outputs (0,,00). The function is implemented as the following: IfC = 0, then 0,0, becomes / lg. If C = 1, then 0,0, becomes (lo1)+1. For example, if C = 1 and /l, is 01, 0,0, becomes 10. Note that, if I, Io is 11 and = 1, then the output value wraps around 00, without any overflow. C he Boolean expression for 01 and 00 and in sum of minterms form are: elect one P. None of the above. 0,Σ1,3,5,6) 00 Σ2.3,4,5 ) 03(2,3,5,6) 0, = E(1,3,4,6) 4 0, Σ(1,3,5,6) 0,=Σ(2.3,4,5 ) b. d.

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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A combinational circuit has three inputs (C,,1o) and two
outputs (0, 0). The function is implemented as the following:
If C = 0, then 0,0, becomes I, lg. If C = 1, then 0,0, becomes
(1,1)+1. For example, if C = 1 and I,l, is 01, 0,0, becomes
10. Note that, if 14 1, is 11 and = 1 , then the output value wraps
around 00, without any overflow.
The Boolean expression for 01 and 00 and in sum of minterms form are:
Select one
O . None of the above.
. 0Σ(13,5,6) 0, Σ(2.3,4,5)
ο. 0, Σ(2,3,5,6) 00-Σ(1,3,4,6)
o10,Σ(1,3,5,6) 0,Σ2,3,4,5 )
%3D
d.
Transcribed Image Text:A combinational circuit has three inputs (C,,1o) and two outputs (0, 0). The function is implemented as the following: If C = 0, then 0,0, becomes I, lg. If C = 1, then 0,0, becomes (1,1)+1. For example, if C = 1 and I,l, is 01, 0,0, becomes 10. Note that, if 14 1, is 11 and = 1 , then the output value wraps around 00, without any overflow. The Boolean expression for 01 and 00 and in sum of minterms form are: Select one O . None of the above. . 0Σ(13,5,6) 0, Σ(2.3,4,5) ο. 0, Σ(2,3,5,6) 00-Σ(1,3,4,6) o10,Σ(1,3,5,6) 0,Σ2,3,4,5 ) %3D d.
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