Organic And Biological Chemistry
Organic And Biological Chemistry
7th Edition
ISBN: 9781305081079
Author: STOKER, H. Stephen (howard Stephen)
Publisher: Cengage Learning,
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Alkanes and Cycloalkanes
Alkanes are saturated organic compounds which are made up of C and H atoms. Alkanes have the general formula of CnH2n+2. Alkane contains sp3 hybridized carbon atoms with four sigmas (σ) bonds & every hydrogen atom is connected with one of the carbon atom…
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Chapter 2, Problem 2.48EP

(a)

Interpretation Introduction

Interpretation:

For the given molecule, whether cis‑trans isomers exist has to be indicated and if it exists the isomers has to be drawn..

Concept Introduction:

Alkenes are hydrocarbons that contain at least one double bond in it.  There will not be any free rotation of the double bond in alkene.  Hence, cis‑trans isomerism is possible.  The first and foremost condition for the alkene to exhibit cis‑trans isomerism is that the carbon attached in either end of double bond must have different groups attached to it.

A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.

A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.

Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.

Cis‑trans isomers are not constitutional isomers but they are stereoisomers.

(b)

Interpretation Introduction

Interpretation:

For the given molecule, whether cis‑trans isomers exist has to be indicated and if it exists the isomers has to be drawn..

Concept Introduction:

Alkenes are hydrocarbons that contain at least one double bond in it.  There will not be any free rotation of the double bond in alkene.  Hence, cis‑trans isomerism is possible.  The first and foremost condition for the alkene to exhibit cis‑trans isomerism is that the carbon attached in either end of double bond must have different groups attached to it.

A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.

A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.

Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.

Cis‑trans isomers are not constitutional isomers but they are stereoisomers.

(c)

Interpretation Introduction

Interpretation:

For the given molecule, whether cis‑trans isomers exist has to be indicated and if it exists the isomers has to be drawn..

Concept Introduction:

Alkenes are hydrocarbons that contain at least one double bond in it.  There will not be any free rotation of the double bond in alkene.  Hence, cis‑trans isomerism is possible.  The first and foremost condition for the alkene to exhibit cis‑trans isomerism is that the carbon attached in either end of double bond must have different groups attached to it.

A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.

A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.

Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.

Cis‑trans isomers are not constitutional isomers but they are stereoisomers.

(d)

Interpretation Introduction

Interpretation:

For the given molecule, whether cis‑trans isomers exist has to be indicated and if it exists the isomers has to be drawn..

Concept Introduction:

Alkenes are hydrocarbons that contain at least one double bond in it.  There will not be any free rotation of the double bond in alkene.  Hence, cis‑trans isomerism is possible.  The first and foremost condition for the alkene to exhibit cis‑trans isomerism is that the carbon attached in either end of double bond must have different groups attached to it.

A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.

A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.

Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.

Cis‑trans isomers are not constitutional isomers but they are stereoisomers.

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Chapter 2, Problem 2.47EP
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Chapter 2 Solutions

Organic And Biological Chemistry

Ch. 2.1 - Prob. 1QQCh. 2.1 - Prob. 2QQCh. 2.1 - Prob. 3QQCh. 2.2 - Prob. 1QQCh. 2.2 - Prob. 2QQCh. 2.2 - Prob. 3QQCh. 2.2 - Prob. 4QQCh. 2.3 - Prob. 1QQCh. 2.3 - Prob. 2QQCh. 2.3 - Prob. 3QQ
Ch. 2.3 - Prob. 4QQCh. 2.4 - Prob. 1QQCh. 2.4 - Prob. 2QQCh. 2.5 - Prob. 1QQCh. 2.5 - Prob. 2QQCh. 2.5 - Prob. 3QQCh. 2.6 - Prob. 1QQCh. 2.6 - Prob. 2QQCh. 2.6 - Prob. 3QQCh. 2.7 - Prob. 1QQCh. 2.7 - Prob. 2QQCh. 2.7 - Prob. 3QQCh. 2.8 - Prob. 1QQCh. 2.8 - Prob. 2QQCh. 2.9 - Prob. 1QQCh. 2.9 - Prob. 2QQCh. 2.10 - Prob. 1QQCh. 2.10 - Prob. 2QQCh. 2.10 - Prob. 3QQCh. 2.10 - Prob. 4QQCh. 2.10 - Prob. 5QQCh. 2.11 - Prob. 1QQCh. 2.11 - Prob. 2QQCh. 2.11 - Prob. 3QQCh. 2.11 - Prob. 4QQCh. 2.11 - Prob. 5QQCh. 2.12 - Prob. 1QQCh. 2.12 - Prob. 2QQCh. 2.12 - Prob. 3QQCh. 2.12 - Prob. 4QQCh. 2.12 - Prob. 5QQCh. 2.13 - Prob. 1QQCh. 2.13 - Prob. 2QQCh. 2.13 - Prob. 3QQCh. 2.14 - Prob. 1QQCh. 2.14 - Prob. 2QQCh. 2.14 - Prob. 3QQCh. 2.14 - Prob. 4QQCh. 2.15 - Prob. 1QQCh. 2.15 - Prob. 2QQCh. 2.15 - Prob. 3QQCh. 2.15 - Prob. 4QQCh. 2.16 - Prob. 1QQCh. 2.16 - Prob. 2QQCh. 2 - Classify each of the following hydrocarbons as...Ch. 2 - Prob. 2.2EPCh. 2 - Prob. 2.3EPCh. 2 - Prob. 2.4EPCh. 2 - Prob. 2.5EPCh. 2 - Prob. 2.6EPCh. 2 - Prob. 2.7EPCh. 2 - Characterize the physical properties of saturated...Ch. 2 - Prob. 2.9EPCh. 2 - Prob. 2.10EPCh. 2 - Prob. 2.11EPCh. 2 - Prob. 2.12EPCh. 2 - Prob. 2.13EPCh. 2 - Prob. 2.14EPCh. 2 - What is the name of the spatial arrangement for...Ch. 2 - Prob. 2.16EPCh. 2 - Prob. 2.17EPCh. 2 - Prob. 2.18EPCh. 2 - Draw a condensed structural formula for each of...Ch. 2 - Prob. 2.20EPCh. 2 - The following names are incorrect by IUPAC rules....Ch. 2 - The following names are incorrect by IUPAC rules....Ch. 2 - Prob. 2.23EPCh. 2 - Draw a condensed structural formula for each of...Ch. 2 - Prob. 2.25EPCh. 2 - Classify each of the following compounds as...Ch. 2 - Prob. 2.27EPCh. 2 - How many hydrogen atoms are present in a molecule...Ch. 2 - Draw a line-angle structural formula for each of...Ch. 2 - Draw a line-angle structural formula for each of...Ch. 2 - Prob. 2.31EPCh. 2 - Prob. 2.32EPCh. 2 - Prob. 2.33EPCh. 2 - Prob. 2.34EPCh. 2 - Prob. 2.35EPCh. 2 - Prob. 2.36EPCh. 2 - Prob. 2.37EPCh. 2 - Prob. 2.38EPCh. 2 - For each of the following pairs of alkenes,...Ch. 2 - For each of the following pairs of alkenes,...Ch. 2 - Prob. 2.41EPCh. 2 - Prob. 2.42EPCh. 2 - Prob. 2.43EPCh. 2 - Prob. 2.44EPCh. 2 - Prob. 2.45EPCh. 2 - Prob. 2.46EPCh. 2 - For each molecule, indicate whether cistrans...Ch. 2 - Prob. 2.48EPCh. 2 - Prob. 2.49EPCh. 2 - Prob. 2.50EPCh. 2 - Draw a structural formula for each of the...Ch. 2 - Prob. 2.52EPCh. 2 - Prob. 2.53EPCh. 2 - For each of the following molecules, indicate...Ch. 2 - Prob. 2.55EPCh. 2 - Prob. 2.56EPCh. 2 - Prob. 2.57EPCh. 2 - Prob. 2.58EPCh. 2 - Prob. 2.59EPCh. 2 - How many isoprene units are present in a....Ch. 2 - Prob. 2.61EPCh. 2 - Indicate whether each of the following statements...Ch. 2 - Prob. 2.63EPCh. 2 - Prob. 2.64EPCh. 2 - Prob. 2.65EPCh. 2 - Prob. 2.66EPCh. 2 - Prob. 2.67EPCh. 2 - Prob. 2.68EPCh. 2 - Prob. 2.69EPCh. 2 - Prob. 2.70EPCh. 2 - Prob. 2.71EPCh. 2 - Prob. 2.72EPCh. 2 - Prob. 2.73EPCh. 2 - Prob. 2.74EPCh. 2 - Prob. 2.75EPCh. 2 - Prob. 2.76EPCh. 2 - Supply the structural formula of the product in...Ch. 2 - Prob. 2.78EPCh. 2 - Prob. 2.79EPCh. 2 - What reactant would you use to prepare each of the...Ch. 2 - Prob. 2.81EPCh. 2 - Prob. 2.82EPCh. 2 - Prob. 2.83EPCh. 2 - Prob. 2.84EPCh. 2 - Prob. 2.85EPCh. 2 - Prob. 2.86EPCh. 2 - Prob. 2.87EPCh. 2 - Prob. 2.88EPCh. 2 - Prob. 2.89EPCh. 2 - Prob. 2.90EPCh. 2 - Prob. 2.91EPCh. 2 - Prob. 2.92EPCh. 2 - Prob. 2.93EPCh. 2 - Prob. 2.94EPCh. 2 - Prob. 2.95EPCh. 2 - Prob. 2.96EPCh. 2 - Prob. 2.97EPCh. 2 - Prob. 2.98EPCh. 2 - Prob. 2.99EPCh. 2 - Prob. 2.100EPCh. 2 - Prob. 2.101EPCh. 2 - Prob. 2.102EPCh. 2 - Prob. 2.103EPCh. 2 - Prob. 2.104EPCh. 2 - Prob. 2.105EPCh. 2 - Prob. 2.106EPCh. 2 - Prob. 2.107EPCh. 2 - Prob. 2.108EPCh. 2 - Assign each of the compounds in Problem 13-107 an...Ch. 2 - Assign each of the compounds in Problem 13-108 an...Ch. 2 - Prob. 2.111EPCh. 2 - Prob. 2.112EPCh. 2 - Prob. 2.113EPCh. 2 - Prob. 2.114EPCh. 2 - Prob. 2.115EPCh. 2 - Prob. 2.116EPCh. 2 - Prob. 2.117EPCh. 2 - Prob. 2.118EPCh. 2 - Prob. 2.119EPCh. 2 - Prob. 2.120EPCh. 2 - Prob. 2.121EPCh. 2 - Prob. 2.122EPCh. 2 - Prob. 2.123EPCh. 2 - Prob. 2.124EPCh. 2 - Prob. 2.125EPCh. 2 - Prob. 2.126EPCh. 2 - Prob. 2.127EPCh. 2 - Prob. 2.128EPCh. 2 - Prob. 2.129EPCh. 2 - Prob. 2.130EP
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Chapter 4 Alkanes and Cycloalkanes Lesson 2; Author: Linda Hanson;https://www.youtube.com/watch?v=AL_CM_Btef4;License: Standard YouTube License, CC-BY
Chapter 4 Alkanes and Cycloalkanes Lesson 1; Author: Linda Hanson;https://www.youtube.com/watch?v=PPIa6EHJMJw;License: Standard Youtube License