Consider this four-factor cross:
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Genetics: Analysis and Principles
- A male plant with genotype AaBBCcDdee was crossed with one heterozygous for all thegenes. (a) what is the probability of getting a pollen with ABcDe genes? (b) of producing anovum with three dominant and two recessive genes? (c) of getting a progeny with samephenotype as the female parent? (d) of progeny with exactly same genotype as the femaleparent? (e) If instead of the above male, the cross was with one heterozygous for all thegenes, what proportion of the offspring will have three dominant phenotypic traits. (f) willbe genotypically like the parents?arrow_forwardIn a trihybrid cross of a tall, purple-flowered pea plant with round seeds (TtPpRr) with a short, white- flowered pea plant with round seeds (ttppRr), what is the probability: A) that a short, white-flowered plant with wrinkled seeds will be produced? B) that a tall, purple-flowered plant with round seeds will be produced? C) that a tall, white-flowered plant with round seeds will be produced?arrow_forwardIf you cross heterozygous spherical (S) yellow (Y) seeded plant with dented(s), green(y) the offsping and the ratio would be: A)F:SsYy, ssyy; ration 1:1B)F: SSYy, Ssyy, ssYy, ssyy; ration 1:1:1:1C)F: SSYy, Ssyy, ssYy,ssyy; ration 1:1:1:1D)F: SsYy, Ssyy, ssYy, ssyy ration 1:1:1:1arrow_forward
- Round (R) seed shape is dominant to wrinkled (r) seed shape in pea plants. If an RR plant is crossed with an rr plant, what is the frequency of phenotypes in the F2 generation? 1)1/4 RR, 1/2 Rr, 1/4 rr 2) All round seeds 3) 3 roundseeds, 1 wrinkled seed 4) All wrinkled seedsarrow_forwardIn corn, the allele f ′ causes floury endosperm and the allele f ″ causes flinty endosperm. In the cross f ′/f ′ ×f ″/f ″, all the progeny endosperms are floury, but, in the reciprocal cross, all the progeny endosperms are flinty. What is a possible explanation? (Check the legend for Figure 2-7.)arrow_forwardIn a certain plant, the seed traits are as follows: Color: white (W) is dominant over yellow (w)Shape: disk (D) is dominant over sphere (d)Seed coat: thick (T) is dominant over thin (t) a) If the parent plant is a triple heterozygote, what is its phenotype? b) Analyzing the phenotypes of the offspring, the alleles of the gametes were determined as: 85 wDt 390 WDT 27 WDt 81 WdT5 wDT 374 wdt 30 wdT 8 Wdt construct a genetic map using the three-point cross.arrow_forward
- Given : The given plant is triploid. Symbol For purple = P For yellow seed = Y For round seed = R Answer 1. The Probability of PpYyRr = 8/64 = 1/8 2. The Probability of PPyyRr = 4/64 = 1/16 3. Probability of at least exhibiting wrinkled seeds = 32/64 = 1/2 4. Probability of at least exhibiting purple flowers = 48/64 = 6/8 = 3/4 QUESTION: Answer the remaining question (5, 6, 7)arrow_forwardWhy is it impossible to cross a green and an albino plant?arrow_forwardIn some plants a red pigment is synthesized from a colorless precursor. The addition of a hydroxyl group to the precursor molecule causes it to become purple. In a cross between two randomly selected purple plants, the following results were obtained. 94 purple 31 red 43 white Q:What are the genotypes of the two random purple plants? R/r; P/p X R/r; P/p R/r; p/p X R/r; p/p r/r; P/p X r/r; P/p r/r; p/p X r/r; p/p R/R; P/P X r/r; p/parrow_forward
- In a certain plant, the seed traits are as follows: Color: white (W) is dominant over yellow (w)Shape: disk (D) is dominant over sphere (d)Seed coat: thick (T) is dominant over thin (t) -If the parent plant is a triple heterozygote, what is its phenotype? Analyzing the phenotypes of the offspring, the alleles of the gametes were determined as: 85 wDt 390 WDT 27 WDt 81 WdT5 wDT 374 wdt 30 wdT 8 Wdt-Try to construct a genetic map using the three-point crossarrow_forwardA cross was made between two pea plants, TtAa and Ttaa, whereT = tall, t = dwarf, A = axial, and a = terminal. What is the probability that the first three offspring will be tall with axial flowers or dwarf with terminal flowers and the fourth offspring will be tall with axial flowers? Discuss what operation(s) (e.g., product rule or binomial expansion equation) you used and in what order they were usedarrow_forwardYou have already localized the genes to the same chromosome by deletion mapping, and now decide that the best way to accomplish the mapping is to conduct two simultaneous three-point testcross experiments. The genes you are investigating are as follows: N = round leaves, n = notched leaves; H = smooth stems, h = hairy stems; R = purple flowers, r = red flowers; B = grey seeds, b = black seeds; and Y = green pods, y = yellow pods. Earlier experiments you have done already established that gene B is in the middle of this gene cluster, so you design both three-point test crosses to include that gene. Cross #1 is designed as RrHhBb x rrhhbb while cross #2 is NnBbYy x nnbbyy. The results of both crosses are given in the table below. Based on the information given, determine the arrangement of these five genes including the position of each allele in the heterozygous fly and the distances between each pair of genes. (Hint: treat each experiment separately, knowing that gene B is in the…arrow_forward
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