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- Question Three a) A wire 3m long and 2mm in diameter when stretched by weight of 10kg has its length increased by 0.28mm. Find the stress, strain and Young Modulus of the material of the wire. (g = 9.81m/s²) b) A steel column is 3.5m long and 0.4m diameter. It carries a load of 50MN. Given that the modulus of elasticity is 200GPa, calculate the compressive stress and strain, and determine how much the column is compressed.From the figure shown, Material 1 (brown) is enclosed inside Material 2 (grey). If there would be a load directly applied iscussions on material 2, what should be the minimum inside diameter of material 2, so that there is no contact pressure between the material 1 and material 2? Grades Force P = 357.5 kN People %3D Diameter of Material 1 = 88.75 mm Pages Poisson's Ratio = 0.355 Syllabus Modulus of Elasticity of Mat. 2 88.56 x 10 A9 N/m^2 Quizzes Modules BigBlueButton Collaborations Badges Google Drive Office 365 Chat TLP Manila Librany Video Presentation Canvas LMS Satisfactory Sunvey ILP STUDENTS COVID-193. A cylindrical rod is fixed between two walls. The rod is composed of two materials. Section AC is made of one material (GAC = 2G) while section CD is made of a different material (GcD = G). A torque, T, is applied at point B, as shown below. Jac = JcD = J = 2 in. GẠC = 2G = 20 x 10ʻ psi T= 300 kip in. GCD = G = 10 × 106 psi A D 2L Determine the reactions at the wall, Ta, and Tp. Specify the direction for each. (Note: this is an example of a no calculator problem.) Ans: TA = 250 kip in ( Tp=50 kip in ( T Fixed Fixed to wall to wall
- The stress-strain curve for four materials are shown in figure below. Which material (A/B/C/D) has 1- The least modulus of elasticity C 2- The strongest and stiffest B 3- Most brittle 4- Most ductile 5- Highest yield stress D 6- Lowest Yield stress 7- Highest UTS 8- Lowest UTS Stress Straintol F = Fe F= F + F COs # F F sin a. # tan Example (L):Find the two components of the force (100 X) if: 0 = 30, 120 270° as shown in figure. F = 100 N F = 100 N 6%330 6 =120° 0 =270° 0 = 300 0 60 F = 100 N ution:Question 5 A 120 mm x 100 mm x 20 mm T section short column is used as a simply supported beam. The beam carries the applied eccentric load F of 120 kN at the position indicated in Figure Q5. Start your calculations be setting an origin from the right-most point on the cross-section and determine the following: 100 120 mm 20 mm F 20 mm Figure QS: T- section short column beam 5.1 The maximum compressive and tensile longitudinal direct stresses induced in the column. 5.2 Plot the stress distribution diagram and determine the position of the NA.
- Question 3: a. A mass of (Z + 50) kg is hung on a steel wire of diameter (Z + 5) mm and the extension found is (Z + 10) mm. If the Young's Modulus of the wire is 200 GPa, Calculate, i. the cross-sectional area of the fishing rope ii. the tensile strain b. A copper sheet of (Z + 75) cm width, (Z + 100) cm height, and (Z + 0.5) cm thick is acted by a shearing force of 50 × 10³ N, as shown in figure below. If the shearing Modulus of Copper is 4.2 x 101°N/m², find the followings: i. Shear Stress ii. Linear Displacement (Ax) Z=62 F Ax thick Width heightQ1: 30-mm-diameter steel bar is to be used as a torsion spring. If the torsional stress in the bar is not to exceed 110 MPa when one end is twisted through an angle of 30°, what must be the length of the bar in m? modulus of rigidity=80 GPa . (close to two decimal)Q1: Rigid bar ABCD is loaded and supported as shown in figure below. Bars (1) and (2) are unstressed before the load P is applied. Bar (1) is made of bronze [E = 100 GPa] and has a cross-sectional area of 520 mm2. Bar (2) is made of aluminum [E = 70 GPa] and has a cross-sectional area of 960 mm2. After the load P is applied, the force in bar (2) is found to be 25 kN (in tension). Determine: (1) the stresses in bars (1) and (2). (2) the vertical deflection of point A. (3) the load P. 0.8 m A В 0.4 m 1.1 m I 0.5 m 0.6 m
- One end of a steel rod of radius R = 10mm and length L = 90 cm is held in a vise. A force of magnitude F = 50000 N is then applied perpendicularly to the end face (uniformly across the area) at the other end, pulling directly away from the vise. What will be the elongation of the rod (in the unit meters)? Young modulus is 200 × 109 N/m2)" 7.2 x 10-4 3.4 x 10-4 4.6 x 10-4 2.7 x 10-4The stress- strain curve for four materials are shown in figure below. Which material (A/B/C/D) has 6 SS D 30 7- Highest UTS 8- Lowe UTS 34 Stress O StrainThe rod has a diameter of 40 mm. (Figure 1) It is subjected to the force system F. F, = 920 N. 1350 N, F,= 540 N, Figure 1 of 1 100 mm 300mm B 100 N m