The two-center orbital picture that describes each of the two weak resonance contributors of 1, 3-butadiene is to be drawn. Concept introduction: Overlap of atomic orbitals (AOs) can be thought of as wave interference. It can be constructive or destructive. Constructive interference increases the electron density between the two nuclei (an antinode) and results in a molecular orbital (MO) of lower energy. The phases of the overlapping orbitals are the same in this case. Destructive interference reduces the electron density between the two nuclei and results in an MO of higher energy. The phases of such AOs are the opposite. Since the electron density between the two nuclei decreases, there is a node (or a nodal plane) between the two atoms. π MOs sometimes extend over three or more atoms. In this case, different combinations of constructive and destructive interference are possible. The overall bonding character and the energy depend on the number of nodes and antinodes. If there are more antinodes than nodes, the overall interaction is bonding, and energy is lowered. If there are more nodes than antinodes, the overall interaction is antibonding, and energy increases.

Question

PAOLLE D 9. А 10. OMe OMe B C CO₂Me CO₂Me A+Y C+W NHCOCH3 W A+X D+Y B+Z N-Ph COMe Y 11 ||| IV V 8. Rank the dienophiles numbered W to Z in order of decreasing reactivity in a typical Diels- Alder reaction. Z Rank the dienes numbered A to D in order of decreasing reactivity in a typical Diels-Alder reaction Arrange the combinations numbered I to V in order of decreasing HOMO-LUMO gap (largest to smallest gap).

Answer 1

Question

Chapter 14, Problem 14.28P

Interpretation Introduction

Interpretation:

The two-center orbital picture that describes each of the two weak resonance contributors of 1, 3-butadiene is to be drawn.

Concept introduction:

Overlap of atomic orbitals (AOs) can be thought of as wave interference. It can be constructive or destructive. Constructive interference increases the electron density between the two nuclei (an antinode) and results in a molecular orbital (MO) of lower energy. The phases of the overlapping orbitals are the same in this case. Destructive interference reduces the electron density between the two nuclei and results in an MO of higher energy. The phases of such AOs are the opposite. Since the electron density between the two nuclei decreases, there is a node (or a nodal plane) between the two atoms.

π MOs sometimes extend over three or more atoms. In this case, different combinations of constructive and destructive interference are possible. The overall bonding character and the energy depend on the number of nodes and antinodes. If there are more antinodes than nodes, the overall interaction is bonding, and energy is lowered. If there are more nodes than antinodes, the overall interaction is antibonding, and energy increases.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Students have asked these similar questions

PAOLLE D 9. А 10. OMe OMe B C CO₂Me CO₂Me A+Y C+W NHCOCH3 W A+X D+Y B+Z N-Ph COMe Y 11 ||| IV V 8. Rank the dienophiles numbered W to Z in order of decreasing reactivity in a typical Diels- Alder reaction. Z Rank the dienes numbered A to D in order of decreasing reactivity in a typical Diels-Alder reaction Arrange the combinations numbered I to V in order of decreasing HOMO-LUMO gap (largest to smallest gap).

app.101edu.co oudy @ 2 X V * UL Week 7: Panopto ||| 3 D E PII $ 4 R Rank these alkyl halides in order of increasing reactivity in an SN2 reaction. F 4x X UL LTU 7-1A F4 HHH % 5 T G 4, CI F5 A 6 4) Y X Question 16 of 24 F6 C|Chegg.com & 7 U F7 ★ A) III < | < || 8 B) || < | < ||| C) ||| < || < | D) || < ||| < | E) | < ||| < || PrtScn 1 FB X + Home ( 9 F9 O ) End 0 D 67 ENG F10 P PgUp Tp S ( D [ * O 6:15 PM 10/18/2022 PgDn + F12 0 SL 3

Select to Draw Os04 (catalytic) NMO OH OH