Q4/B/ The stress- strain curve for four materials are shown in figure below. Which material (A/B/C/D) has с 1- The least modulus of elasticity 2- The strongest and stiffest B 3- Most brittle 4- Most ductile 5- Highest yield stress D 6- Lowest Yield stress 7- Highest UTS 8- Lowest UTS Stress Strain

Q4/B/ The stress- strain curve for four materials are shown in figure below. Which material (A/B/C/D) has с 1- The least modulus of elasticity 2- The strongest and stiffest B 3- Most brittle 4- Most ductile 5- Highest yield stress D 6- Lowest Yield stress 7- Highest UTS 8- Lowest UTS Stress Strain

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter1: Tension, Compression, And Shear

Section: Chapter Questions

Problem 1.6.7P: A wine of length L = 4 ft and diameter d = 0.125 in. is stretched by tensile forces P = 600 lb. The...

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The stress-strain curve for four materials are shown in figure below. Which material (A/B/C/D) has 1- The least modulus of elasticity C 2- The strongest and stiffest B 3- Most brittle 4- Most ductile 5- Highest yield stress D 6- Lowest Yield stress 7- Highest UTS 8- Lowest UTS Stress Strain
Sketch a representative stress-strain digrama for a ductile material showing the following on it (label the axis and provid units). 1- YIELD STRENGTH. 2- TENSILE STRENGTH. 3- FRACTURE POINT. 4- HARDENING PART. 5- SOFTENING PART. 6- A METHOD TO CALCULATE THE STIFFNESS. 7- A METHOD TO CALCULATE THE DUCTILITY.
4. The maximum stress a human tendon can withstand is estimated to be 1200 MPa. If you were to test it for rupture what load cell you should use (25ON or 5kN) what problems may occur if you select an incorrect load cell. 5. The figure below is a J-shaped (or concave upward) stress-strain curve. What does a J-shaped stress stain curve indicate about a material's response to stress and tendency to yield? Name two materials that have J-shaped stress strain curves.
1- A solid axial member which is made from three parts with different materials (sections 1,2, and 3) is loaded and supported as shown in the Figure 1. Segments (1) has a diameter of 30 mm, segment (2) has a diameter of 20 mm and segment (3) has a diameter of 25 mm. For the Elastic modulus of segments please follow the table 1. Surname starting (A-M) Surname starting (N-Z) 1.1 m 1.3 m 0.7 m B. (1) E₁ = 200 GPa E₁ = 100 GPa (2) (3) P₁ = 40 kN P₂ = 10 KN P3 = 20 kN Figure 1 Table 1 E₂ = 100 GPa E₂ = = 80 GPa E3 = 80 GPa E3 = 200 GPa (i) determine the deformation of segment (2). (ii) determine the deflection of joint D with respect to the fixed support at A. (iii) calculate the maximum normal stress in the entire axial member. (iv) What type of changes the design do you suggest to reduce the deflection on joint D calculated in section (ii). Explain your answer.
From the stress-strain data for poly(methyl methacrylate) shown in figure below, determine the modulus of elasticity in the elastic linear region and the tensile strength at 40 °C (104 °F). Stress (MPa) 80 70 60 30 20 10 4°C (40°F) ,20°C (68°F) 30°C (86°F) .40°C (104°F) 0.1 Strain 50°C (122°F) 60°C (140°F) 0.2 To 1.30 The modulus of elasticity is 2.3 GPa and the tensile strength is 49 MPa O The modulus of elasticity is 38 MPa and the tensile strength is 3.3 GPa The modulus of elasticity is 1.2 GPa and the tensile strength is 52 MPa The modulus of elasticity is 1.2 GPa and the tensile strength is 38 MPa T 12 10 8 2 0.3 Stress (10³ psi)
3. A leaf spring in an automobile is subjected to cyclic stresses. The average stress = 150 MPa; variable stress = 500 MPa; ultimate stress = 630 MPa; yield point stress = 350 MPa and endurance limit = 150 MPa. Estimate, under what factor of safety the spring is working, by Goodman and Soderberg formulae. [Ans. 1.75, 1.3]
Example: Convert the change in length data in Table 3-2 to engineering stress and strain and plot a stress-strain curve Homework- help Table 3-2 The results of a tensile test of a 0.505 in. diameter aluminum alloy test bar, initial length (1o) = 2 in. Calculated LTO Load (Ib) Change in Length (in.) Stress (psi) Strain (in./in.) 0.000 1000 0.001 0.0005 4,993 14,978 24,963 34,948 37,445 39,442 39,941 39,691 37,944 3000 0.003 0.0015 5000 0.005 0.0025 7000 0.007 0.0035 7500 0.030 0.0150 7900 0.080 0.0400 8000 (maximum load) 0.120 0.0600 7950 0.160 0.0800 7600 (fracture) 0.205 0.1025
Consider the material Al-$456 It has the following physical ploperties Syleld = 230mPA %3D s-72GPA (modulos elasticity) Oultimate=315 mPA G- 28GPA Cmad vlus rigidity) Tuield =130 mPA Joltimate=185 mPA A Calculate Poisson's ratio B) If we have a following dimensions And Forces 3-0 block of Al-5456 with the Ex =800N X= Bcm Fy=1000N ) Is Our block Safes (consider only plane stes) Dset up the 3 eqetions to find the strains (Ex Ey E2) in each directian E Solve the 3exuations to find the Einal dimensions of our block
3. A cylindrical rod is fixed between two walls. The rod is composed of two materials. Section AC is made of one material (GAC = 2G) while section CD is made of a different material (GcD = G). A torque, T, is applied at point B, as shown below. Jac = JcD = J = 2 in. GẠC = 2G = 20 x 10ʻ psi T= 300 kip in. GCD = G = 10 × 106 psi A D 2L Determine the reactions at the wall, Ta, and Tp. Specify the direction for each. (Note: this is an example of a no calculator problem.) Ans: TA = 250 kip in ( Tp=50 kip in ( T Fixed Fixed to wall to wall
Aluminium alloy AA7475 is applied as a high strength aluminium sheet for aerospace. In preparation for its use a number of tests are carried out on sample sheets including analysis of fracture toughness. A central through-thickness crack is introduced in the sheets. The suppliers of the material quote a fracture toughness of 42 MPa m1/2. Dimensions of the sheet are demonstrated in Figure Q3, where Width W = 50 mm and thickness t = 1 mm. A stress of 447 MPa is applied. Calculate the critical crack half length ac. You may assume a value of Y = 1. Answers should be given in metres (without units) to 2 significant figures Stress intensity K = Υσ πα t W 2a ↓ F F Figure Q3- a plate of width W containing a central through-thickness crack of length 2a
1. A 0.015 meter diameter bar of steel is stress tested and the following stress-strain curve is produced Stress (psix 10 60 50 8 20 10 1 MPa 300 100 psi (x 10%) 50 200-30 OL 40- 20- 10 0.05 0.005 1 L 0.010 0.10 Strain a. What is the ultimate tensile strength (MPa)? d. What is the yield strength(MPa)? 0.15 c. What is the percent plastic elongation at the time of fracture? e. What is the Modulus of Elasticity (GPa)? 400 300 200 Stress (MPa) b. What is the greatest load that can be place on this bar before failure(N)? 100 10 0.20
From the figure shown, Material 1 (brown) is enclosed inside Material 2 (grey). If there would be a load directly applied iscussions on material 2, what should be the minimum inside diameter of material 2, so that there is no contact pressure between the material 1 and material 2? Grades Force P = 357.5 kN People %3D Diameter of Material 1 = 88.75 mm Pages Poisson's Ratio = 0.355 Syllabus Modulus of Elasticity of Mat. 2 88.56 x 10 A9 N/m^2 Quizzes Modules BigBlueButton Collaborations Badges Google Drive Office 365 Chat TLP Manila Librany Video Presentation Canvas LMS Satisfactory Sunvey ILP STUDENTS COVID-19