CODE USING C++3. The proposal!by CodeChum AdminThanks to your help again, I found the perfect ring for her. I'm going to propose tomorrow but I'm nervous. I think when I'm going to ask her the famous question, "Will you marry me?", she's going to respond with: "Only if you can determine if there is a vowel in a certain word" Shucks! It's always better to be prepared. Who knows that might indeed happen. I'm going to need your help to create function that'll do this so tomorrow, I will just call this function. Instructions:In the code editor, you are provided a main() function that asks the user for a word. This word is then passed to a function called, hasVowel().Your task is to define the hasVowel() function which has the following detailsReturn type - intName - hasVowelParameter:char* - to hold the character arrayReturn value - 1 if there is at least 1 vowel and 0 if there is none. Be sure to consider both the capital and small letter vowels when checking.Input1. The wordOutputEnter·the·word:·CodeChumThere·is·a·vowel·in·the·word·"CodeChum" main.cpp+C++"Only if you can determine if there is a vowel in a certain word"1 #include Shucks! It's always better to be prepared. Who knows that might indeed2 using namespace std;happen. I'm going to need your help to create function that'll do this so34 int main(void) {char word[100];tomorrow, I will just call this function.67cout <« "Enter the word: ";cin >> word;Instructions:891. In the code editor, you are provided a main() function that asks10int result = hasVowel(word);the user for a word. This word is then passed to a function called,hasVowel().2. Your task is to define the hasVowel() function which has thefollowing details11if(result == 1) {cout <« "There is a vowel in the word \"" << word << "\"":121314} else if(result == 0) {1. Return type - int15cout <« "There is no vowel in the word \"" << word << "\"":16}2. Name - hasvowel173. Parameter:18return 0;1. char* - to hold the character array19 }4. Return value - 1 if there is at least 1 vowel and 0 if there isnone. Be sure to consider both the capital and small lettervowels when checking.Input1. The wordOutputEnter the word: CodechumThere is a vowel in the word "CodeChum"

I have provided C++ CODE along with CODE SCREENSHOT and also provided 2 OUTPUT…

Answered: In the code editor, you are provided a…

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CODE USING C++

3. The proposal!

by CodeChum Admin

Thanks to your help again, I found the perfect ring for her. I'm going to propose tomorrow but I'm nervous. I think when I'm going to ask her the famous question, "Will you marry me?", she's going to respond with:

"Only if you can determine if there is a vowel in a certain word"

Shucks! It's always better to be prepared. Who knows that might indeed happen. I'm going to need your help to create function that'll do this so tomorrow, I will just call this function.

Instructions:

In the code editor, you are provided a main() function that asks the user for a word. This word is then passed to a function called, hasVowel().
Your task is to define the hasVowel() function which has the following details
1. Return type - int
2. Name - hasVowel
3. Parameter:
  1. char* - to hold the character array
4. Return value - 1 if there is at least 1 vowel and 0 if there is none. Be sure to consider both the capital and small letter vowels when checking.

Input

1. The word

Output

Enter·the·word:·CodeChum

There·is·a·vowel·in·the·word·"CodeChum"

main.cpp
+
C++
"Only if you can determine if there is a vowel in a certain word"
1 #include <iostream>
Shucks! It's always better to be prepared. Who knows that might indeed
2 using namespace std;
happen. I'm going to need your help to create function that'll do this so
3
4 int main(void) {
char word[100];
tomorrow, I will just call this function.
6
7
cout <« "Enter the word: ";
cin >> word;
Instructions:
8
9
1. In the code editor, you are provided a main() function that asks
10
int result = hasVowel(word);
the user for a word. This word is then passed to a function called,
hasVowel().
2. Your task is to define the hasVowel() function which has the
following details
11
if(result == 1) {
cout <« "There is a vowel in the word \"" << word << "\"":
12
13
14
} else if(result == 0) {
1. Return type - int
15
cout <« "There is no vowel in the word \"" << word << "\"":
16
}
2. Name - hasvowel
17
3. Parameter:
18
return 0;
1. char* - to hold the character array
19 }
4. Return value - 1 if there is at least 1 vowel and 0 if there is
none. Be sure to consider both the capital and small letter
vowels when checking.
Input
1. The word
Output
Enter the word: Codechum
There is a vowel in the word "CodeChum"

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