Universe
11th Edition
ISBN: 9781319039448
Author: Robert Geller, Roger Freedman, William J. Kaufmann
Publisher: W. H. Freeman
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Chapter 1, Problem 18Q
To determine
The diameter of the Moon in kilometers (km), given that the distance between Earth and Moon is 384000 km and the angle subtended by Moon is
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The table below presents the semi-major axis (a) and Actual orbital period for all of the major planets in the solar system. Cube for each planet the semi-major axis in Astronomical Units. Then take the square root of this number to get the Calculated orbital period of each planet. Fill in the final row of data for each planet.
Table of Data for Kepler’s Third Law:
Table of Data for Kepler’s Third Law:
Planet aau = Semi-Major Axis (AU) Actual Planet Calculated Planet
Period (Yr) Period (Yr)
__________ ______________________ ___________ ________________
Mercury 0.39 0.24
Venus 0.72 0.62
Earth 1.00 1.00
Mars 1.52 1.88
Jupiter…
The angle on the sky between Venus and
the Sun is measured to be 46.3° when
Venus is at greatest eastern elongation.
What is the distance of Venus from the
Sun, measured in AU? Choose the answer
below that most closely matches your
answer.
Select one:
а.
1.763 AU
O b. 0.587 AU
Ос.
0.652 AU
O d. 0.846 AU
Ое.
0.723 AU
Dione, a moon of Saturn, has an orbital radius of 377,400 km, and an
orbital period of about 2.737 Earth days. Find the orbital period of Rhea,
another moon of Saturn, which has an orbital radius of 527,040 km.
Find the period in Earth days. Round to the nearest hundredth. Don't
worry about putting the unit, just put the answer.
Chapter 1 Solutions
Universe
Ch. 1 - Prob. 1CCCh. 1 - Prob. 2CCCh. 1 - Prob. 3CCCh. 1 - Prob. 1QCh. 1 - Prob. 2QCh. 1 - Prob. 3QCh. 1 - Prob. 4QCh. 1 - Prob. 5QCh. 1 - Prob. 6QCh. 1 - Prob. 7Q
Ch. 1 - Prob. 8QCh. 1 - Prob. 9QCh. 1 - Prob. 10QCh. 1 - Prob. 11QCh. 1 - Prob. 12QCh. 1 - Prob. 13QCh. 1 - Prob. 14QCh. 1 - Prob. 15QCh. 1 - Prob. 16QCh. 1 - Prob. 17QCh. 1 - Prob. 18QCh. 1 - Prob. 19QCh. 1 - Prob. 20QCh. 1 - Prob. 21QCh. 1 - Prob. 22QCh. 1 - Prob. 23QCh. 1 - Prob. 24QCh. 1 - Prob. 25QCh. 1 - Prob. 26QCh. 1 - Prob. 27QCh. 1 - Prob. 28QCh. 1 - Prob. 29QCh. 1 - Prob. 30QCh. 1 - Prob. 31QCh. 1 - Prob. 32QCh. 1 - Prob. 33QCh. 1 - Prob. 34QCh. 1 - Prob. 35QCh. 1 - Prob. 36QCh. 1 - Prob. 37QCh. 1 - Prob. 38QCh. 1 - Prob. 39QCh. 1 - Prob. 40QCh. 1 - Prob. 41QCh. 1 - Prob. 42QCh. 1 - Prob. 43QCh. 1 - Prob. 44Q
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- What is the angular diameter of Jupiter as seen from Callisto? From Amalthea? Relevant data can be found in Celestial Profile 7 and Appendix Table A-11. (Hint: Use the small-angle formula in Reasoning with Numbers 3-1.)arrow_forward1. The diameter of the Sun is equal to 1.392 × 10⁹ m, and the distance from the Sun to Saturn is equal to 9.5 AU. Suppose you want to build an exact scale model of the solar system, and you are using a volleyball with average diameter of 21 cm to represent the Sun. a) In your scale model, how far away would Saturn be from the Sun? Give your answer in meters. b) The actual diameter of Saturn is 116,460 km. What would be Saturn's diameter in your scale model? Give your answer in centimeters.arrow_forwardShow your complete and detailed solution. Round off your answers to 4 decimal digits and box your final answers.arrow_forward
- I. Directions: Complete the given table by finding the ratio of the planet's time of revolution to its radius. Average Radius of Orbit Times of Planet R3 T2 T?/R3 Revolution Mercury 5.7869 x 1010 7.605 x 106 Venus 1.081 x 1011 1.941 x 107 Earth 1.496 x 1011 3.156 x 107 1. What pattern do you observe in the last column of data? Which law of Kepler's does this seem to support? II. Solve the given problems. Write your solution on the space provided before each number. 1. You wish to put a 1000-kg satellite into a circular orbit 300 km above the earth's surface. Find the following: a) Speed b) Period c) Radial Acceleration Given: Unknown: Formula: Solution: Answer: Given: Unknown: Formula: Solution: Answer: Given: Unknown: Formula: Solution: Answer:arrow_forwardFrom Earth, the angular size of the Moon is 0.5 degree. The distance between the Earth and the Moon is 384,400 km. Use the small-angle formula to find the size of the Moon. Compare the number to the distance of the Moon given previously. It is consistent?arrow_forwardWe need to create a scale model of the solar system (by shrinking the sun down to the size of a basketball or ~30cm). First, we will need to scale down actual solar system dimensions (planet diameters and average orbital radiuses) by converting our units. There are two blank spaces in the table below. We will effectively fill in the missing data in the next set of questions. Use the example below to help you. Example: What is the scaled diameter of Mercury if the Sun is scaled to the size of a basketball (30 cm)? The actual diameter of Mercury is 4879 km The Sun's diameter is 1392000 km If the Sun is to be reduced to the size of a basketball, then the conversion we need for this equation will be: 30cm1392000km Here is how we run the conversion: 4879km×30cm1392000km=0.105cm or 0.11cm if we were to round our answer. This means that if the sun in our model is the size of a basketball, Mercury is the size of a grain of sand. We can also see by looking at the table, that we would…arrow_forward
- The moon is about 3.8 × 10^5 km from Earth. How many centimeters is this? One km = 100,000 cm. Write your answer in scientific notationarrow_forwardLook at Appendix F and Appendix G and indicate the moon with a diameter that is the largest fraction of the diameter of the planet or dwarf planet it orbits.arrow_forwardBy what factor is the full moon brighter than Venus at its brightest? (Hint: Refer to Figure 2-6.)arrow_forward
- The radius of Mars is about 3400 km, and its moons Phobos and Deimos orbit 9600 km and 23,500 km from the center of the planet. Design a model in which Mars is 5 in. in radius. How far away from the center of the planet would the two moons orbit?arrow_forwardThe diameter of Earth across the equator is 7928 miles. If a mile equals 1.609 km. what is Earths diameter in kilometers? In centimeters?arrow_forwardGalileos telescope showed him that Venus has a large angular diameter (61 arc seconds) when it is a crescent and a small angular diameter (10 arc seconds) when it is nearly full. Use the small-angle formula to find the ratio of its maximum to minimum distance from Earth. Is this ratio compatible with the Ptolemaic universe shown in Figure 3b of the Chapter 4 Concept Art: An Ancient Model of the Universe?arrow_forward
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