EBK MANUFACTURING PROCESSES FOR ENGINEE
6th Edition
ISBN: 9780134425115
Author: Schmid
Publisher: YUZU
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Chapter 2, Problem 2.46Q
To determine
Whether the offset method is necessary for highly strained material or not.
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A cylindrical brass rod with a minimum tensile strength of 450 MPa, a ductility of at least 13% EL (elongation), and a final diameter of 12.7mm is required. You have in your inventory some 19.0mm diameter brass stock that has been cold worked to 35%. Assuming that the cross section of the rod is still circular after being cold worked, and that brass experiences cracking at 65% CW, describe the necessary working steps in order to achieve the final product. Take the expression for % cold work to be = (Ao - Af)/ Ao x 100%, where Ao and Af are the original and final circular cross-sectional areas of the rod.
(C) A plain sided specimen is subjected to 2 * 107 cycles at the applied stress
range of 100 MPa. Estimate how many further cycles can be applied at a stress
range of 400 MPa before failure is predicted to occur.
(a) Draw two Engineering Stress - Engineering Strain graphs: one
for a ductile metal and one for a brittle metal, marking and
labelling on both graphs the Yield Stress, the Ultimate Tensile
Stress, the Fracture Stress, the region in which necking occurs.
Correctly label all graph axes and give correct units.
Chapter 2 Solutions
EBK MANUFACTURING PROCESSES FOR ENGINEE
Ch. 2 - Prob. 2.1QCh. 2 - Prob. 2.2QCh. 2 - Prob. 2.3QCh. 2 - Prob. 2.4QCh. 2 - Prob. 2.5QCh. 2 - Prob. 2.6QCh. 2 - Prob. 2.7QCh. 2 - Prob. 2.8QCh. 2 - Prob. 2.9QCh. 2 - Prob. 2.10Q
Ch. 2 - Prob. 2.11QCh. 2 - Prob. 2.12QCh. 2 - Prob. 2.13QCh. 2 - Prob. 2.14QCh. 2 - Prob. 2.15QCh. 2 - Prob. 2.16QCh. 2 - Prob. 2.17QCh. 2 - Prob. 2.18QCh. 2 - Prob. 2.19QCh. 2 - Prob. 2.20QCh. 2 - Prob. 2.21QCh. 2 - Prob. 2.22QCh. 2 - Prob. 2.23QCh. 2 - Prob. 2.24QCh. 2 - Prob. 2.25QCh. 2 - Prob. 2.26QCh. 2 - Prob. 2.27QCh. 2 - Prob. 2.28QCh. 2 - Prob. 2.29QCh. 2 - Prob. 2.30QCh. 2 - Prob. 2.31QCh. 2 - Prob. 2.32QCh. 2 - Prob. 2.33QCh. 2 - Prob. 2.34QCh. 2 - Prob. 2.35QCh. 2 - Prob. 2.36QCh. 2 - Prob. 2.37QCh. 2 - Prob. 2.38QCh. 2 - Prob. 2.39QCh. 2 - Prob. 2.40QCh. 2 - Prob. 2.41QCh. 2 - Prob. 2.42QCh. 2 - Prob. 2.43QCh. 2 - Prob. 2.44QCh. 2 - Prob. 2.45QCh. 2 - Prob. 2.46QCh. 2 - Prob. 2.47QCh. 2 - Prob. 2.48QCh. 2 - Prob. 2.49PCh. 2 - Prob. 2.50PCh. 2 - Prob. 2.51PCh. 2 - Prob. 2.52PCh. 2 - Prob. 2.53PCh. 2 - Prob. 2.54PCh. 2 - Prob. 2.55PCh. 2 - Prob. 2.56PCh. 2 - Prob. 2.57PCh. 2 - Prob. 2.58PCh. 2 - Prob. 2.59PCh. 2 - Prob. 2.60PCh. 2 - Prob. 2.61PCh. 2 - Prob. 2.62PCh. 2 - Prob. 2.63PCh. 2 - Prob. 2.64PCh. 2 - Prob. 2.65PCh. 2 - Prob. 2.66PCh. 2 - Prob. 2.67PCh. 2 - Prob. 2.68PCh. 2 - Prob. 2.69PCh. 2 - Prob. 2.70PCh. 2 - Prob. 2.71PCh. 2 - Prob. 2.72PCh. 2 - Prob. 2.73PCh. 2 - Prob. 2.74PCh. 2 - Prob. 2.75PCh. 2 - Prob. 2.76PCh. 2 - Prob. 2.78PCh. 2 - Prob. 2.79PCh. 2 - Prob. 2.80PCh. 2 - Prob. 2.81PCh. 2 - Prob. 2.82PCh. 2 - Prob. 2.83PCh. 2 - Prob. 2.84PCh. 2 - Prob. 2.85PCh. 2 - Prob. 2.86PCh. 2 - Prob. 2.87PCh. 2 - Prob. 2.88PCh. 2 - Prob. 2.89PCh. 2 - Prob. 2.90PCh. 2 - Prob. 2.91PCh. 2 - Prob. 2.92PCh. 2 - Prob. 2.93PCh. 2 - Prob. 2.94PCh. 2 - Prob. 2.95PCh. 2 - Prob. 2.96PCh. 2 - Prob. 2.97PCh. 2 - Prob. 2.98PCh. 2 - Prob. 2.99PCh. 2 - Prob. 2.100PCh. 2 - Prob. 2.101P
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- Describe Castigliano’s Second Theorem?arrow_forwardA 20 foot long x 4 feet wide x ½ inch thick sheet of an aluminum alloy is cold rolled to a thickness of ¼ inch. During the rolling operation the with of the sheet increases by 10%. The strength coefficient (K) and the strain hardening coefficient (n ) for the aluminum alloy are 25,500 psi and 0.3, respectively Calculate the true strain at the end of the rolling process.arrow_forwardwhy use yield strength not tensile strength? You are drawing wire which you want the wire to elongate pernamently, and not return back to original shape .arrow_forward
- With a suitable example explain the difference between True stress-strain and Engineering stress- strain.arrow_forwardWhat is “Necking”? How does it lead to reduction in engineering stress as true stress increases?arrow_forwardA 20 foot long x 4 feet wide x ½ inch thick sheet of an aluminum alloy is cold rolled to a thickness of ¼ inch. During the rolling operation the with of the sheet increases by 10%. The strength coefficient (K) and the strain hardening coefficient (n ) for the aluminum alloy are 25,500 psi and 0.3, respectively. Calculate the length of the sheet after the rolling operation in feet.arrow_forward
- (b) Identify FOUR (4) differences between plane stress and plane strain transformation.arrow_forward- With a suitable example explain the difference between True stress-strain and Engineering stressstrain.arrow_forwardWhen a 3000 kg load is applied to a 10-mm-diameter ball in a Brinell test of a steel,an indentation of 3.1 mm diameter is produced.Estimate the tensile strength of the steel?arrow_forward
- part made from AISI 1212 steel undergoes a 20 percent cold-work operation. (a) Obtain the yield strength and ultimate strength before and after the cold-work operation. Determine the percent increase in each strength. (b) Determine the ratios of ultimate strength to yield strength before and after the cold work operation. What does the result indicate about the change of ductility of the part?arrow_forwardFigure 6.22 shows the tensile engineering stress– strain behavior for a steel alloy. (a) What is the modulus of elasticity? (b) What is the proportional limit? (c) What is the yield strength at a strain offset of 0.002? (d) What is the tensile strength?arrow_forwardExample Problem-2 A cylindrical rod of non cold-worked brass having an initial diameter of 6.4 mm (0.25 in.) is to be cold worked by drawing such that the cross-sectional area is reduced. It is required to have a cold-worked yield strength of at least 345 Mpa (50,000 psi) and a ductility in excess of 20%EL; in addition, a final diameter of 5.1 mm (0.20 in.) is necessary. Describe the solution.arrow_forward
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