Concept explainers
Sulphurous acid, H2SO3, is a weak acid capable of providing two H+ ions.
- (a) What is the pH of a 0.45M solution of H2SO3?
- (b) What is the equilibrium concentration of the sulphate ion SO32−, in the 0.45M solution of H2SO3?
(a)
Interpretation:
The
Concept Introduction:
If a molecule donate only one hydrogen atom then the acid is called a monoprotic acid.
Example:
If each molecule can donate two or more hydrogen ions, the acid is a polyprotic acid.
A diprotic acid, such as sulfuric acid,
Some acids, such as phosphoric acid,
Polyprotic bases:
Can accept more than on proton
Diprotic bases:
Can accept two protons.
Example: Sulphate ion
Answer to Problem 71PS
pH of a 0.45M solution of
Explanation of Solution
Sulfurous acid is a diprotic acid.
From the
Therefore,
Let’s calculate the
Enter the ICE table the concentrations before equilibrium is established, the change that occurs as the reaction proceeds to equilibrium and the concentrations when equilibrium has been achieved.
(b)
Interpretation:
The equilibrium concentration has to be determined for the sulphate ion
Concept Introduction:
Equilibrium constants:
The equilibrium constant is used to quantitative measurement of the strength of the acid and bases in the water.
If a molecule donate only one hydrogen atom then the acid is called a monoprotic acid.
Example:
If each molecule can donate two or more hydrogen ions, the acid is a polyprotic acid.
A diprotic acid, such as sulfuric acid,
Some acids, such as phosphoric acid,
Polyprotic bases:
Can accept more than on proton
Diprotic bases:
Can accept two protons.
Example: Sulphate ion
Answer to Problem 71PS
The equilibrium concentration of the sulphate ion
Explanation of Solution
Enter the ICE table the concentrations before equilibrium is established, the change that occurs as the reaction proceeds to equilibrium and the concentrations when equilibrium has been achieved.
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Chapter 16 Solutions
Chemistry & Chemical Reactivity
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