Study Guide for Stewart's Multivariable Calculus, 8th
8th Edition
ISBN: 9781305271845
Author: Stewart, James
Publisher: Brooks Cole
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Textbook Question
Chapter 12.3, Problem 1PT
For a = 2i + 3j − 4k and b = −i + 2j − k, a · b =
- a) 0
- b) 8
- c) 10
- d) 12
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Chapter 12 Solutions
Study Guide for Stewart's Multivariable Calculus, 8th
Ch. 12.1 - Prob. 1PTCh. 12.1 - Prob. 2PTCh. 12.1 - Prob. 3PTCh. 12.1 - Prob. 4PTCh. 12.1 - Prob. 5PTCh. 12.2 - Prob. 1PTCh. 12.2 - Prob. 2PTCh. 12.2 - Prob. 3PTCh. 12.2 - Prob. 4PTCh. 12.2 - Prob. 5PT
Ch. 12.2 - Prob. 6PTCh. 12.3 - For a = 2i + 3j 4k and b = i + 2j k, a b = a) 0...Ch. 12.3 - Prob. 2PTCh. 12.3 - Prob. 3PTCh. 12.3 - Prob. 4PTCh. 12.3 - Prob. 5PTCh. 12.3 - Prob. 6PTCh. 12.4 - Prob. 1PTCh. 12.4 - Prob. 2PTCh. 12.4 - Prob. 3PTCh. 12.4 - Prob. 4PTCh. 12.4 - Prob. 5PTCh. 12.4 - Prob. 6PTCh. 12.5 - The equation of the line through (4, 10, 8) and...Ch. 12.5 - True or False: These lines are skew:...Ch. 12.5 - The equation of the plane through 7, 2, 3 with...Ch. 12.5 - The equation of the plane formed by the two lines...Ch. 12.5 - The distance from (1, 2, 1) to the plane 6x + 5y +...Ch. 12.5 - A normal vector to the plane 2x + 3y + 6z =20 is:...Ch. 12.6 - Prob. 1PTCh. 12.6 - Prob. 2PTCh. 12.6 - Prob. 3PTCh. 12.6 - The graph at the right has equation: a)...Ch. 12.6 - Prob. 5PTCh. 12.6 - Prob. 6PT
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- Given that 2x3=7. What reason allows the conclusion 2x=10?arrow_forward1. Solve for x.A) 11x + 5 – 4x = 55B) 7 + 8x – 3x +12 = 63C) 45x -19x = 12 +2x 2.Evaluate the expression when: a = -2.3 b = 19.2 A) a2 x 4 + 3bB) 9b2 + 8aC) (8 - 12a) / -bD) 6a3 – (4 x b) 3. Compare the exponents. (<, >, or =) 364 ______________ 11882 ______________ 64126 ______________ 8355 ______________ 253arrow_forward8. Find mMP. (9х- 43), R P (5x + 33) DELLarrow_forward
- Show that (A + B)2 is not equal to A2 + B2 by showing that this is not true with A = 3 and B = 2. Then, show that (C – D)2 is not equal to C2 – D2 by using C = 8 and D = 5.arrow_forward3x Calculate: dx (x² + 2)? 3 + C 4 (x² + 2)² 3 + C x2 + 2 b) 3 + C 4 x2 + 8 3 + C 2x2 +4 d) 1 + C 6 (x² + 2)* Beviewarrow_forwarddx x²V(x² -4) Select one: a, 4x b. Vx2 - 4) + C С. -Vx? - 4) + C 2x d. Vx² - 4) 21 + C 2xarrow_forward
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