O Kinetics and Equilibrium Calculating equilibrium composition from an equilibrium constant Suppose a 500. mL flask is filled with 0.50 mol of H2 and 2.0 mol of Cl₂. The following reaction becomes possible: H2(g) +Cl₂(g) 2HCl(g) The equilibrium constant K for this reaction is 4.39 at the temperature of the flask. Calculate the equilibrium molarity of HCl. Round your answer to two decimal places. Ом M х S 0/5
O Kinetics and Equilibrium Calculating equilibrium composition from an equilibrium constant Suppose a 500. mL flask is filled with 0.50 mol of H2 and 2.0 mol of Cl₂. The following reaction becomes possible: H2(g) +Cl₂(g) 2HCl(g) The equilibrium constant K for this reaction is 4.39 at the temperature of the flask. Calculate the equilibrium molarity of HCl. Round your answer to two decimal places. Ом M х S 0/5
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 62QRT
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![O Kinetics and Equilibrium
Calculating equilibrium composition from an equilibrium constant
Suppose a 500. mL flask is filled with 0.50 mol of H2 and 2.0 mol of Cl₂. The following reaction becomes possible:
H2(g) +Cl₂(g)
2HCl(g)
The equilibrium constant K for this reaction is 4.39 at the temperature of the flask.
Calculate the equilibrium molarity of HCl. Round your answer to two decimal places.
Ом
M
х
S
0/5](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdfff7cce-2019-43f0-990a-79a2665b3e76%2F8ab47044-0956-486c-9d3f-36f0e2d58469%2Fjgo7f8v_processed.jpeg&w=3840&q=75)
Transcribed Image Text:O Kinetics and Equilibrium
Calculating equilibrium composition from an equilibrium constant
Suppose a 500. mL flask is filled with 0.50 mol of H2 and 2.0 mol of Cl₂. The following reaction becomes possible:
H2(g) +Cl₂(g)
2HCl(g)
The equilibrium constant K for this reaction is 4.39 at the temperature of the flask.
Calculate the equilibrium molarity of HCl. Round your answer to two decimal places.
Ом
M
х
S
0/5
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