Interpretation:
The equivalent thickness of air layers in millimeters is to be calculated.
Concept Introduction:
The law of heat conduction states that the heat transfer rate through any material is proportional directly to the negative of the temperature gradient and the area of the heat flow.
Here,
For N materials present in series in a wall, the rate of heat transfer is taken same throughout the wall. The heat transfer equation will now become:
Answer to Problem 10.1P
The air layer thickness is calculated as,
Explanation of Solution
Given information:
Thickness of the refractory fireclay brick,
Thickness of the kaolin brick,
Thickness of the steel pipe,
Thin layers of air are between brick and steel.
Fire side refractory temperature,
Temperature of the outside of steel side,
Heat loss from the wall per meter square of the wall,
For the appendix 11, take the thermal conductivity of fireclay brick, kaolin brick, steel plate, and air as:
Let the thickness of air layer be
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Chapter 10 Solutions
Unit Operations of Chemical Engineering
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