One company's bottles of grapefruit juice are filled by a machine that is set to dispense an average of 180 milliliters (ml) ofliquid. A quality-control inspector must check that the machine is working properly. The inspector takes a random sample of 40bottles and measures the volume of liquid in each bottle.We want to testHg: μ = 180Ha: 180where μ = the true mean volume of liquid dispensed by the machine. The mean amount of liquid in the bottles is 179.6 ml andthe standard deviation is 1.3 ml. A significance test yields a P-value of 0.0589.Interpret the P-value.Assuming the true mean volume of liquid dispensed by the machine is 180 ml, there is a 0.0589 probability of getting asample mean of 179.6 just by chance in a random sample of 40 bottles filled by the machine.Assuming the true mean volume of liquid dispensed by the machine is 180 ml, there is a 0.0589 probability of getting asample mean at least as far from 180 as 179.6 (in either direction) just by chance in a random sample of 40 bottles filledby the machine.The probability that the alternative hypothesis is true is 0.0589.Assuming the true mean volume of liquid dispensed by the machine is 180 ml, there is a 0.0589 probability of getting asample mean no greater than 179.6 just by chance in a random sample of 40 bottles filled by the machine.The probability that the null hypothesis is true is 0.0589.

Given Information: Null Hypothesis H0:μ=180 Alternative Hypothesis Ha:μ≠180 (two-tailed) Sample size…

One company's bottles of grapefruit juice are filled by a machine that is set to dispense an average of 180 milliliters (ml) of liquid. A quality-control inspector must check that the machine is working properly. The inspector takes a random sample bottles and measures the volume of liquid in each bottle. We want to test Ho: μ = 180 Ha: 180 where μ = the true mean volume of liquid dispensed by the machine. The mean amount of liquid in the bottles is 179.6 ml the standard deviation is 1.3 ml. A significance test yields a P-value of 0.0589. Interpret the P-value. Assuming the true mean volume of liquid dispensed by the machine is 180 ml, there is a 0.0589 probability of gettin sample mean of 179.6 just by chance in a random sample of 40 bottles filled by the machine. Assuming the true mean volume of liquid dispensed by the machine is 180 ml, there is a 0.0589 probability of gettin sample mean at least as far from 180 as 179.6 (in either direction) just by chance in a random sample of 40 bottles fil by the machine. The probability that the alternative hypothesis is true is 0.0589. Assuming the true mean volume of liquid dispensed by the machine is 180 ml, there is a 0.0589 probability of gettin sample mean no greater than 179.6 just by chance in a random sample of 40 bottles filled by the machine. habilit 0.0590

12th Edition

ISBN:9781305652231

Author:R. David Gustafson, Jeff Hughes

Publisher:R. David Gustafson, Jeff Hughes

Chapter4: Polynomial And Rational Functions

Section4.6: Rational Functions

Problem 11SC: Find the mean hourly cost when the cell phone described above is used for 240 minutes.