nternet protocol version 4 ( IPV4 ) Represents each IP address as a 32-bit binary number. Internet protocol version 6 ( IPV6 ) represents each IP adress as a 128-bit binary number. WHich of the following best describes the result of using 128-bit addresses instead of 32-bit adresses
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Internet protocol version 4 ( IPV4 ) Represents each IP address as a 32-bit binary number. Internet protocol version 6 ( IPV6 ) represents each IP adress as a 128-bit binary number. WHich of the following best describes the result of using 128-bit addresses instead of 32-bit adresses
- 4 times as many address are available
- 96 times as many addresses are available
- 2^4 times as many adresses are avialabe
- 2^96 times as many adresses are available
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- In classful addressing, the IP address space is divided into 5 classes. Indicate the classes of each of the following addresses expressed in binary. Indicate how the class was identified. 3.1.1 00000001 00001011 00001011 11101111 3.1.2 11000001 10000011 00011011 11111111 3.1.3 10100111 11011011 10001011 01101111 3.1.4 11110011 10011011 11111011 00001111• IPV6 addresses use 128 bits to represent an address which includes bits to be used for subnetting. The second half of the address (least significant 64 bits) is always used for hosts only. Therefore, there is no compromise if we subnet the network. Use the Figure below to Create five subnets using route prefix 2001:db:acad::/48 (1 Marks) Routing Prefix Subnet ID Interface ID 48 Bits 16 Bits 64 BitsInternet protocol version 6 (IPV6) has been introduced to replace the previous version (IPV4), Which of the following best describes a benefit of IPV6 over IPV4? A IPV6 addresses are shorter than IPV4 addresses, which allows for faster routing of packets. B IPV6 allows for a greater number of addresses than IPV4, which allows more devices to be connected to the Internet. IPV6 eliminates the use of hierarchy in addressing, making addresses easier to use. D IPV6 allows users to bypass older security protocols so that data can be sent peer-to-peer without the use of routers.
- SUBNET ADDRESSING Consider the router and the two attached subnets below (A and B). The number of hosts is also shown below. The subnets share the 23 high-order bits of the address space: 144.145.110.0/23 : A 175 hosts QUESTION 2 OF 10 Answer How many hosts can there be in this address space? 144.145.110.0/23 B Assign subnet addresses to each of the subnets (A and B) so that the amount of address space assigned is minimal, and at the same time leaving the largest possible contiguous address space available for assignment if a new subnet were to be added. Then answer the questions below. 84 hosts6.) Every computer or internet-connected device has an IP address. (a) Originally IP addresses consisted of 32 binary digits, known as bits, each of which can be 0 or 1. How many such IP addresses are possible? (b) As all the available IP addresses were getting used up, a new system was devised with 128 bits. How many IP addresses are possible under this new system?Answer the following questions based on the concept of IPV6 Addressing Valid / If invalid, give your S# IPV6 Address Invalid comment а. 1200:0000:AB00:1234:0000:2552:7777:1313 b. ABCD:2673:ABCD:EFAB:1234:5678:9ABC:7362 с. 1200::AB00:1234::2552:7777:1313 d. FFFF:AAAA:BBBB:CCCC:DDDD:EEEE:FFFF:1111 Apply Only Rule 2 е. 1000:0001:0001:1000:0001:1000:0001:0000 f. 91CA:DED3:ABC0:2F3B:02AA:0CFF:FD28:9DDA Apply only Rule 1 g. FC00:0000:0000:0000:8E00:1275:0000:0084 h. 2000:0000:0000:0000:0000:ABCD:0000:0025
- Answer the following: a) Rewrite the given IPv4 address using dotted-decimal notation and find the class. 01011110 10110000 01110101 00010101 b) Rewrite the given IPv4 address in binary representation and find the class.SUBNET ADDRESSING Consider the router and the two attached subnets below (A and B). The number of hosts is also shown below. The subnets share the 23 high-order bits of the address space: 144.145.110.0/23 175 hosts QUESTION 3 OF 10 A Answer What is the subnet address of subnet A? (CIDR notation) 144,145.110.0/23 Assign subnet addresses to each of the subnets (A and B) so that the amount of address space assigned is minimal, and at the same time leaving the largest possible contiguous address space available for assignment if a new subnet were to be added. Then answer the questions below. B 84 hostsNetwork Address 172.85.26.0/23 Chippendale LAN 12 Hosts Chippendale Ultimo LAN Glebe LAN 45 Hosts 85 Hosts Ultimo City Glebe City/Glebe LAN 210 Hosts Given the following information and diagram and the IP address 172.85.26.0/23, use VLSM addressing to assign IP addresses for different subnets. Complete the Table with the Network Address and Host Address for different LANS. All host addresses will be the 8th host address in each subnet. Complete the Table with IP address using 'xxx.xxx.XXx.Xxx' without prefix. For example: 192.168.10.15 for IP address rather than 192.168.10.15/24. Host Network Network Address Host Address Requirement 45 Ultimo LAN 12 Chippendale LAN 210 City/Glebe LAN 85 Glebe LAN
- 13 In the IPV4 addressing format, the number of networks allowed under Class C addresses is 2^7 2^24 2^14 2^21Cisco Router A Network with id: 192.168.0.0 and subnet mask 255.255.0.0 is given to you to split it in such a way that the following classrooms are given adequate number of IPs based on their needs. Each classroom will occupy its own subnet. The following information for each subnet must be included: Subnet ID CIDR Subnet Mask First IP usable in the subnet Last IP usable in the subnet Broadcast IP Address for the subnet Classroom1: 8 PCsClassroom2: 400PC and 4 PrinterClassroom 3: 2 PCsClassroom4: 62 PCs and a ServerClassroom5: 24PCs1) Show the shortest (abbreviated) form of the following IPv6 address: a. 2340:0000:006B:0000:0000: 0000:1328:0000 b. 2001:00BD:3C00:0015:0000:0000:1A20:002B C. 0010:0000:3003:0000:0000:0001:0000:0123