Modern Physics For Scientists And Engineers
Modern Physics For Scientists And Engineers
2nd Edition
ISBN: 9781938787751
Author: Taylor, John R. (john Robert), Zafiratos, Chris D., Dubson, Michael Andrew
Publisher: University Science Books,
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Chapter 2, Problem 2.23P
To determine

To Calculate:

The amount of Kinetic energy released in the α decay.

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A 212^Bi (bismuth) nucleus undergoes alpha decay, resulting in a 208^Tl (thallium) nucleus and a 4He (helium) nucleus as per the following reaction: 212^Bi →208^Tl + 4^He The masses of each nucleus is listed in the table below. Given that the bismuth atom was at rest before the reaction, if the resulting thallium nucleus is traveling 3.3 × 105 m/s, how fast is the helium nucleus traveling?
A Neptunium-237 nucleus, initially at rest, decays by emitting an alpha particle. The resulting nucleus is Protactinium-233 and travels to the right with a speed of 1,398 m/s. What is the speed of the alpha particle? The masses of each can be kept in atomic mass units. No need to convert to kilograms. The masses of the Neptunium, Protactinium, and alpha particle are 237, 233, and 4 respectively. Np 237 u v=? Pa 233 u 4 u Give speed, not velocity.
A nuclear reaction releases 9. 00 x 103 J of energy. What was the change in mass? O 5.0 x 10 2 kg O 5.0 x 10 kg O 1.0 x 10- kg O 5.0 x 10 kg
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