Concept explainers
Alcohols are important for
Using your reaction roadmap as a guide, show how to convert 4-methyl-1-pentene into 5-methylhexanenitrile. You must use 4-methyl-1-pentene and sodium cyanide as the source of all carbon atoms in the target molecule. Show all reagents needed and all molecules synthesized along the way.
Want to see the full answer?
Check out a sample textbook solutionChapter 10 Solutions
Organic Chemistry
Additional Science Textbook Solutions
Inorganic Chemistry
Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition) - Standalone book
EBK INTRODUCTION TO CHEMISTRY
Chemistry: A Molecular Approach (4th Edition)
- Acid-catalyzed dehydration of secondary and tertiary alcohols proceeds through an E1 mechanism. The first step is the protonation of the alcohol oxygen to form an oxonium ion. Dehydration of 3-methyl-2-butanol forms one major and two minor organic products. Draw the structures, including hydrogen atoms, of the three organic products of this reaction. н н :бн н Нас. Нас. CHз CH3 ČH3 CH3 3-methyl-2-butanol an oxonium ion Major Product Minor Product Minor Productarrow_forward10) For the reaction between isopropyl 1-propyl (or 'n-propyl') ether and HBr, which type of reaction best matches the expected products? A) Acid-catalyzed dehydration B) Nucleophilic substitution reaction C) Ether cleavage reaction D) Nucleophilic addition-elimination reactionarrow_forwardEsterication is the reaction of a carboxylic acid (RCOOH) with an alcohol (R'OH) to form an ester (RCOOR') with loss of water. Equation [1] is an example of an intermolecular esterication reaction. Equation [2] is an example of an intramolecular esterication reaction; that is, the carboxylic acid and alcohol are contained in the same starting material, forming a cyclic ester as product. The equilibrium constants for both reactions are given. Explain why Keq is different for these two apparently similar reactions.arrow_forward
- The alcohol given below yields three alkene products upon dehydration. Which of the products will be present in the highest quantity?arrow_forwardThe alkene 2-methylbut-2-ene reacts with hydrogen cyanide (HCN) to form the Markovnikov product. What is the preferred IUPAC name of the main product of this reaction. Please can you explain this.arrow_forwardWhat is the slow, rate-determining step, in the acid-catalyzed dehydration of 2- butanol? Loss of a b-hydrogen from the carbocation to form an alkene. Protonation of the alcohol to form an oxonium ion. Loss of water from the oxonium ion to form a carbocation. The simultaneous loss of a B-hydrogen and water from the oxonium ion.arrow_forward
- Predict the major and minor products of the reaction. Name the products using systematic names. CH3CH=CH2+H2O−→−H+ major product: minor product: Predict the organic product of the reaction. Include all hydrogen atoms.arrow_forwardSN2 reaction is an example of a nucleophilic substitution reaction. Imagine that 1-iodobutane reacts with 4-methylheptan-1-ol under basic conditions. Draw the structure of the two reactants.arrow_forwardCompounds X and Y have the formula C6H12- Both X and Y react with one molar equivalent of hydrogen in the presence of a palladium catalyst to form 2-methylpentane. The heat of hydrogenation of X is less than that of Y. X and Y react with HBr to form a mixture of the same bromoalkanes, and they both undergo hydroboration/oxidation to give a mixture of the same alcohols. What is the structure of Y? In cases where there is more than one answer, just draw one. n. n [ ]# ChemDoodleⓇ zaarrow_forward
- H3C CH3 H3C NA C→XT Br Br₂ CH₂Cl₂ H3C Electrophilic addition of bromine, Br₂, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH₂Cl₂. CH3 Br In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions Br CH3 H3C CH3arrow_forward5B In the following reactions, mixtures of alkenes and ethyl ethers are formed. Draw their structures. Explain which is or are likely to be the main product(s) in each reaction. In case of formation of two isomers of alkenes, explain which is formed in greater proportion CH3 CH3 H3C-C H -Br CH3 EtOHarrow_forwardEthers can be prepared by reaction of an alkoxide or phenoxide ion with a primary alkyl halide. Draw the structure of the expected organic product of the reaction of iodomethane with the following alkoxide ion: CH3 H3C O Na You do not have to consider stereochemistry. You do not have to explicitly draw H atoms. • Do not include lone pairs in your answer. They will not be considered in the grading. • Do not include counter-ions, e.g., Na", I, in your answer. орy вste ChemDoodlearrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning