Applied Statics and Strength of Materials (6th Edition)
6th Edition
ISBN: 9780133840544
Author: George F. Limbrunner, Craig D'Allaird, Leonard Spiegel
Publisher: PEARSON
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Chapter 2, Problem 2.8CP
Write a program that will calculate the rectangular components of a force. User input is to be the magnitude of the force (lb) and its inclination with the positive X axis, as defined in Figure 2.12 .
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The following concurrent forces are acting on a body in xy plane: A 300 lb pointing up to the right 30 degrees with x axis, 400 lb at 45 degrees with x axis acting up to the left, 200 lb down to the left at 60 degrees with x axis, 150 lb down to the right at 75 degrees with x axis and a 100 lb directly to the right. Determine the resultant force and its direction using graphical and analytical method.
Pls show the solution, formula and free body diagram.
The following concurrent forces are acting on a body in xy plane: A 300 lb pointing up to the right 30 degrees with x axis, 400 lb at 45 degrees with x axis acting up to the left, 200 lb down to the left at 60 degrees with x axis, 150 lb down to the right at 75 degrees with x axis and a 100 lb directly to the right. Determine the resultant force and its direction using graphical and analytical method.
Show solution, formula and the FBD and pls write legible
The drawing shows a rectangular piece of wood. The forces applied to corners B and D have the same magnitude of 20 N and are directed parallel to the long and short sides of the rectangle. The long side of the rectangle is twice as long as the short side. An axis of rotation is shown perpendicular to the plane of the rectangle at its center. A third force (not shown in the drawing) is applied to corner A, directed along the short side of the rectangle (either toward B or away from B), such that the piece of wood is at equilibrium. Find the magnitude and direction of the force applied to corner A.
Chapter 2 Solutions
Applied Statics and Strength of Materials (6th Edition)
Ch. 2 - Find the resultant force for each system of forces...Ch. 2 - Rework Problem 2.1 solving for the resultants...Ch. 2 - Compute the vertical and horizontal components for...Ch. 2 - Compute the vertical and horizontal components for...Ch. 2 - Compute the vertical and horizontal components for...Ch. 2 - The rectangular components of a force are...Ch. 2 - Find the resultant force on the screw eye. One...Ch. 2 - Write a program that will calculate the...Ch. 2 - Write a program that will calculate me magnitude...Ch. 2 - Calculate and display the vertical and horizontal...
Ch. 2 - A plastic barrel containing water is used as an...Ch. 2 - A telephone pole is braced by a guy wire that...Ch. 2 - Compute the vertical and horizontal components for...Ch. 2 - Compute the vertical and horizontal components of...Ch. 2 - Compute the rectangular components parallel and...Ch. 2 - Determine the vertical and horizontal components...Ch. 2 - Find the vertical and horizontal components of...Ch. 2 - An inclined cable is used to pull on a log as...Ch. 2 - In Problem 2.18 , if the log will slide when a...Ch. 2 - A rope is bed to the top of a 10-m flagpole The...Ch. 2 - A rope tow is used to pull skiers up a...Ch. 2 - Determine the slope triangle dimension s so that...Ch. 2 - The crane wheel applies a 9500-lb forte to the...Ch. 2 - The horizontal and vertical components,...Ch. 2 - Calculate the X and Y components of each force...Ch. 2 - Find the resultant of the two force acting on the...Ch. 2 - A drawbar support assembly is shown in the figure....Ch. 2 - The Howe roof truss shown is subjected to wind...Ch. 2 - The release cam mechanism is subjected to the...
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- QI/ A force F acts at the origin in a direction 20 above the positive x- axis. A second force Facts at the origin in a direction of the positive y axis. The resultant force magnitude is 15 units and makes an angle of 65° with the x- axis. Calculate the two forces magnitudes.arrow_forwardTwo forces act on the screw eye shown on figure 7. Determine the magnitude and the directionof the resultant force.arrow_forwardThe sketch shows the top view of a door that has width, L. The small blue circle is hinge. The door is free to rotate about the hinge. All forces have same value, F. The angled forces and F5 are at the middle of the L. (a) Draw the line of action of force for each force on the given diagram. (b) Draw the lever force of each forces shown above. There should be a drawing for each force including the force, its line of action, axis of rotation and finally the lever arm. (c) Write down the torque due to each force using sign convention used in class. Label a force first and then write the torque equation.arrow_forward
- First, write your individual forces here (if you are using trig stuff, the system knows radians): FQ Fp Now, find the sum of the forces in a new vector here: i- The magnitude of the resultant is lbs. The direction of the resultant is degrees.arrow_forwardThree coplanar forces act on a point at a certain magnesium point, the forces which act at the point have the following magnitude and directions 80N force, 0°horizontally to the right, 60N, 110°Anticlock wise from the 80N force and 110N, 225°Anticlock wise from the 80N force. Calculate the graphical method of the magnitude and the direction of the resultant vector, draw the space diagram before the vector diagram?arrow_forwardThe resultant of the concurrent forces in Figure 1-33 is 200 N up to the left at 0, = 60°. Compute the values of F and 0 required to give this resultant. F 500 N 30 240 N Figure 1-33arrow_forward
- Determine the magnitude and direction of the resultant force using parallelogram law of forces for the figure given below.arrow_forwardProblem 6: Values: A = 13 lb 0₁ = 20⁰ 0₂ = 60° Use the figure shown on the right to complete the following steps: a) Express the force as a Cartesian vector. Use basic trig functions to determine the force components. Some textbooks provide equations for this, but it's a waste of time to memorize these, or worse, to apply them without understanding what you're doing. Just break the vector into two right triangles and apply basic trig. Nothing to memorize. Nothing fancy. The leg of one triangle becomes the hypotenuse of the other. b) Specify the coordinate direction angles of the vector. These are referred to in Hibbeler's textbook as a, ß, and y. They are also sometimes referred to as 0, 0y, and 0-. See the figure below for clarification. Use vector equations for this, not trig. That is, once you have the vector components, this is a straightforward calc- no crazy trig or geometry involved. X Ai Z A.KA UA Y B A,j -y N 0₂ 0₁ A yarrow_forwardWe have three forces F1=200g, F2=150g, and F3=300g with their respective angle 0 degree, 60degrees, and 120 degrees. Graph the three forces in one graph.arrow_forward
- 3. Four forces act on a point but only three of them are shown in the figure below. Determine the magnitude and direction of the fourth (missing) force if the magnitude and direction of the four forces is 95.0 lb and points in the first quadrant at an angle of 40° above the x-axis. (Hint: all 4 vectors should be drawn in your FBD.) 70 lb 60° * 60⁰ 50° 50 lb 120 lb/ 8arrow_forwardFor multiple choice, choose the best answer. Show all work: indicate your plan and draw FBD's (Free Body Diagrams), write/label (symbolic) equations (e.g., ZFx = 0) before writing numeric equations, box answers. 2. For the force and geometry shown, determine the moment of force F about point A. 200 mm 30° F=80 N 400 mm 40° 250 mm 300 mm 200 mmarrow_forwardIn the following free body diagram, force F is acting at an angle t from the horizontal, and the force of 800 N is acting at an angle of 50 degrees to the vertical as shown. Find the magnitude of force F and the angle t it makes with the horizontal, if the resultnat force is directed toward the x direction with the magnitude of 1000 N. Show A your work. 50 degrees 800 Narrow_forward
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