In exercising, a weight lifter loses 0.197 kg of water through evaporation, the heat required to evaporate the water coming from the weight lifter's body. The work done in lifting weights is 1.98 x 105 J. (a) Assuming that the latent heat of vaporization of perspiration is 2.42 x 106 J/kg, find the change in the internal energy of the weight lifter. (b) Determine the minimum number of nutritional Calories of food that must be consumed to replace the loss of internal energy. (1 nutritional Calorie = 4186 J). (a) Number Units (b) Number Units

Physics for Scientists and Engineers: Foundations and Connections
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Chapter22: Entropy And The Second Law Of Thermodynamics
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In exercising, a weight lifter loses 0.197 kg of water through evaporation, the heat required to evaporate the water coming from the
weight lifter's body. The work done in lifting weights is 1.98 x 105 J. (a) Assuming that the latent heat of vaporization of perspiration is
2.42x 10° J/kg, find the change in the internal energy of the weight lifter. (b) Determine the minimum number of nutritional Calories of
food that must be consumed to replace the loss of internal energy. (1 nutritional Calorie = 4186 J).
(a) Number
i
Units
(b) Number
Units
Transcribed Image Text:In exercising, a weight lifter loses 0.197 kg of water through evaporation, the heat required to evaporate the water coming from the weight lifter's body. The work done in lifting weights is 1.98 x 105 J. (a) Assuming that the latent heat of vaporization of perspiration is 2.42x 10° J/kg, find the change in the internal energy of the weight lifter. (b) Determine the minimum number of nutritional Calories of food that must be consumed to replace the loss of internal energy. (1 nutritional Calorie = 4186 J). (a) Number i Units (b) Number Units
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