPCh. 24 - Prob. 24.56EPCh. 24 - Prob. 24.57EPCh. 24 - Prob. 24.58EPCh. 24 - Prob. 24.59EPCh. 24 - Prob. 24.60EPCh. 24 - Prob. 24.61EPCh. 24 - Prob. 24.62EPCh. 24 - Prob. 24.63EPCh. 24 - Prob. 24.64EPCh. 24 - Prob. 24.65EPCh. 24 - The liver, but not the brain or muscle cells, has...Ch. 24 - Prob. 24.67EPCh. 24 - Prob. 24.68EPCh. 24 - Prob. 24.69EPCh. 24 - Prob. 24.70EPCh. 24 - Prob. 24.71EPCh. 24 - Prob. 24.72EPCh. 24 - Prob. 24.73EPCh. 24 - Prob. 24.74EPCh. 24 - Prob. 24.75EPCh. 24 - Prob. 24.76EPCh. 24 - Prob. 24.77EPCh. 24 - Prob. 24.78EPCh. 24 - Prob. 24.79EPCh. 24 - Prob. 24.80EPCh. 24 - Prob. 24.81EPCh. 24 - Prob. 24.82EPCh. 24 - Prob. 24.83EPCh. 24 - Prob. 24.84EPCh. 24 - Prob. 24.85EPCh. 24 - Prob. 24.86EPCh. 24 - Prob. 24.87EPCh. 24 - Prob. 24.88EPCh. 24 - Prob. 24.89EPCh. 24 - Prob. 24.90EPCh. 24 - Prob. 24.91EPCh. 24 - Prob. 24.92EPCh. 24 - Prob. 24.93EPCh. 24 - Prob. 24.94EPCh. 24 - Prob. 24.95EPCh. 24 - Prob. 24.96EPCh. 24 - Prob. 24.97EPCh. 24 - Prob. 24.98EPCh. 24 - Prob. 24.99EPCh. 24 - Prob. 24.100EPCh. 24 - Prob. 24.101EPCh. 24 - Prob. 24.102EPCh. 24 - Prob. 24.103EPCh. 24 - Prob. 24.104EPCh. 24 - Prob. 24.105EPCh. 24 - Prob. 24.106EPCh. 24 - Prob. 24.107EPCh. 24 - Prob. 24.108EPCh. 24 - Prob. 24.109EPCh. 24 - Prob. 24.110EPCh. 24 - Prob. 24.111EPCh. 24 - Prob. 24.112EPCh. 24 - Prob. 24.113EPCh. 24 - Prob. 24.114EPCh. 24 - Prob. 24.115EPCh. 24 - Compare the biological functions of glucagon and...Ch. 24 - Prob. 24.117EPCh. 24 - Prob. 24.118EP
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