ST975 individuals iri eacH pnd Chocolate A: 68% of individuals had a blood pressure reading of values m the above to (117-3.38) (117+3.38) 95% of individuals had a blood pressure reading of_ *+2 standard deviations, or twice the reported value to (117 – 6.76) (117+ 6.76) -se the alues for Locolafeb om the ple a bove Chocolate B: 68% of individuals had a blood pressure reading of to 95% of individuals had a blood pressure reading of to Has your confidence in the effectiveness of Chocolate A and Chocolate B increased or decreased now that you know the standard deviation values (as compared to just knowing the average results)? Explain your reasoning below:

Biomedical Instrumentation Systems
1st Edition
ISBN:9781133478294
Author:Chatterjee
Publisher:Chatterjee
Chapter9: Instrumentation In Blood Circulation
Section: Chapter Questions
Problem 4P
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100%
DARK
DARK
CHOCOLATE A
CHOCOLATE B
Average systolic
reading (mmHg)
117
110
68% of area
Calculated value of
95% of area
"1" Standard.Dev.
+ 3.38
+ 7.97
(mmHg)
99.7% of area
-3
-2
-1
For normally distributed data:
68% of the individual data values are within + "1" standard deviation of the mean.
95% of the individual data values are within + "2" standard deviations of the mean
99% of the individual data values are within + "3" standard deviations of the mean
The values listed in the table above are for + "1" standard deviation. Add and subtract these
0thb values to and from the sample mean to gain a better appreciation for the blood pressures of the
09to975 individuals in each study.
811
values
from the
table
above
to
Chocolate A: 68% of individuals had a blood pressure reading of
(117 – 3.38)
(117 + 3.38)
95% of individuals had a blood pressure reading of
*+2 standard deviations, or twice the reported value
to
(117- 6.76)
(117 + 6.76)
use the
values for tChocolate B: 68% of individuals had a blood pressure reading of
Chocolafed
from the
table above)
to
to
95% of individuals had a blood pressure reading of
Has your confidence in the effectiveness of Chocolate A and Chocolate B increased or
decreased now that you know the standard deviation values (as compared to just knowing the
average results)? Explain vour reasoning below:
Transcribed Image Text:DARK DARK CHOCOLATE A CHOCOLATE B Average systolic reading (mmHg) 117 110 68% of area Calculated value of 95% of area "1" Standard.Dev. + 3.38 + 7.97 (mmHg) 99.7% of area -3 -2 -1 For normally distributed data: 68% of the individual data values are within + "1" standard deviation of the mean. 95% of the individual data values are within + "2" standard deviations of the mean 99% of the individual data values are within + "3" standard deviations of the mean The values listed in the table above are for + "1" standard deviation. Add and subtract these 0thb values to and from the sample mean to gain a better appreciation for the blood pressures of the 09to975 individuals in each study. 811 values from the table above to Chocolate A: 68% of individuals had a blood pressure reading of (117 – 3.38) (117 + 3.38) 95% of individuals had a blood pressure reading of *+2 standard deviations, or twice the reported value to (117- 6.76) (117 + 6.76) use the values for tChocolate B: 68% of individuals had a blood pressure reading of Chocolafed from the table above) to to 95% of individuals had a blood pressure reading of Has your confidence in the effectiveness of Chocolate A and Chocolate B increased or decreased now that you know the standard deviation values (as compared to just knowing the average results)? Explain vour reasoning below:
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