In the manufacturing process of a pharmaceutical product, repeated measurements of the concentration of the active ingredient follow a Normal distribution with mean μ equal to the true product concentration, and with standard deviation = 0.008 g/l. How many measurements would be needed to estimate the true concentration within ±0.001 g/l with 99% confidence? Give your answer rounded up to the nearest whole number. n=
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- Unfortunately, arsenic occurs naturally in some ground water.t A mean arsenic level of u = 8.0 parts per billion (ppb) is considered safe for agricultural use. A well in Texas is used to water cotton crops. This well is tested on a regular basis for arsenic. A random sample of 36 tests gave a sample mean of x = 6.7 ppb arsenic, with s = 3.0 ppb. Does this information indicate that the mean level of arsenic in this well is less than 8 ppb? Use a = 0.01. n USE SALT (a) What is the level of significance? State the null and alternate hypotheses. O Ho: H = 8 ppb; H,: u > 8 ppb O Ho: H = 8 ppb; H,: H + 8 ppb O Ho: H 8 ppb; H,: u = 8 ppb O Ho: H = 8 ppb; H,: µ 0.100 O 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.005 < P-value < 0.010 P-value < 0.005 Sketch the sampling distribution and show the area corresponding to the P-value. MacBook Pro escOne company's bottles of grapefruit juice are filled by a machine that is set to dispense an average of 180 milliliters (ml) of liquid. A quality-control inspector must check that the machine is working properly. The inspector takes a random sample of 40 bottles and measures the volume of liquid in each bottle. We want to test Hg: μ = 180 Ha: 180 where μ = the true mean volume of liquid dispensed by the machine. The mean amount of liquid in the bottles is 179.6 ml and the standard deviation is 1.3 ml. A significance test yields a P-value of 0.0589. Interpret the P-value. Assuming the true mean volume of liquid dispensed by the machine is 180 ml, there is a 0.0589 probability of getting a sample mean of 179.6 just by chance in a random sample of 40 bottles filled by the machine. Assuming the true mean volume of liquid dispensed by the machine is 180 ml, there is a 0.0589 probability of getting a sample mean at least as far from 180 as 179.6 (in either direction) just by chance in a…Unfortunately, arsenic occurs naturally in some ground water.t A mean arsenic level of u = 8.0 parts per billion (ppb) is considered safe for agricultural use. A well in Texas is used to water cotton crops. This well is tested on a regular basis for arsenic. A random sample of 36 tests gave a sample mean of x = 7.1 ppb arsenic, with s = 2.2 ppb. Does this information indicate that the mean level of arsenic in this well is less than 8 ppb? Use a = 0.01. A USE SALT (a) What is the level of significance? State the null and alternate hypotheses. O Họ: u = 8 ppb; H,: u > 8 ppb O Ho: H 8 ppb; H,: u = 8 ppb (b) What sampling distribution will you use? Explain the rationale for your choice of sampling distribution. The standard normal, since the sample size is large and a is unknown. O The Student's t, since the sample size is large and a is known. O The standard normal, since the sample size is large and a is known. The Student's t, since the sample size is large and a is unknown. What is the…
- Suppose the lengths of human pregnancies are normally distributed with u = 266 days and 0 = 16 days. The figure to the right represents the normal curve with u = 266 days and 0 = 16 days. The area to the left of X = 245 is 0.0947. Provide two interpretations of this area.Unfortunately, arsenic occurs naturally in some ground water.t A mean arsenic level of u = 8.0 parts per billion (ppb) is considered safe for agricultural use. A well in Texas is used to water cotton crops. This well is tested on a regular basis for arsenic. A random sample of 36 tests gave a sample mean of x = 7.1 ppb arsenic, with s = 2.2 ppb. Does this information indicate that the mean level of arsenic in this well is less than 8 ppb? Use a = 0.01. A USE SALT (a) What is the level of significance? State the null and alternate hypotheses. O Ho: H= 8 ppb; H,: H > 8 ppb O Ho: H 8 ppb; H: H = 8 ppb (b) What sampling distribution will you use? Explain the rationale for your choice of sampling distribution. O The standard normal, since the sample size is large and a is unknown. O The Student's t, since the sample size is large and a is known. O The standard normal, since the sample size is large and a is known. O The Student's t, since the sample size is large and a is unknown. What is…Trace metals in drinking water affect the flavor and an unusually high concentration can pose a health hazard. Ten pairs of data were taken measuring zinc concentration in bottom water and surface water. The raw data provided in table below. Does the data suggest that the true average concentration in the bottom water exceeds that of surface water? Use ?=0.01.
- find the out of control average run length for the control chart for defects when: shifted rate of defects =6.4 UCL = 2.61 LCL = 0.2 REPORT YOUR ANSWER IN 6 DECIMAL PLACES!Sulfur compounds cause "off‑odors" in wine, so winemakers want to know the odor threshold, the lowest concentration of a compound that the human nose can detect. The odor threshold for dimethyl sulfide (DMS) in trained wine tasters is about 25 micrograms per liter of wine (?g/L ). The untrained noses of consumers may be less sensitive, however. The DMS odor thresholds for 10 untrained students are given. 30 30 42 35 22 33 31 29 19 23 (a) Assume that the standard deviation of the odor threshold for untrained noses is known to be ?=7?g/Lσ To access the complete data set, click the link for your preferred software format: Do the three simple conditions hold in this case? Make a stemplot and use it to check the shape of the distribution. (b) STATE: What is the average (mean) DMS odor threshold, ?μ , for all untrained people? PLAN: Using the four‑step process, give a 95%95% confidence interval for the mean DMS odor threshold among all students. SOLVE: We have assumed that we…A population with a mean of μ = 8 has SX = 40.How many scores are in the population?
- An insulating material process produces sheets whose thickness is lognormally distributed with mean, μ = 8.5 inches and standard deviation, σ = 2.0 inches. Please calculate the thickness that 80.0 percent of the products thicknesses are thinner than or equal to.Air samples for worker's exposure to oil mist were found to indicate the following levels in Table 1. Calculate TWA. Table 1 Sample Measured Amount Time of Sample 3 mg/m 28 mg/m Sample 1 2 hours Sample 2 6 hours (a) 6.57 mg/m³ (b) 6.75 mg/m' (c) 54 mg/m (d) 31 mg/mThe compressive strength of concrete is normally distributed with u = 2507 psi and o = 51 psi. A random sample of n = 4 specimens is collected. What is the standard error of the sample mean? Round your final answer to three decimal places (e.g. 12.345). The standard error of the sample mean is psi.