Problem 4: A coal car of mass m]= 3395 kg is rolling down the tracks at a velocity of v¡ = 4.3 m/s when a loader drops coal m2 = 6196 kg into the car. Randomized Variables m = 3395 kg m2 = 6196 kg Vi = 4.3 m/s

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Chapter9: Linear Momentum And Collisions
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Linear Momentum Q4a: please answer, rest of the parts are answered
Problem 4: A coal car of mass m1 = 3395 kg is rolling down the tracks at a velocity of v; = 4.3 m/s when a loader drops a load of
coal m2= 6196 kg into the car.
Randomized Variables
m] = 3395 kg
m2 = 6196 kg
Vi = 4.3 m/s
Part (a) What is the momentum of the system in (kg m)/s before the coal is added?
Numeric : A numeric value is expected and not an expression.
P=
Part (b) What is the velocity after the coal is added in meters per second?
Numeric_: A,numeric value is expected and not an expression.
y= 17.97
Part (c) If you measured the final velocity of the car to be 1 m/s and the initial mass of the car remains the same, how much coal was added to the
car in kg?
Numeric
A numeric value is expected and not an expression.
45
m2' =
Transcribed Image Text:Problem 4: A coal car of mass m1 = 3395 kg is rolling down the tracks at a velocity of v; = 4.3 m/s when a loader drops a load of coal m2= 6196 kg into the car. Randomized Variables m] = 3395 kg m2 = 6196 kg Vi = 4.3 m/s Part (a) What is the momentum of the system in (kg m)/s before the coal is added? Numeric : A numeric value is expected and not an expression. P= Part (b) What is the velocity after the coal is added in meters per second? Numeric_: A,numeric value is expected and not an expression. y= 17.97 Part (c) If you measured the final velocity of the car to be 1 m/s and the initial mass of the car remains the same, how much coal was added to the car in kg? Numeric A numeric value is expected and not an expression. 45 m2' =
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