Chapter 23.3, Problem 20R

To determine

To Calculate: The mass of a polymer containing $122$ monomers.

Answer to Problem 20R

The mass of the polymer is $12810\text{ a}\text{.m}\text{.u}$ .

Explanation of Solution

Given data:

Mass of one monomer $=\text{105 a}\text{.m}\text{.u}$

The polymer contains $122$ monomers.

Calculation:

As per the problem,

Polymers consist of repeated units of the same monomer.

Therefore, mass of the polymer is equal to the sum of the mass of all units of monomers.

The polymer contains $122$ monomers.

Now, mass of one monomer $=\text{105 a}\text{.m}\text{.u}$

Therefore, mass of the polymer $=\text{105 a}\text{.m}\text{.u}\times \text{122}=12810\text{ a}\text{.m}\text{.u}$

Conclusion:

The mass of the polymer is $12810\text{ a}\text{.m}\text{.u}$ .