Biochemistry
Biochemistry
9th Edition
ISBN: 9781305961135
Author: Mary K. Campbell, Shawn O. Farrell, Owen M. McDougal
Publisher: Cengage Learning
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Chapter 20, Problem 8RE

MATHEMATICAL Using the information in Table 20.2, calculate Δ G ° ' for the following reaction:

2 Cyt  a a 3   [ oxidized; Fe ( III ) ]   + 2 Cyt  b   [ reduced; Fe ( II ) ]   2 Cyt  a a 3   [ reduced; Fe ( II ) ] + 2 Cyt  b   [ oxidized; Fe ( III ) ]

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Interpretation Introduction

Interpretation:

The standard free energy change for the given biological reaction is to be determined.

Concept introduction:

Oxidation is the addition of an electronegative element or the removal of an electropositive element in a chemical reaction.

Reduction is the addition of an electropositive element or the removal of an electronegative element in a chemical reaction

The chemical reaction in which oxidation process and reduction process takes place and reduction take place simultaneously is called a redox reaction.

The relation between standard free energy change and standard reduction potential for the biological process is shown as follows:

ΔG'=nFE'

Here, ΔG'is standard Gibbs free energy change for a biological process, E'is standard reduction potential, Fis the Faraday’s constant(1F = 96500 J/V . mol e)and n is the transfer of electrons in the half reactions.

Answer to Problem 8RE

Solution: 60.0kJmol1

Explanation of Solution

The half reactions that are paired during the redox reaction are shown below, along with their standard free energy change:

Reaction1: 2Cyt b[Fe(II)] + 2 Cyt c1[Fe(III)] 2Cyt c1[Fe(II)]+2Cytb[Fe(III)] ΔG'=34.7kJmol1

Reaction2: 2 Cyt c1[Fe(II)] + 2 Cyt c[Fe(III)] 2Cyt c[Fe(II)]+2Cyt c1[Fe(III)] ΔG'=5.8kJmol1

Reaction3: 2 Cyt c[Fe(II)] + 2 Cyt (aa3)[Fe(III)] 2Cyt (aa3)[Fe(II)]+2Cyt c[Fe(III)] ΔG'=7.7kJmol1

Reaction4:  2 Cyt (aa3)[Fe(II)]+12O2+2 H+ 2Cyt (aa3)[Fe(III)]+H2O ΔG'=102.3kJmol1

The aim reaction for which the standard free energy is to be calculated is shown as follows:

2Cytaa3[oxidized;Fe(III)]+2Cytb[reduced;Fe(II)]2Cytaa3[reduced;Fe(II)]+2Cytb[oxidized;Fe(III)]

As, the aim reaction can be calculated as follows:

Aim reaction =(Reaction1)+(Reaction2)+(Reaction3)(Reaction4)

Therefore the standard free energy is calculated as follows:

ΔG'=34.7kJmol1+(5.8kJmol1)+(7.7kJmol1)(102.3kJmol1)ΔG'=34.7kJmol15.8kJmol17.7kJmol1+102.3kJmol1ΔG'=+59.9kJmol1ΔG'+60.0kJmol1

Hence, the standard free energy of the given biological reaction will be calculated.

Conclusion

The standard free energy of the given biological reaction is60.0kJmol1.

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Chapter 20 Solutions

Biochemistry

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