Question 2 The results of a standard compaction test on a soil (G; = 2.7) are as shown in the table below. w(%) xkN/m³) 16.9 6.8 8.1 9.8 11.5 13.2 15 17 18.5 19.5 20.5 20.1 19.2 18 (a) Using excel, plot the compaction curve. Submit your excel file with your exam solution (b) Plot the ZAV curve for the appropriate water content and dry density range (c) Construct the 80 % and 90% saturation lines (d) Determine the maximum dry unit weight and optimum water content (e) Determine the degree of saturation at the maximum dry density
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- The following are the results of a sieve analysis: a. Determine the percent finer than each sieve and plot a grain-size distributioncurve. b. Determine D10, D30, and D60from the grain-size distribution curve. c. Calculate the Cu and Cc Please kindly solve a, b and c... Help me urgent Thank youSituation 3. Following are the results of a sieve analysis. Determine: a. Cu b. Cc c. So Sieve No. 4 6 10 20 40 60 100 200 Pan Diameter (mm) 4.760 2.380 2.000 0.840 0.420 0.250 0.149 0.074 Soil Sample Mass Retained (g) 100 180 86 160 105 134 110 65 45Question 3 A sieve analysis was performed Sieve # 4 10 20 40 100 200 Pan Opening size (mm) 4.75 2 0.85 0.425 0.15 0.075 % Finer 80% For the soil passing # 40 sieve, Atterberg limits were measured as follows: Plastic Limit=29 and Liquid Limit = 36. (a) Fill the blanks in the table. (b) Plot the grain size distribution curve on the following semi-log graph. 100% 60% 40% 20% on a soil sample and the results are given below. Mass of soil retained (g) 0 43.4 80.6 124 186 124 62 0% 10.000 % Retained 1.000 E% Retained 0.100 % Finer 0.010 Grain Size (mm) (c) Extract the percentages of gravel, sand, and fine-grained soil (silt and clay). (d) Determine (1) the effective size (D10), (11) the Uniformity Coefficient (Cu), and (iii) the Coefficient of Curvature (Cc).
- 0 10 16 20 30 40 Liquid limit 50 60 70 80 90 100 0 10- CL-ML 20 Plasticity index 30 J A-line PI = 0.73(LL - 20) 40- U-line PI = 0.9(LL - 8) 70 7 Table 5.2 Unified Soil Classification System (Based on Material Passing 76.2-mm Sieve) Criteria for assigning group symbols O Gravels More than 50% of coarve fraction retained on No. 4 sieve Sands 50% or more of coerse fraction passes No. 4 sieve Coarse-grained soils More than 50% of retained on No. 200 sieve Fine-grained soils 50% or more passes No. 200 sieve Silts and clays Liquid limit less than 50 Silts and clays Liquid limit 50 or more Clean Gravels Less than 5% fines Gravels with Fines More than 12% fines Clean Sands Less than 5% fines Sands with Fines More than 12% fines Inorganic Organic Inorganic Organic C, 4 and 1 c, s 3 C 3r PI 7 and plots on or above "A" line (Figure 5.3) C = 6 and 1 c, ≤ 3 C6 and/or C, 3º Pl 7 and plots on or above "A" line (Figure 5.3) Pl> 7 and plots on or above "A" line (Figure 5.3 PI < 4 or plots below "A"…Problem A: For questions 1 to 7. In the given results of the sieve analysis of a soil. Calculate the following; U.S. Opening Mass Sieve (mm) Retained, grams 4 4.75 10 2.00 21.6 20 0.850 49.50 40 0.425 102.60 60 0.250 89.10 100 0.150 95.60 200 0.075 60.4 Pan 31.2 Sum 1) For the problem above the most probable value for D10=. a) 0.15 mm 2) For D30 =_ a) 0.17 mm 3) For Dso = ? a) 0.27 mm 4) The Uniformity coefficient will be ? a) 4.56 5) The Coefficient of Gradation is? a) 0.90 6) The particle size distribution curve is what type? a) Gap-graded 7) Using the AASHTO system what is the percentage of sand? a) 6.90 b) 0.25 mm c) 0.67 mm d) 0.09 mm b) 0.27 mm c) 0.185 mm d) 0.03 mm b) 0.41mm c) 1.05 mm d) 0.21 mm b) 4.78 c) 3.98 d) 4.21 b) 0.93 c) 0.96 d) 1.15 b) Poorly Graded c) Well-graded b) 4.88 c) 72.90 d) 88.30Determine: 1. The percent finer in Sieve # 20 2. The percent finer in Sieve # 80 3. D60from the grain-size distribution curve 4. D30from the grain-size distribution curve 5. D10from the grain-size distribution curve 6. The coefficient of gradation 7. The uniformity coefficient Please answer this asap. For upvote. Thank you very much
- The table below shows the lab result of the sieve analysis of a soil sample Diameter (mm) 4.750 Percent Passing, % 100 2.000 94.5 0.850 86.3 0.425 74.1 0.250 54.9 0.180 38.1 0.150 9.3 0.075 1.7 a. Calculate the coefficient of gradation of the soil sample. Use logarithmic interpolation b. Classify the soil according to USCS5. The results of a particle size analysis of a soil are given in the following table. The Atterberg limit tests yielded LL=62, PL = 20. Sieve Opening (mm) Percent Coarser by Weight Sieve No. 4.75 5.1 10 2.00 10.0 20 0.85 0.425 40.7 40 70.2 84.8 90.5 60 0.25 100 0.15 200 Pan 0.075 100 a) Draw the gradation curve for this soil b) Determine the uniformity coefficient and the coefficient of curvature c) Classify the soil using USCS and ASSHTO d) Rate this soil as a subgrade for highway constructionThe following data are the results of a sieve analysis. Detemine the percentage retained on sieve #200. Mass of soil Sieve no. Opening retained (mm) on each sieve 4 4.75 10 2 18.5 20 0.85 53.2 40 0.425 90.5 60 0.25 81.8 100 0.15 92.2 200 0.075 58.5 Pan 26.5 Select one: а. 94 b. 58 c. none of the choices d. 27 е. 38
- 200 pan 44 22Repeat Problem 2.4 with the following data. 2.4 The following are the results of a sieve analysis. a. Determine the percent finer than each sieve and plot a grain-size distribution curve. b. Determine D10, D30, and D60 for each soil. c. Calculate the uniformity coefficient Cu. d. Calculate the coefficient of gradation Cc.Based on the compaction curve shown in Figure A (below), choose the appropriate combination for each parameter Av = (i) Av = (ii) Av = 10% (iii) Sr = (iv) O i = 5%; ii = 12%; iii = OMC; iv = 95% O i = 7%; ii = 12%; iii = MDD; iv = 100% %3D O i = 0%; ii = 6%; iii = MDD; iv = 100% %3D %3D O i = 0%; ii = 7%; iii = OMC; iv = 95% %3D