Concept explainers
Each diode cut−in voltage in the circuit in Figure P2.59 is 0.7 V. Determine
Figure P2.59
(a).
The values of
Answer to Problem 2.59P
Explanation of Solution
Given Information:
The given circuit is shown below.
Calculation:
For
The input voltage is dropped across the output because the current in the circuit is zero.
(b).
The values of
Answer to Problem 2.59P
Explanation of Solution
Given Information:
The given circuit is shown below.
Calculation:
For
The value of diode current
The modified circuit is:
Applying Kirchhoff’s voltage law:
The value of output voltage
(c).
The values of
Answer to Problem 2.59P
Explanation of Solution
Given Information:
The given circuit is shown below.
Calculation:
Assuming the diodes are in forward bias and in active mode.
Applying Kirchhoff’s current law at output node:
From above calculation diodes D1,D2 are in forward bias active mode but the diode D3 is in cut off mode because the voltage difference between positive and negative terminal is less than 0.7 V. The current through diode D3 is zero.
Hence, the assumption is incorrect.
The modified figure is:
Applying Kirchhoff’s current law at output node:
The diode currents
(d).
The values of
Answer to Problem 2.59P
Explanation of Solution
Given Information:
The given circuit is shown below.
Calculation:
For
Applying Kirchhoff’s current law at output node:
The values of diode currents are:
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Chapter 2 Solutions
Microelectronics: Circuit Analysis and Design
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