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- Internet protocol version 6 (IPV6) has been introduced to replace the previous version (IPV4), Which of the following best describes a benefit of IPV6 over IPV4? A IPV6 addresses are shorter than IPV4 addresses, which allows for faster routing of packets. B IPV6 allows for a greater number of addresses than IPV4, which allows more devices to be connected to the Internet. IPV6 eliminates the use of hierarchy in addressing, making addresses easier to use. D IPV6 allows users to bypass older security protocols so that data can be sent peer-to-peer without the use of routers.Internet protocol version 4 ( IPV4 ) Represents each IP address as a 32-bit binary number. Internet protocol version 6 ( IPV6 ) represents each IP adress as a 128-bit binary number. WHich of the following best describes the result of using 128-bit addresses instead of 32-bit adresses- 4 times as many address are available- 96 times as many addresses are available - 2^4 times as many adresses are avialabe- 2^96 times as many adresses are available• IPV6 addresses use 128 bits to represent an address which includes bits to be used for subnetting. The second half of the address (least significant 64 bits) is always used for hosts only. Therefore, there is no compromise if we subnet the network. Use the Figure below to Create five subnets using route prefix 2001:db:acad::/48 (1 Marks) Routing Prefix Subnet ID Interface ID 48 Bits 16 Bits 64 Bits
- Explain CIDR IP allocation technique with IP Block 192.168.1.0/24. A network of size 248 computers needs to be divided into four network segments of 126, 62, 30 & 30 computers.For the network shown in below which has an address 192.168.45.2:Find and apply a valid IP range address for each component within the network by using variable length subnetting mask of each host for the * .LAN/WAN environments 30 hosts Network B 20 hosts Network A= Your first name Network C FO/O FO/O Network B=Your middle name Network C= Your last name Lab_D Lab E 2 hosts Network F Network D=Your first name * Network E=Your middle name * Network F=Your last name * Lab_A Lab_B 2 hosts Network G= Same name FO/O 6 hosts Network D FO/O 14 hosts Network A Network H Network H= Same name 2 hosts Network GNetwork Address 172.85.26.0/23 Chippendale LAN 12 Hosts Chippendale Ultimo LAN Glebe LAN 45 Hosts 85 Hosts Ultimo City Glebe City/Glebe LAN 210 Hosts Given the following information and diagram and the IP address 172.85.26.0/23, use VLSM addressing to assign IP addresses for different subnets. Complete the Table with the Network Address and Host Address for different LANS. All host addresses will be the 8th host address in each subnet. Complete the Table with IP address using 'xxx.xxx.XXx.Xxx' without prefix. For example: 192.168.10.15 for IP address rather than 192.168.10.15/24. Host Network Network Address Host Address Requirement 45 Ultimo LAN 12 Chippendale LAN 210 City/Glebe LAN 85 Glebe LAN
- 12 IKT204-G H21, IP and subnet Suppose an ISP owns the block of IPV4 addresses of the form 105. 16.80.0/23. Suppose it wants to create a total of five sub-nets (SN) from this block, by first dividing the address block into four sub-nets and then dividing the last sub-net into two so that the first three blocks have the same number of IP addresses and the last last two blocks have the same number of IP addresses. What are the prefixes (of the form a.b.c.d/x) for the five sub-nets in increasing order? SN1: 105. 16. SN2: 105. 16. SN3. 105 16. SN4: 105. 16. SN5. 105 16. How many bits constitutes the host portion of the prefixes created for SN1, SN2 and SN3? bits How many hosts may be assigned an IP address within SN4 and SN5? hostsSubnetting IP Networks - Given the address block 192.168.30.0/24, create an IP addressing scheme that would allow for 2 subnets with 126 host IP addresses per subnet. Compute for the first two subnets onlyIPV4 is a Connection oriented Protocol. * False True Broadcast is the process of sending a packet from one host to a selected group of hosts. * False True The prefix length is the number of bits in the address that gives the Host portion. " False True The metric is used to decide which route appears on the routing table. * True False The throughput value is greater than The Bandwidth Value. * True False O O O O
- An ISP is granted a block of addresses starting with 130.100.0.0/16. The ISP needs to distribute these addresses to 4 large companies. Each company requires 1024 IP addresses. Write the address ranges for these companies into the following table with /n notation. Company First address Last address 1 2 3 4Q. In classful addressing, an IP address 123.23.156.4 belongs to class format.Write a Java TCP Client-Server Program for Currency Converter as shown below. () CLIENT SERVER IP Address: 128.36.69.6 Domain Name. CurrencyConveret Port : 2834 NOTE Server Details are in the above figure > Client-Server communicates continuously until the Client send Bye to the Server NOTE: 1 SAR = 0.26 USD (US Dollar) 1 SAR = 0.24 EUR (Euro) 1 SAR = 0.20 GBP (British Pound) 1 SAR = 1.73 CNY (Chines Yuan) Sample Output: Client From Server Present Currency Rates: 1 SAR = 0.26 USD (US Dollar) 1 SAR = 0.24 EUR (Euro) 1 SAR = 0.20 GBP (British Pound) 1 SAR = 1.73 CNY (Chines Yuan) Server Server Waiting for the Cline to be Connected... CONECTION ESTABLISHED Received From Client : 10 SAR Received From Client: BYE Enter currency in SAR or BYE to EXIT: 10 Received from Server : 10 SAR = 2.6 USD (US Dollar) 10 SAR = 2.4 EUR (Euro) 10 SAR = 2.0 GBP (British Pound) 10 SAR = 17.3 CNY (Chines Yuan) Enter currency in SAR : BYE Received from Server: Thank You For Using My Program Client DISCONNECTED