Explanation Given: Hyperboloid x 2 + y 2 = z 2 + 1 with z = 0 and z = 1 Key points: • Moment of Inertia is the sum of the products of the mass of the each particle in the body with the square of distance from the axis of rotation Calculation: Consider solid region w inside the hyperboloid x 2 + y 2 = z 2 + 1 with z = 0 and z = 1 Moment of inertia about z − a x i s is ⇒ I = ∭ w ( x 2 + y 2 ) d v

4th Edition

ISBN: 9781319050733

Author: Rogawski

Publisher: MAC HIGHER

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Chapter 16.5, Problem 50E

To determine

To calculate:The moment of inertia $I_{z}$ of the solid region $w$ inside the hyperboloid $x^{2} + y^{2} = z^{2} + 1$

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Chapter 16.5, Problem 49E

Chapter 16.5, Problem 51E

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Chapter 16 Solutions

CALCULUS (CLOTH)

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The moment of inertia I z of the solid region w inside the hyperboloid x 2 + y 2 = z 2 + 1

Solution Summary: The author calculates the moment of inertia I z of the solid region w inside the hyperboloid x 2 + y 2.

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To calculate:The moment of inertia $I_{z}$ of the solid region $w$ inside the hyperboloid $x^{2} + y^{2} = z^{2} + 1$

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Chapter 16 Solutions

The moment of inertia I z of the solid region w inside the hyperboloid x 2 + y 2 = z 2 + 1

Solution Summary: The author calculates the moment of inertia I z of the solid region w inside the hyperboloid x 2 + y 2.

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To calculate:The moment of inertia Iz of the solid region w inside the hyperboloid x2+y2=z2+1

Want to see the full answer?

Chapter 16 Solutions

To calculate:The moment of inertia $I_{z}$ of the solid region $w$ inside the hyperboloid $x^{2} + y^{2} = z^{2} + 1$