Applied Statics and Strength of Materials (6th Edition)
6th Edition
ISBN: 9780133840544
Author: George F. Limbrunner, Craig D'Allaird, Leonard Spiegel
Publisher: PEARSON
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Chapter 16, Problem 16.12P
Design simply supported timber beams (S4S) for the following uniformly distributed line loads and spans:
a. eastern white pine, 5.0 kN/m, 7-m span length
b. southern pine, 6.3 kN/m, 8-m span length
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2. Design a timber beam (S4S) made of Douglas fir to support the load shown
below.
500 lbs/ft
Ju
12'-0
Analysis and design of continuous beams:
Q1/ Draw the load pattern for the beams B1&B2, If imposed dead
load equal to (2.5 kN/m?), and live load equal to (4.8 kN/m?),are
applied on the floor ,Assume all beams have the same dimensions and
the beams supports as a simply span? Y. = 24 kN / m' ,all columns are
(400*400) mm
the secondary beam in the middle of span B2?
8m
180mm
B1
5m
300mm
200mm
B2
Design a timber beam of hem-fir (S4S) to support a uniformly distributed line load of 250 Ib/ft on a simply supported span of 6 ft. Deflection is not to exceed span/300.
1. SIMPLE BEAM: UNIFORMLY DISTRIBUTED LOAD
TABLE E.1 U.S. Customary units
R=V
Nominal Size in.
Dressed Size in.
A in.2
Wt. Ib/ft
I, in.4
S, in.
2 x 4
1} × 3}
5.25
1.46
5.36
3.06
V,
x 5
x 7
x 6
8.25
2.29
20.8
7.56
M max (at center)
x 8
10.9
3.02
47.6
13.1
x 10
13.9
3.85
98.9
21.4
M,
Shear
x 11
x 13
x 12
16.9
4.68
178
31.6
Amux (at center).
384EI
x 14
19.9
5.52
291
43.9
M max
x 16
x 15
22.9
6.35
443
58.2
4,
24
Moment
x 18
x 17
25.9
7.17
642
74.5
3 x 4
2} x 3)
8.75
2.42
8.93
5.10
x 5}
x 7
TABLE F.1 U.S. Customary units
x 6
13.8
3.82
34.7
12.6
x 8
18.1
5.04
79.4
21.9
Allowable Stress" (psi)
Modulus of
x 10
x9}
23.1
6.42
165
35.6
Elasticity E
(ksi)
Species
Fc
F,
Fo
F,
x 12
x 11}
28.1
7.81
297
52.7
x 13
x 15
x 17
Douglas fir
1050
550
625
900
180
1700
x 14
33.1
9.20
485
73.2
Southern pine
1250
410
825
1400
175
1700
x 16
38.1…
Chapter 16 Solutions
Applied Statics and Strength of Materials (6th Edition)
Ch. 16 - Prob. 16.1PCh. 16 - A simply supported beam is to support a uniformly...Ch. 16 - Rework Problem 16.1 given a load of 1.0 kip/ft and...Ch. 16 - Select the lightest W shape to support a...Ch. 16 - Select the lightest W shape to support a...Ch. 16 - 16.6 A simply supported beam is to span 15 ft. It...Ch. 16 - 16.7 A simply supported beam is to span 24 ft. It...Ch. 16 - 16.8 Design a timber beam of hem-fir (S4S) to...Ch. 16 - Select simply supported timber beams (S4S) for the...Ch. 16 - 16.10 Select a southern pine (S4S) timber beam for...
Ch. 16 - 16.11 Select simply supported hem-fir (S4S) joists...Ch. 16 - Design simply supported timber beams (S4S) for the...Ch. 16 - For the following computer problems, any...Ch. 16 - 16.16 Select the lightest W shape to support a...Ch. 16 - 16.17 Select the lightest W shape for the beam...Ch. 16 - Select the lightest W shape for the cantilever...Ch. 16 - 16.19 Select the lightest W shape to support a...Ch. 16 - 16.20 Select the lightest W shape for the beams...Ch. 16 - 16.21 The structural steel floor system shown is...Ch. 16 - 16.22 The structural steel framing plan shown...Ch. 16 - 16.23 Select the lightest steel wide-flange...Ch. 16 - 16.24 Select the lightest steel wide-flange...Ch. 16 - 16.25 Design the lightest W-shape beams to support...Ch. 16 - 16.26 In Problem 16.18, assume that the 500 lb/ft...Ch. 16 - 16.27 Select a southern pine (S4S) simply...Ch. 16 - 16.28 A redwood beam is to support a uniformly...Ch. 16 - 16.29 A partial plan view for a residential floor...Ch. 16 - 16.30 For the floor framing of Problem 16.29,...Ch. 16 - 16.31 Select a Douglas fir (S4S) beam for the...Ch. 16 - 16.32 Select southern pine (S4S) simply supported...Ch. 16 - 16.33 Rework Problem 16.32 using joists spaced 12...Ch. 16 - 16.34 Select Douglas fir (S4S) simply supported...Ch. 16 - 16.35 Select southern pine (S4S) simply supported...Ch. 16 - 16.36 A 15-ft-span simply supported hem-fir (S4S)...Ch. 16 - 16.37 Select a timber beam (S4S) of Southern pine...Ch. 16 - 16.38 A series of 14-ft-long Douglas fir (S4S)...Ch. 16 - 16.39 A cantilever beam 3 m long is to be made...Ch. 16 - 16.40 Select an eastern white pine (S4S) beam for...
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- As the same total load becomes evenly distributed over larger portions of a simple span, the maximum bending moment in the beam will Increase Decrease Remain constant No answer text provided.arrow_forwardActivity 1 Calculate the shear force and the maximum bending moment of beams using for the construction bridge and building. An Encastre /Built-in beam has a span of 3 m and carries the loading system shown in figure 1 (a). 40KN 30kN/m 1.8m -1.2m Figure 1(a): Encastre / Built-in In addition, you should be able to calculate the shear force and the maximum bending moment of a cantilever beam, with a hollow cross-section of Dout: 0.2 m, wall thickness of 0.02 m, and the length of 3 (m). The beam is subjected to a point load of 50 kN at its free end as shown in Figure 1 (b). Dout 50KN 3m Figure 1(b): Cantilever beamarrow_forward4. A simply supported beam with a span of 5 m is built with the isolated T-section shown in Fig. (4). The beam is used to support a uniformly distributed dead load (including self-weight) of 20 kN/m and uniformly distributed live load of 25 kN/m. If the simply supported beam is part of floor attached to partition not likely to be damaged by the deflection, check if the deflection in the beam within the permissible limits of ACI318 code? ( Assume 20% of the live load is sustained after 5- years). Given: fc=21 MPa, and f,=420 MPa, and n = 9. 700 mm |75 mm Stirrups #10 5#32 400 mm 300 mm Fig. (4)arrow_forward
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